Basically, dsolve is set up for the "usual" situation where you have existence and uniqueness. If you want to deal with one of these pathological situations, you must do some careful analysis. Start with the general solution
> dsolve(diff(x(t),t) = sqrt(x(t)));
Note that this does not include the singular solution x(t) = 0. Maple's solution is defined for t >= - 2 _C1, but can be continued as x(t) = 0 for t < -2 _C1. In particular this gives solutions satisfying x(0)=0 for any _C1 <= 0.
use the theorem to test the
use the theorem to test the ODE ,the solutions are NOT unique
however maple gives me a unique solution?
dsolve and non-unique solutions
Basically, dsolve is set up for the "usual" situation where you have existence and uniqueness. If you want to deal with one of these pathological situations, you must do some careful analysis. Start with the general solution
> dsolve(diff(x(t),t) = sqrt(x(t)));
Note that this does not include the singular solution x(t) = 0. Maple's solution is defined for t >= - 2 _C1, but can be continued as x(t) = 0 for t < -2 _C1. In particular this gives solutions satisfying x(0)=0 for any _C1 <= 0.
i see so basically if i just
i see
so basically if i just ask it to solve with initial condition given
i wont know if the solution is unique or not
thanks
with Axiom
which is free, you can get the other one:
So, you may want to check results.