Symbolic inverse

Robert Israel — Fri, 25 Nov 2011 01:13:10 Z

Maple can calculate the inverse of a Matrix A as A^(-1). If you do want the adjoint, that is Adjoint(A) (in the LinearAlgebra package). You shouldn't have to worry about pivot elements. What you do have to worry about, however, is that the inverse of a 6 x 6 symbolic matrix will be horrendously complicated. In general (if there is no special simplification) each entry will be a fraction whose denominator is Determinant(A), which is the sum of 6! = 720 terms, each being the product of 6 entries of A. For example, the inverse of

has a length, as reported by the length command, of 2246858. If the matrix entries are more complicated, the length will increase even more. Further computations with such a monster are likely to be very difficult. You should ask yourself whether you really need an explicit expression for A^-1. What do you intend to do with it? Could you reformulate things so that an explicit inverse is not needed?

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Symbolic inverse