http://www.mapleprimes.com/questions/35576-Lists en-us 2026 Maplesoft, A Division of Waterloo Maple Inc. Maplesoft Document System Thu, 18 Jun 2026 07:38:17 GMT Thu, 18 Jun 2026 07:38:17 GMT The latest answers and comments added to the Question, lists http://www.mapleprimes.com/images/mapleprimeswhite.jpg http://www.mapleprimes.com/questions/35576-Lists http://www.mapleprimes.com/questions/35576-Lists?ref=Feed:MaplePrimes:lists:Comments#answer44343 <pre> [seq([seq(`if`((j+k)::even,s,t),j=1..k)],k=1..5)]; [[s], [t, s], [s, t, s], [t, s, t, s], [s, t, s, t, s]] </pre> <pre> [seq([seq(`if`((j+k)::even,s,t),j=1..k)],k=1..5)]; [[s], [t, s], [s, t, s], [t, s, t, s], [s, t, s, t, s]] </pre> 44343 Sun, 07 Mar 2010 06:49:37 Z Joe Riel Joe Riel http://www.mapleprimes.com/questions/35576-Lists?ref=Feed:MaplePrimes:lists:Comments#answer44344 <p>Sorry I am trying really hard to get my head around this but I am failing.</p> <p>I get that j=1...k is the part which determines the size of each list, in this case going up to 5</p> <p>&nbsp;</p> <p>however I really dont get the part&nbsp;&nbsp;&nbsp; (`if`((j+k)::even,s,t),j=1..k)], is it saying if j+k is even then the element is s, if not it is t</p> <p>i.e [[ 1+1=even therefore s], [2+1=odd therfore t, 1+1=even therefore s], [ 3+1=even hence s] etc.....</p> <p>sorry I am just very confused.</p> <p>Sorry I am trying really hard to get my head around this but I am failing.</p> <p>I get that j=1...k is the part which determines the size of each list, in this case going up to 5</p> <p>&nbsp;</p> <p>however I really dont get the part&nbsp;&nbsp;&nbsp; (`if`((j+k)::even,s,t),j=1..k)], is it saying if j+k is even then the element is s, if not it is t</p> <p>i.e [[ 1+1=even therefore s], [2+1=odd therfore t, 1+1=even therefore s], [ 3+1=even hence s] etc.....</p> <p>sorry I am just very confused.</p> 44344 Tue, 09 Mar 2010 03:27:12 Z mathperson mathperson http://www.mapleprimes.com/questions/35576-Lists?ref=Feed:MaplePrimes:lists:Comments#answer44345 <p>From your examples I deduced that you wanted the first element in a list to be s if the number of elements in the list is odd, otherwise the first element is t. After that, the elements alternate between s and t.&nbsp; This was an easy way to both alternate parity (with j) and ensure that the first element of each sublist was the appropriate term.&nbsp; Your explanation is correct.&nbsp; </p> <p>From your examples I deduced that you wanted the first element in a list to be s if the number of elements in the list is odd, otherwise the first element is t. After that, the elements alternate between s and t.&nbsp; This was an easy way to both alternate parity (with j) and ensure that the first element of each sublist was the appropriate term.&nbsp; Your explanation is correct.&nbsp; </p> 44345 Tue, 09 Mar 2010 04:05:52 Z Joe Riel Joe Riel