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    <title>MaplePrimes - answers and comments on Question, How to transform equations</title>
    <link>http://www.mapleprimes.com/questions/140387-How-To-Transform-Equations</link>
    <language>en-us</language>
    <copyright>2026 Maplesoft, A Division of Waterloo Maple Inc.</copyright>
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    <lastBuildDate>Tue, 09 Jun 2026 12:04:16 GMT</lastBuildDate>
    <pubDate>Tue, 09 Jun 2026 12:04:16 GMT</pubDate>
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    <itunes:summary />
    <description>The latest answers and comments added to the Question, How to transform equations</description>
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      <title>MaplePrimes - answers and comments on Question, How to transform equations</title>
      <link>http://www.mapleprimes.com/questions/140387-How-To-Transform-Equations</link>
    </image>
    <item>
      <title>one way</title>
      <link>http://www.mapleprimes.com/questions/140387-How-To-Transform-Equations?ref=Feed:MaplePrimes:How to transform equations:Comments#answer140391</link>
      <itunes:summary>&lt;pre&gt;eq:=A*x^beta=R-A*beta/(x^(1-beta)*(1-t));

                  beta             A beta       
               A x     = R - -------------------
                              (1 - beta)        
                             x           (1 - t)

map(z-&amp;gt;1/((1-t)*z), R-eq);

                                        (1 - beta)
                        1              x          
              ---------------------- = -----------
                      /    beta    \     A beta   
              (1 - t) \-A x     + R/              
&lt;/pre&gt;
&lt;!--break--&gt;
&lt;p&gt;One minor variation on that is,&lt;/p&gt;
&lt;pre&gt;map( z-&amp;gt;1/z, (R-eq)*(1-t) );
&lt;/pre&gt;
&lt;p&gt;acer&lt;/p&gt;</itunes:summary>
      <description>&lt;pre&gt;eq:=A*x^beta=R-A*beta/(x^(1-beta)*(1-t));

                  beta             A beta       
               A x     = R - -------------------
                              (1 - beta)        
                             x           (1 - t)

map(z-&amp;gt;1/((1-t)*z), R-eq);

                                        (1 - beta)
                        1              x          
              ---------------------- = -----------
                      /    beta    \     A beta   
              (1 - t) \-A x     + R/              
&lt;/pre&gt;
&lt;!--break--&gt;
&lt;p&gt;One minor variation on that is,&lt;/p&gt;
&lt;pre&gt;map( z-&amp;gt;1/z, (R-eq)*(1-t) );
&lt;/pre&gt;
&lt;p&gt;acer&lt;/p&gt;</description>
      <guid>140391</guid>
      <pubDate>Thu, 15 Nov 2012 19:39:35 Z</pubDate>
      <itunes:author>acer</itunes:author>
      <author>acer</author>
    </item>
    <item>
      <title>Thanks, ... and I have another one</title>
      <link>http://www.mapleprimes.com/questions/140387-How-To-Transform-Equations?ref=Feed:MaplePrimes:How to transform equations:Comments#comment140435</link>
      <itunes:summary>&lt;p&gt;Thank you, acer. I guess I learned something about map. :-)&lt;/p&gt;
&lt;p&gt;But with this one I only found a complicate solution:&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;img class="math" src="http://www.mapleprimes.com/MapleImage.ashx?f=7364463ecec6cf1c45ce98331ebe684b.gif" alt="U = x+(R-y)^(1-Theta)/(1-Theta)"&gt;&lt;/p&gt;
&lt;p&gt;lhs((%)) = op(1, op(2, (%)))+ln(-numer(op(2, op(2, (%)))))/(-denom(op(2, op(2, (%))))) assuming R &amp;gt; y&lt;/p&gt;
&lt;p&gt;&lt;img class="math" src="http://www.mapleprimes.com/MapleImage.ashx?f=bbe7f9cd7a9160d83ceba0e83a040429.gif" alt="`assuming`([lhs(U = x+(R-y)^(1-Theta)/(1-Theta)) = op(1, op(2, U = x+(R-y)^(1-Theta)/(1-Theta)))+ln(-numer(op(2, op(2, U = x+(R-y)^(1-Theta)/(1-Theta)))))/(-denom(op(2, op(2, U = x+(R-y)^(1-Theta)/(1-Theta)))))], [R &amp;gt; y])"&gt;&lt;/p&gt;
&lt;p&gt;simplify((%), ln) assuming (R-y) &amp;gt; 0, Theta &amp;gt; 0&lt;/p&gt;
&lt;p&gt;&lt;img class="math" src="http://www.mapleprimes.com/MapleImage.ashx?f=44a2539917f47221170b25c4334a3a26.gif" alt="U = x+ln(R-y)"&gt;&lt;/p&gt;
&lt;p&gt;So, the result is nice, but my first transormation is quite complicated. In addition, I have to put a - at the numerator and the denominator, that it works. Because Maple changes the sign ahead of the fraction, for whatever reason.&lt;/p&gt;
&lt;p&gt;I guess, there is an easier way.&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;</itunes:summary>
      <description>&lt;p&gt;Thank you, acer. I guess I learned something about map. :-)&lt;/p&gt;
&lt;p&gt;But with this one I only found a complicate solution:&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;img class="math" src="http://www.mapleprimes.com/MapleImage.ashx?f=7364463ecec6cf1c45ce98331ebe684b.gif" alt="U = x+(R-y)^(1-Theta)/(1-Theta)"&gt;&lt;/p&gt;
&lt;p&gt;lhs((%)) = op(1, op(2, (%)))+ln(-numer(op(2, op(2, (%)))))/(-denom(op(2, op(2, (%))))) assuming R &amp;gt; y&lt;/p&gt;
&lt;p&gt;&lt;img class="math" src="http://www.mapleprimes.com/MapleImage.ashx?f=bbe7f9cd7a9160d83ceba0e83a040429.gif" alt="`assuming`([lhs(U = x+(R-y)^(1-Theta)/(1-Theta)) = op(1, op(2, U = x+(R-y)^(1-Theta)/(1-Theta)))+ln(-numer(op(2, op(2, U = x+(R-y)^(1-Theta)/(1-Theta)))))/(-denom(op(2, op(2, U = x+(R-y)^(1-Theta)/(1-Theta)))))], [R &amp;gt; y])"&gt;&lt;/p&gt;
&lt;p&gt;simplify((%), ln) assuming (R-y) &amp;gt; 0, Theta &amp;gt; 0&lt;/p&gt;
&lt;p&gt;&lt;img class="math" src="http://www.mapleprimes.com/MapleImage.ashx?f=44a2539917f47221170b25c4334a3a26.gif" alt="U = x+ln(R-y)"&gt;&lt;/p&gt;
&lt;p&gt;So, the result is nice, but my first transormation is quite complicated. In addition, I have to put a - at the numerator and the denominator, that it works. Because Maple changes the sign ahead of the fraction, for whatever reason.&lt;/p&gt;
&lt;p&gt;I guess, there is an easier way.&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;</description>
      <guid>140435</guid>
      <pubDate>Fri, 16 Nov 2012 18:59:41 Z</pubDate>
      <itunes:author>awehring</itunes:author>
      <author>awehring</author>
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