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    <title>MaplePrimes - answers and comments on Question, How to solve an integration with unknown constants inside of it ???</title>
    <link>http://www.mapleprimes.com/questions/35507-How-To-Solve-An-Integration-With-Unknown</link>
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    <lastBuildDate>Wed, 10 Jun 2026 22:18:16 GMT</lastBuildDate>
    <pubDate>Wed, 10 Jun 2026 22:18:16 GMT</pubDate>
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    <itunes:summary />
    <description>The latest answers and comments added to the Question, How to solve an integration with unknown constants inside of it ???</description>
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      <url>http://www.mapleprimes.com/images/mapleprimeswhite.jpg</url>
      <title>MaplePrimes - answers and comments on Question, How to solve an integration with unknown constants inside of it ???</title>
      <link>http://www.mapleprimes.com/questions/35507-How-To-Solve-An-Integration-With-Unknown</link>
    </image>
    <item>
      <title>No closed form solution</title>
      <link>http://www.mapleprimes.com/questions/35507-How-To-Solve-An-Integration-With-Unknown?ref=Feed:MaplePrimes:How to solve an integration with unknown constants inside of it ???:Comments#answer44119</link>
      <itunes:summary>&lt;p&gt;It is very likely that the antiderivative can't be expressed in &amp;quot;closed form&amp;quot;, and there doesn't appear to be anything special about the endpoint 0.2 that might lead one to think that special techniques (such as residues) could be applied to the definite integral.&amp;nbsp; Perhaps you could use power-series solutions, e.g. (with J your integral)&lt;/p&gt;
&lt;pre&gt;
&amp;gt; sort(mtaylor(J, [a,b,c,d]), [a,b,c,d], ascending);

&lt;/pre&gt;
&lt;p&gt;&lt;maple&gt;.2000000000+.1000000000*d^2+.4000000000e-1*c*d+.5333333333e-2*c^2+.8000000000e-2*b*d+.2400000000e-2*b*c+.2880000000e-3*b^2+.1600000000e-2*a*d+.5120000000e-3*a*c+.1280000000e-3*a*b+.1462857143e-4*a^2-.2500000000e-1*d^4-.2000000000e-1*c*d^3-.7999999999e-2*c^2*d^2-.1600000000e-2*c^3*d-.1280000000e-3*c^4-.4000000000e-2*b*d^3-.3600000000e-2*b*c*d^2-.1152000000e-2*b*c^2*d-.1280000000e-3*b*c^3-.4320000000e-3*b^2*d^2-.2880000000e-3*b^2*c*d-.4937142857e-4*b^2*c^2-.2468571428e-4*b^3*d-.8640000000e-5*b^3*c-.5759999999e-6*b^4-.8000000000e-3*a*d^3-.7680000000e-3*a*c*d^2-.2560000001e-3*a*c^2*d-.2925714286e-4*a*c^3-.1920000000e-3*a*b*d^2-.1316571428e-3*a*b*c*d-.2304000000e-4*a*b*c^2-.1728000000e-4*a*b^2*d-.6144000000e-5*a*b^2*c-.5529600000e-6*a*b^3-.2194285714e-4*a^2*d^2-.1536000000e-4*a^2*c*d-.2730666666e-5*a^2*c^2-.4096000001e-5*a^2*b*d-.1474560000e-5*a^2*b*c-.2010763636e-6*a^2*b^2-.3276800000e-6*a^3*d-.1191563636e-6*a^3*c-.3276800000e-7*a^3*b-.2016492308e-8*a^4&lt;/maple&gt;&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;Hmm, interesting: the &amp;lt;maple&amp;gt; tag doesn't preserve the order of terms in the sum.&amp;nbsp; That should have been&lt;/p&gt;
&lt;p&gt;.2000000000+.1000000000*d^2+.4000000000e-1*c*d+.5333333333e-2*c^2+.8000000000e-2*b*d+.2400000000e-2*b*c+.2880000000e-3*b^2+.1600000000e-2*a*d+.5120000000e-3*a*c+.1280000000e-3*a*b+.1462857143e-4*a^2-.2500000000e-1*d^4-.2000000000e-1*c*d^3-.7999999999e-2*c^2*d^2-.1600000000e-2*c^3*d-.1280000000e-3*c^4-.4000000000e-2*b*d^3-.3600000000e-2*b*c*d^2-.1152000000e-2*b*c^2*d-.1280000000e-3*b*c^3-.4320000000e-3*b^2*d^2-.2880000000e-3*b^2*c*d-.4937142857e-4*b^2*c^2-.2468571428e-4*b^3*d-.8640000000e-5*b^3*c-.5759999999e-6*b^4-.8000000000e-3*a*d^3-.7680000000e-3*a*c*d^2-.2560000001e-3*a*c^2*d-.2925714286e-4*a*c^3-.1920000000e-3*a*b*d^2-.1316571428e-3*a*b*c*d-.2304000000e-4*a*b*c^2-.1728000000e-4*a*b^2*d-.6144000000e-5*a*b^2*c-.5529600000e-6*a*b^3-.2194285714e-4*a^2*d^2-.1536000000e-4*a^2*c*d-.2730666666e-5*a^2*c^2-.4096000001e-5*a^2*b*d-.1474560000e-5*a^2*b*c-.2010763636e-6*a^2*b^2-.3276800000e-6*a^3*d-.1191563636e-6*a^3*c-.3276800000e-7*a^3*b-.2016492308e-8*a^4&lt;/p&gt;</itunes:summary>
