Question: Why are polynomials including constants not factorized?

March 22 2014 ErikP 70
Maple 16
2

Hello,

I have trouble in using the function factors. For example, I expect

factor(Pi*(t^2+1), {I});

to output

-Pi*(-t+I)*(t+I)

but instead the result is

Pi*(t^2+1)

This problem does not appear if Pi gets replaced by a general symbol:

factor(pi*(t^2+1), {I});

produces (as I expect it should)

-pi*(-t+I)*(t+I)

The problem seems to be tied to symbols representing constants, as for example replacing Pi by Catalan also results in no factorization being performed. It further seems to be tied to specifying a splitting field, because

factor(Pi*(t^2-1));

results in

Pi*(t-1)*(t+1)

Is this behaviour intended? Probably the reason is that the polynomial does not have algebraic coefficients (as it includes Pi). Indeed,

factor(Pi*(t^2-1),{});

produces the error message

Error, (in factor) expecting a polynomial over an algebraic number field

But why does this error then not appear for the call factor(Pi*(t^2-1))? If this would assume complex coefficients, it should factor using I. Considering coefficients in an algebraic number field, also the original call factor(Pi*(t^2+1), {I}); should raise an error!?

Thanks,

Erik

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