function vs expression

Robert Israel — Sat, 06 Mar 2010 06:05:46 Z

intConv works if it's given two functions (well, it would if you corrected a small typo).

Heaviside is a function, and so is rect, i.e. you can say rect(x) where x is a number and you'll get a number. But rect(-t) is an expression, not a function: rect(-t)(x) doesn't make sense. You can use unapply to make an expression into a function. Thus

> intConv(Heaviside, unapply(rect(-t),t));

I think this was exactly

848380 — Sat, 06 Mar 2010 22:15:34 Z

I think this was exactly what I was looking for, thank you so much for your competent help!

MaplePrimes - answers and comments on Question, Call a procedure with negative argument variable

function vs expression

I think this was exactly