Integration Issue (Inverse Fourier Transforms)

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Integration Issue (Inverse Fourier Transforms)

Posted on 2008-03-11 15:31 By tsaunder (1)

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Curious about something. In Maple 10 I was able to find the inverse Fourier transform of a product of transforms (a linear filter actually) by definition. For example, Maple 10 would evaluate:

1/sqrt(2*Pi)*int(LF*exp(I*lambda*t),lambda=-infinity..infinity) where LF is was a product of two Fourier transforms.

Maple 11 on the other hand will not evaluate the integral and I am left having to use:

with(inttrans): sqrt(2*Pi)*invfourier(LF,lambda,t);

which I don't find beneficial as a tool for teaching my students. I would rather have them evaluate it by definition. The results are the same. Any suggestions as to why Maple 11 will not evaluate the integral? It just returns the integral as its result.

Thanks in advance for any feedback.

What function?

Comment on 2008-03-11 18:53 from Robert Israel ( Maple Rating 4

1429)

What is the particular LF in this case? Do assumptions such as t::real
make a difference (depending on what LF is, that might be necessary for convergence)?

Indeed

Comment on 2008-03-12 09:27 from JacquesC ( Maple Rating 4

1697)

with a particular LF, we can figure out what is really going on. It might be that, while fixing some bug in Maple 10, this was broken for 11, unbeknownst to the developers. If you can find such an instance, then it is worth reporting that bug (known as a 'regression' bug, which are taken quite seriously).