http://www.mapleprimes.com/questions/140659-Equivalent-Algebraic-Substitution en-us 2026 Maplesoft, A Division of Waterloo Maple Inc. Maplesoft Document System Wed, 10 Jun 2026 21:24:55 GMT Wed, 10 Jun 2026 21:24:55 GMT The latest answers and comments added to the Question, equivalent algebraic substitution http://www.mapleprimes.com/images/mapleprimeswhite.jpg http://www.mapleprimes.com/questions/140659-Equivalent-Algebraic-Substitution http://www.mapleprimes.com/questions/140659-Equivalent-Algebraic-Substitution?ref=Feed:MaplePrimes:equivalent algebraic substitution:Comments#answer140661 <p>restart;<br>m:=Matrix(2, 2, {(1, 1) = phi*(w1*exp(mu)/(exp(mu)+1)+(1-w1)*exp(mu+eta[2])/(exp(mu+eta[2])+1)), (1, 2) = phi^2*(w1*exp(mu+tau[3])/(exp(mu+tau[3])+1)+(1-w1)*exp(mu+tau[3]+eta[2])/(exp(mu+tau[3]+eta[2])+1))*(1-w1*exp(mu)/(exp(mu)+1)-(1-w1)*exp(mu+eta[2])/(exp(mu+eta[2])+1)), (2, 1) = 0, (2, 2) = phi*(w1*exp(mu+tau[3])/(exp(mu+tau[3])+1)+(1-w1)*exp(mu+tau[3]+eta[2])/(exp(mu+tau[3]+eta[2])+1))});<br>expand~(m);<br>subs(exp(mu)=1/s1,exp(tau[3])=1/s2,exp(eta[2])=1/s3,phi=s5,w1=s6,%);<br>simplify(%);<br><br></p> <p>restart;<br>m:=Matrix(2, 2, {(1, 1) = phi*(w1*exp(mu)/(exp(mu)+1)+(1-w1)*exp(mu+eta[2])/(exp(mu+eta[2])+1)), (1, 2) = phi^2*(w1*exp(mu+tau[3])/(exp(mu+tau[3])+1)+(1-w1)*exp(mu+tau[3]+eta[2])/(exp(mu+tau[3]+eta[2])+1))*(1-w1*exp(mu)/(exp(mu)+1)-(1-w1)*exp(mu+eta[2])/(exp(mu+eta[2])+1)), (2, 1) = 0, (2, 2) = phi*(w1*exp(mu+tau[3])/(exp(mu+tau[3])+1)+(1-w1)*exp(mu+tau[3]+eta[2])/(exp(mu+tau[3]+eta[2])+1))});<br>expand~(m);<br>subs(exp(mu)=1/s1,exp(tau[3])=1/s2,exp(eta[2])=1/s3,phi=s5,w1=s6,%);<br>simplify(%);<br><br></p> 140661 Wed, 21 Nov 2012 21:37:57 Z Preben Alsholm Preben Alsholm