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    <title>MaplePrimes - answers and comments on Question, How to solve this equations?</title>
    <link>http://www.mapleprimes.com/questions/127963-How-To-Solve-This-Equations</link>
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    <pubDate>Tue, 09 Jun 2026 08:33:10 GMT</pubDate>
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    <description>The latest answers and comments added to the Question, How to solve this equations?</description>
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      <title>MaplePrimes - answers and comments on Question, How to solve this equations?</title>
      <link>http://www.mapleprimes.com/questions/127963-How-To-Solve-This-Equations</link>
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    <item>
      <title>Missing multiplication signs?</title>
      <link>http://www.mapleprimes.com/questions/127963-How-To-Solve-This-Equations?ref=Feed:MaplePrimes:How to solve this equations?:Comments#answer127981</link>
      <itunes:summary>&lt;p&gt;In the posted text several multiplication signs were missing.&lt;/p&gt;
&lt;p&gt;eqns := {(x[1]+1)^2+y[1]^2 = (x[2]-1)^2+y[2]^2, (x[1]-c[1])^2+(y[1]-c[2])^2 = (x[3]-1)^2+y[3]^2, (x[2]-c[1])^2+(y[2]-c[2])^2 = (x[3]+1)^2+y[3]^2, y[1]*(x[3]+1) = y[3]*(x[1]+1), y[2]*(x[3]-1) = y[3]*(x[2]-1), (x[2]-c[1])*(y[1]-c[2]) = (x[1]-c[1])*(y[2]-c[2])};&lt;br&gt;vars := {x[1], x[2], x[3], y[1], y[2], y[3]};&lt;br&gt;#With my limited patience I didn't wait for a possible answer from 'solve', but proceeded to 'fsolve', which of course expects c[1] and c[2] to be of type numeric.&lt;br&gt;solve(eqns, vars);&lt;br&gt;fsolve(eval(eqns,{c[1]=1.234,c[2]=2.345}), vars);&lt;br&gt;&lt;br&gt;&lt;/p&gt;</itunes:summary>
      <description>&lt;p&gt;In the posted text several multiplication signs were missing.&lt;/p&gt;
&lt;p&gt;eqns := {(x[1]+1)^2+y[1]^2 = (x[2]-1)^2+y[2]^2, (x[1]-c[1])^2+(y[1]-c[2])^2 = (x[3]-1)^2+y[3]^2, (x[2]-c[1])^2+(y[2]-c[2])^2 = (x[3]+1)^2+y[3]^2, y[1]*(x[3]+1) = y[3]*(x[1]+1), y[2]*(x[3]-1) = y[3]*(x[2]-1), (x[2]-c[1])*(y[1]-c[2]) = (x[1]-c[1])*(y[2]-c[2])};&lt;br&gt;vars := {x[1], x[2], x[3], y[1], y[2], y[3]};&lt;br&gt;#With my limited patience I didn't wait for a possible answer from 'solve', but proceeded to 'fsolve', which of course expects c[1] and c[2] to be of type numeric.&lt;br&gt;solve(eqns, vars);&lt;br&gt;fsolve(eval(eqns,{c[1]=1.234,c[2]=2.345}), vars);&lt;br&gt;&lt;br&gt;&lt;/p&gt;</description>
      <guid>127981</guid>
      <pubDate>Tue, 22 Nov 2011 20:22:16 Z</pubDate>
      <itunes:author>Preben Alsholm</itunes:author>
      <author>Preben Alsholm</author>
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    <item>
      <title>Symbolic solution</title>
      <link>http://www.mapleprimes.com/questions/127963-How-To-Solve-This-Equations?ref=Feed:MaplePrimes:How to solve this equations?:Comments#answer128114</link>
      <itunes:summary>&lt;p&gt;At least one symbolic solution of eqns union vars can be found:&lt;br&gt;&amp;gt;SolveTools[PolynomialSystem]({y[1]*(x[3]+1) = y[3]*(x[1]+1), y[2]*(x[3]-1) = y[3]*(x[2]-1),&lt;br&gt;&amp;nbsp;(x[2]-c[1])*(y[1]-c[2]) = (x[1]-c[1])*(y[2]-c[2]), (x[1]+1)^2+y[1]^2 = (x[2]-1)^2+y[2]^2, &lt;br&gt;(x[1]-c[1])^2+(y[1]-c[2])^2 = (x[3]-1)^2+y[3]^2, (x[2]-c[1])^2+(y[2]-c[2])^2 = (x[3]+1)^2+y[3]^2},&lt;br&gt;&amp;nbsp;{x[1], x[2], x[3], y[1], y[2], y[3]})&lt;br&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; &lt;br&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; { x[1] = 0, x[2] = 0, x[3] = 0, y[1] =(-1+c[1]^2+c[2]^2)/(2 c[2]), &lt;br&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; &lt;br&gt;y[2]=(-1+c[1]^2+c[2]^2)/(2 c[2]), y[3]=(-1+c[1]^2+c[2]^2)/(2 c[2])}&lt;/p&gt;</itunes:summary>
      <description>&lt;p&gt;At least one symbolic solution of eqns union vars can be found:&lt;br&gt;&amp;gt;SolveTools[PolynomialSystem]({y[1]*(x[3]+1) = y[3]*(x[1]+1), y[2]*(x[3]-1) = y[3]*(x[2]-1),&lt;br&gt;&amp;nbsp;(x[2]-c[1])*(y[1]-c[2]) = (x[1]-c[1])*(y[2]-c[2]), (x[1]+1)^2+y[1]^2 = (x[2]-1)^2+y[2]^2, &lt;br&gt;(x[1]-c[1])^2+(y[1]-c[2])^2 = (x[3]-1)^2+y[3]^2, (x[2]-c[1])^2+(y[2]-c[2])^2 = (x[3]+1)^2+y[3]^2},&lt;br&gt;&amp;nbsp;{x[1], x[2], x[3], y[1], y[2], y[3]})&lt;br&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; &lt;br&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; { x[1] = 0, x[2] = 0, x[3] = 0, y[1] =(-1+c[1]^2+c[2]^2)/(2 c[2]), &lt;br&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; &lt;br&gt;y[2]=(-1+c[1]^2+c[2]^2)/(2 c[2]), y[3]=(-1+c[1]^2+c[2]^2)/(2 c[2])}&lt;/p&gt;</description>
      <guid>128114</guid>
      <pubDate>Sat, 26 Nov 2011 00:38:13 Z</pubDate>
      <itunes:author>Markiyan Hirnyk</itunes:author>
      <author>Markiyan Hirnyk</author>
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