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  <channel>
    <title>MaplePrimes - answers and comments on Question, Equivalent Maple Command to # in Mathematica</title>
    <link>http://www.mapleprimes.com/questions/122686-Equivalent-Maple-Command-To--In-Mathematica</link>
    <language>en-us</language>
    <copyright>2026 Maplesoft, A Division of Waterloo Maple Inc.</copyright>
    <generator>Maplesoft Document System</generator>
    <lastBuildDate>Fri, 12 Jun 2026 01:16:34 GMT</lastBuildDate>
    <pubDate>Fri, 12 Jun 2026 01:16:34 GMT</pubDate>
    <itunes:subtitle />
    <itunes:summary />
    <description>The latest answers and comments added to the Question, Equivalent Maple Command to # in Mathematica</description>
    <image>
      <url>http://www.mapleprimes.com/images/mapleprimeswhite.jpg</url>
      <title>MaplePrimes - answers and comments on Question, Equivalent Maple Command to # in Mathematica</title>
      <link>http://www.mapleprimes.com/questions/122686-Equivalent-Maple-Command-To--In-Mathematica</link>
    </image>
    <item>
      <title>convert FromMma</title>
      <link>http://www.mapleprimes.com/questions/122686-Equivalent-Maple-Command-To--In-Mathematica?ref=Feed:MaplePrimes:Equivalent Maple Command to # in Mathematica:Comments#answer122688</link>
      <itunes:summary>&lt;p&gt;You could use converter from Mma to Maple,&lt;/p&gt;
&lt;pre&gt;convert("f[#, a, #, b] &amp;amp;[x, y]",FromMma);

                unapply(f(_Z1, a, _Z1, b), _Z1)(x, y)

%;

                            f(x, a, x, b)
&lt;/pre&gt;
&lt;p&gt;Alec&lt;/p&gt;</itunes:summary>
      <description>&lt;p&gt;You could use converter from Mma to Maple,&lt;/p&gt;
&lt;pre&gt;convert("f[#, a, #, b] &amp;amp;[x, y]",FromMma);

                unapply(f(_Z1, a, _Z1, b), _Z1)(x, y)

%;

                            f(x, a, x, b)
&lt;/pre&gt;
&lt;p&gt;Alec&lt;/p&gt;</description>
      <guid>122688</guid>
      <pubDate>Wed, 15 Jun 2011 01:52:13 Z</pubDate>
      <itunes:author>Alec Mihailovs</itunes:author>
      <author>Alec Mihailovs</author>
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