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    <title>MaplePrimes - answers and comments on Question, How do I solve the following system of differential equations in Maple?</title>
    <link>http://www.mapleprimes.com/questions/129724-How-Do-I-Solve-The-Following-System</link>
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    <description>The latest answers and comments added to the Question, How do I solve the following system of differential equations in Maple?</description>
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      <title>MaplePrimes - answers and comments on Question, How do I solve the following system of differential equations in Maple?</title>
      <link>http://www.mapleprimes.com/questions/129724-How-Do-I-Solve-The-Following-System</link>
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      <title>Answer</title>
      <link>http://www.mapleprimes.com/questions/129724-How-Do-I-Solve-The-Following-System?ref=Feed:MaplePrimes:How do I solve the following system of differential equations in Maple?:Comments#answer129729</link>
      <itunes:summary>&lt;p&gt;&lt;span class="hps"&gt;Such non-linear&lt;/span&gt; &lt;span class="hps"&gt;systems &lt;/span&gt;are &lt;span class="hps"&gt;usually solved&lt;/span&gt; &lt;span class="hps"&gt;numerically&lt;/span&gt; &lt;span class="hps"&gt;for given values&lt;/span&gt; &lt;span class="hps"&gt;​​of all parameters&lt;/span&gt;&lt;span&gt;!&lt;/span&gt; &lt;span class="hps"&gt;Note that&lt;/span&gt;&amp;nbsp;&lt;span class="hps"&gt;parameter m on&lt;/span&gt;&amp;nbsp;&lt;span class="hps"&gt;the right side of&lt;/span&gt; &lt;span class="hps"&gt;the first equation&lt;/span&gt; &lt;span class="hps"&gt;must be equal to&lt;/span&gt; &lt;span class="hps"&gt;0, otherwise&lt;/span&gt; &lt;span class="hps"&gt;it&lt;/span&gt; &lt;span class="hps"&gt;would be contrary to&lt;/span&gt; &lt;span class="hps"&gt;the initial conditions.&lt;/span&gt;&lt;/p&gt;</itunes:summary>
      <description>&lt;p&gt;&lt;span class="hps"&gt;Such non-linear&lt;/span&gt; &lt;span class="hps"&gt;systems &lt;/span&gt;are &lt;span class="hps"&gt;usually solved&lt;/span&gt; &lt;span class="hps"&gt;numerically&lt;/span&gt; &lt;span class="hps"&gt;for given values&lt;/span&gt; &lt;span class="hps"&gt;​​of all parameters&lt;/span&gt;&lt;span&gt;!&lt;/span&gt; &lt;span class="hps"&gt;Note that&lt;/span&gt;&amp;nbsp;&lt;span class="hps"&gt;parameter m on&lt;/span&gt;&amp;nbsp;&lt;span class="hps"&gt;the right side of&lt;/span&gt; &lt;span class="hps"&gt;the first equation&lt;/span&gt; &lt;span class="hps"&gt;must be equal to&lt;/span&gt; &lt;span class="hps"&gt;0, otherwise&lt;/span&gt; &lt;span class="hps"&gt;it&lt;/span&gt; &lt;span class="hps"&gt;would be contrary to&lt;/span&gt; &lt;span class="hps"&gt;the initial conditions.&lt;/span&gt;&lt;/p&gt;</description>
      <guid>129729</guid>
      <pubDate>Tue, 17 Jan 2012 23:44:16 Z</pubDate>
      <itunes:author>Kitonum</itunes:author>
      <author>Kitonum</author>
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      <title>m=0</title>
      <link>http://www.mapleprimes.com/questions/129724-How-Do-I-Solve-The-Following-System?ref=Feed:MaplePrimes:How do I solve the following system of differential equations in Maple?:Comments#comment129767</link>
      <itunes:summary>&lt;p&gt;Indeed the condition m=0 is the problem here: Maple is correctly telling us that there is, in general, no solution to that combination of equations. If we substitute &lt;em&gt;m&lt;/em&gt; = 0 in both equations, then we get the solution &lt;em&gt;x&lt;/em&gt;(&lt;em&gt;t&lt;/em&gt;) = &lt;em&gt;y&lt;/em&gt;2(&lt;em&gt;t&lt;/em&gt;) = 0 for all &lt;em&gt;t&lt;/em&gt;. Otherwise, if we leave &lt;em&gt;m&lt;/em&gt; symbolic as is, we can get a solution if we leave the initial condition &lt;em&gt;x&lt;/em&gt;(0) = 0 out; it's kind of complicated so I won't include it here. Leaving out the condition &lt;em&gt;y&lt;/em&gt;2(0) = 0 still leaves an inconsistent system.&lt;/p&gt;
&lt;p&gt;Hope this helps,&lt;/p&gt;
&lt;p&gt;Erik Postma&lt;br&gt;Maplesoft.&lt;/p&gt;</itunes:summary>
      <description>&lt;p&gt;Indeed the condition m=0 is the problem here: Maple is correctly telling us that there is, in general, no solution to that combination of equations. If we substitute &lt;em&gt;m&lt;/em&gt; = 0 in both equations, then we get the solution &lt;em&gt;x&lt;/em&gt;(&lt;em&gt;t&lt;/em&gt;) = &lt;em&gt;y&lt;/em&gt;2(&lt;em&gt;t&lt;/em&gt;) = 0 for all &lt;em&gt;t&lt;/em&gt;. Otherwise, if we leave &lt;em&gt;m&lt;/em&gt; symbolic as is, we can get a solution if we leave the initial condition &lt;em&gt;x&lt;/em&gt;(0) = 0 out; it's kind of complicated so I won't include it here. Leaving out the condition &lt;em&gt;y&lt;/em&gt;2(0) = 0 still leaves an inconsistent system.&lt;/p&gt;
&lt;p&gt;Hope this helps,&lt;/p&gt;
&lt;p&gt;Erik Postma&lt;br&gt;Maplesoft.&lt;/p&gt;</description>
      <guid>129767</guid>
      <pubDate>Wed, 18 Jan 2012 21:27:35 Z</pubDate>
      <itunes:author>epostma</itunes:author>
      <author>epostma</author>
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