subs

Preben Alsholm — Tue, 27 Dec 2011 20:33:35 Z

'eval' and 'subs' both need equations as in subs(a=7,expr);

Thus after having defined eq3 you can do

res:=solve({eq1, eq2, eq3}, {a, b, c});
subs(res,Te);

#Since you are evaluating Te and its derivative a few times you may find it easier to define Te as a function of y ( a procedure) and then do as follows.

restart;
Te := y->a+b*y+c*y^2;

eq1 := Te(delta[t]) = T[inf];

eq2 := D(Te)(delta[t]) = 0;

Eq3 := Te(0) = T[w]+2*(2-sigma[t])*gamma*Kn*H*D(Te)(0)/(sigma[t]*(gamma+1)*Pr);

eq3 := factor(simplify(Eq3, {2*(2-sigma[t])*gamma*Kn/(sigma[t]*(gamma+1)*Pr) = B}));

res:=solve({eq1, eq2, eq3}, {a, b, c});
subs(res,Te(y));

subs

samantasubho — Tue, 27 Dec 2011 22:04:17 Z

It worked. Thank you for your kind reply.

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subs

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