      <description>&lt;p&gt;It is very likely that the antiderivative can't be expressed in &amp;quot;closed form&amp;quot;, and there doesn't appear to be anything special about the endpoint 0.2 that might lead one to think that special techniques (such as residues) could be applied to the definite integral.&amp;nbsp; Perhaps you could use power-series solutions, e.g. (with J your integral)&lt;/p&gt;
&lt;pre&gt;
&amp;gt; sort(mtaylor(J, [a,b,c,d]), [a,b,c,d], ascending);

&lt;/pre&gt;
&lt;p&gt;&lt;maple&gt;.2000000000+.1000000000*d^2+.4000000000e-1*c*d+.5333333333e-2*c^2+.8000000000e-2*b*d+.2400000000e-2*b*c+.2880000000e-3*b^2+.1600000000e-2*a*d+.5120000000e-3*a*c+.1280000000e-3*a*b+.1462857143e-4*a^2-.2500000000e-1*d^4-.2000000000e-1*c*d^3-.7999999999e-2*c^2*d^2-.1600000000e-2*c^3*d-.1280000000e-3*c^4-.4000000000e-2*b*d^3-.3600000000e-2*b*c*d^2-.1152000000e-2*b*c^2*d-.1280000000e-3*b*c^3-.4320000000e-3*b^2*d^2-.2880000000e-3*b^2*c*d-.4937142857e-4*b^2*c^2-.2468571428e-4*b^3*d-.8640000000e-5*b^3*c-.5759999999e-6*b^4-.8000000000e-3*a*d^3-.7680000000e-3*a*c*d^2-.2560000001e-3*a*c^2*d-.2925714286e-4*a*c^3-.1920000000e-3*a*b*d^2-.1316571428e-3*a*b*c*d-.2304000000e-4*a*b*c^2-.1728000000e-4*a*b^2*d-.6144000000e-5*a*b^2*c-.5529600000e-6*a*b^3-.2194285714e-4*a^2*d^2-.1536000000e-4*a^2*c*d-.2730666666e-5*a^2*c^2-.4096000001e-5*a^2*b*d-.1474560000e-5*a^2*b*c-.2010763636e-6*a^2*b^2-.3276800000e-6*a^3*d-.1191563636e-6*a^3*c-.3276800000e-7*a^3*b-.2016492308e-8*a^4&lt;/maple&gt;&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;Hmm, interesting: the &amp;lt;maple&amp;gt; tag doesn't preserve the order of terms in the sum.&amp;nbsp; That should have been&lt;/p&gt;
&lt;p&gt;.2000000000+.1000000000*d^2+.4000000000e-1*c*d+.5333333333e-2*c^2+.8000000000e-2*b*d+.2400000000e-2*b*c+.2880000000e-3*b^2+.1600000000e-2*a*d+.5120000000e-3*a*c+.1280000000e-3*a*b+.1462857143e-4*a^2-.2500000000e-1*d^4-.2000000000e-1*c*d^3-.7999999999e-2*c^2*d^2-.1600000000e-2*c^3*d-.1280000000e-3*c^4-.4000000000e-2*b*d^3-.3600000000e-2*b*c*d^2-.1152000000e-2*b*c^2*d-.1280000000e-3*b*c^3-.4320000000e-3*b^2*d^2-.2880000000e-3*b^2*c*d-.4937142857e-4*b^2*c^2-.2468571428e-4*b^3*d-.8640000000e-5*b^3*c-.5759999999e-6*b^4-.8000000000e-3*a*d^3-.7680000000e-3*a*c*d^2-.2560000001e-3*a*c^2*d-.2925714286e-4*a*c^3-.1920000000e-3*a*b*d^2-.1316571428e-3*a*b*c*d-.2304000000e-4*a*b*c^2-.1728000000e-4*a*b^2*d-.6144000000e-5*a*b^2*c-.5529600000e-6*a*b^3-.2194285714e-4*a^2*d^2-.1536000000e-4*a^2*c*d-.2730666666e-5*a^2*c^2-.4096000001e-5*a^2*b*d-.1474560000e-5*a^2*b*c-.2010763636e-6*a^2*b^2-.3276800000e-6*a^3*d-.1191563636e-6*a^3*c-.3276800000e-7*a^3*b-.2016492308e-8*a^4&lt;/p&gt;</description>
      <guid>44119</guid>
      <pubDate>Mon, 15 Mar 2010 18:54:00 Z</pubDate>
      <itunes:author>Robert Israel</itunes:author>
      <author>Robert Israel</author>
    </item>
    <item>
      <title>Int ( sqrt( product ) )</title>
      <link>http://www.mapleprimes.com/questions/35507-How-To-Solve-An-Integration-With-Unknown?ref=Feed:MaplePrimes:How to solve an integration with unknown constants inside of it ???:Comments#answer44120</link>
      <itunes:summary>&lt;p&gt;I played a bit in an old Maple, which reports 6 explicite solutions for the term under the sqrt (have not checked them),&lt;/p&gt;
&lt;p&gt;may be you check Int ( sqrt( product ) )&lt;/p&gt;</itunes:summary>
      <description>&lt;p&gt;I played a bit in an old Maple, which reports 6 explicite solutions for the term under the sqrt (have not checked them),&lt;/p&gt;
&lt;p&gt;may be you check Int ( sqrt( product ) )&lt;/p&gt;</description>
      <guid>44120</guid>
      <pubDate>Mon, 15 Mar 2010 19:49:23 Z</pubDate>
      <itunes:author>Axel Vogt</itunes:author>
      <author>Axel Vogt</author>
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