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    <title>MaplePrimes - answers and comments on Question, singularitys</title>
    <link>http://www.mapleprimes.com/questions/35604-Singularitys</link>
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    <pubDate>Sat, 13 Jun 2026 20:01:03 GMT</pubDate>
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    <description>The latest answers and comments added to the Question, singularitys</description>
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      <title>MaplePrimes - answers and comments on Question, singularitys</title>
      <link>http://www.mapleprimes.com/questions/35604-Singularitys</link>
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    <item>
      <title>By series</title>
      <link>http://www.mapleprimes.com/questions/35604-Singularitys?ref=Feed:MaplePrimes:singularitys:Comments#answer88314</link>
      <itunes:summary>&lt;p&gt;&amp;nbsp;Solve the system by series, replacing&lt;/p&gt;
&lt;p&gt;&amp;gt; sol4 := dsolve([eqn12, eqn13, f(0) = 1, e(0) = 1], numeric, maxfun =  1000000000);&lt;/p&gt;
&lt;p&gt;by&lt;/p&gt;
&lt;p&gt;&amp;gt;sol4 := dsolve({eqn12, eqn13}union {f(0) = 1, e(0) = 1},{e(z),f(z)},type='series');&lt;br /&gt;
&lt;br /&gt;
It works. Next, you might follow&amp;nbsp;&lt;/p&gt;
&lt;p&gt;http://www.mapleprimes.com/forum/odewpowerseriesplotting in this forum.&lt;/p&gt;</itunes:summary>
      <description>&lt;p&gt;&amp;nbsp;Solve the system by series, replacing&lt;/p&gt;
&lt;p&gt;&amp;gt; sol4 := dsolve([eqn12, eqn13, f(0) = 1, e(0) = 1], numeric, maxfun =  1000000000);&lt;/p&gt;
&lt;p&gt;by&lt;/p&gt;
&lt;p&gt;&amp;gt;sol4 := dsolve({eqn12, eqn13}union {f(0) = 1, e(0) = 1},{e(z),f(z)},type='series');&lt;br /&gt;
&lt;br /&gt;
It works. Next, you might follow&amp;nbsp;&lt;/p&gt;
&lt;p&gt;http://www.mapleprimes.com/forum/odewpowerseriesplotting in this forum.&lt;/p&gt;</description>
      <guid>88314</guid>
      <pubDate>Fri, 07 May 2010 07:27:15 Z</pubDate>
      <itunes:author>hirnyk</itunes:author>
      <author>hirnyk</author>
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    <item>
      <title>O</title>
      <link>http://www.mapleprimes.com/questions/35604-Singularitys?ref=Feed:MaplePrimes:singularitys:Comments#answer88315</link>
      <itunes:summary>&lt;p&gt;First of all, you shouldn't use O (which has a special meaning in terms of series, and causes a &amp;quot;too many levels of recursion&amp;quot; error).&amp;nbsp; Try o instead.&lt;/p&gt;
&lt;p&gt;Now it looks to me like there is a real singularity there: f(z)^4*(e(z)^2-.27*(1+z)^3)^2 hits 0.0081 at approximately z =  .76663139, after which you'll be taking the square root of a negative quantity.&amp;nbsp; If you want any chance of a sensible continuation past that singularity, perhaps you'll want to insert an absolute value.&amp;nbsp; Thus&lt;/p&gt;
&lt;pre&gt;
&amp;gt; eqn10 := diff(e(z)^2, z) = ((3/2)*e(z)^2-3*(n^2/f(z)^2)^2/(2*(e(z)^2-o*(1+z)^(3*g)))
     +(1/2)*((g-1)*3)*o*(1+z)^(3*g))/(2*(1+z));
  eqn11 := diff(f(z), z) = sqrt(abs(1-(n^2/f(z)^2)^2/(e(z)^2-o*(1+z)^(3*g))^2))/(e(z)*(1+z));
  eqn12 := subs(o = .27, g = 1, n = .3, eqn10);
  eqn13 := subs(o = .27, g = 1, n = .3, eqn11);
  sol4 := dsolve([eqn12, eqn13, f(0) = 1, e(0) = 1], numeric,method=classical[rk4],stepsize=0.00001,maxfun=10^6);
  plots[odeplot](sol4,[[z,e(z),colour=red],[z,f(z),colour=blue]],z=0 .. 2,numpoints=1000);
&lt;/pre&gt;
&lt;p&gt;&lt;span&gt;&lt;a href="http://www.mapleprimes.com/viewfile/4326"&gt;&lt;img src="http://www.mapleprimes.com/scripts/image.php?image=http://www.mapleprimes.com/files/4541_sol4.jpg&amp;amp;width=300&amp;amp;height=300" alt="" /&gt;&lt;/a&gt;&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;&lt;span&gt;As you can see, something &lt;/span&gt;strange happens to f(z).&amp;nbsp; &lt;br /&gt;
It turns out that (e(z)^2-.27*(1+z)^3) hits 0, resulting in df/dz going to infinity, at around z = .7867866833.&amp;nbsp; Because of the square root, I think the singularity should still be integrable, so f won't go to infinity, but it's going to be very hard for numerical methods to accurately reflect what does happen.&amp;nbsp; &lt;/p&gt;</itunes:summary>
      <description>&lt;p&gt;First of all, you shouldn't use O (which has a special meaning in terms of series, and causes a &amp;quot;too many levels of recursion&amp;quot; error).&amp;nbsp; Try o instead.&lt;/p&gt;
&lt;p&gt;Now it looks to me like there is a real singularity there: f(z)^4*(e(z)^2-.27*(1+z)^3)^2 hits 0.0081 at approximately z =  .76663139, after which you'll be taking the square root of a negative quantity.&amp;nbsp; If you want any chance of a sensible continuation past that singularity, perhaps you'll want to insert an absolute value.&amp;nbsp; Thus&lt;/p&gt;
&lt;pre&gt;
&amp;gt; eqn10 := diff(e(z)^2, z) = ((3/2)*e(z)^2-3*(n^2/f(z)^2)^2/(2*(e(z)^2-o*(1+z)^(3*g)))
     +(1/2)*((g-1)*3)*o*(1+z)^(3*g))/(2*(1+z));
  eqn11 := diff(f(z), z) = sqrt(abs(1-(n^2/f(z)^2)^2/(e(z)^2-o*(1+z)^(3*g))^2))/(e(z)*(1+z));
  eqn12 := subs(o = .27, g = 1, n = .3, eqn10);
  eqn13 := subs(o = .27, g = 1, n = .3, eqn11);
  sol4 := dsolve([eqn12, eqn13, f(0) = 1, e(0) = 1], numeric,method=classical[rk4],stepsize=0.00001,maxfun=10^6);
  plots[odeplot](sol4,[[z,e(z),colour=red],[z,f(z),colour=blue]],z=0 .. 2,numpoints=1000);
&lt;/pre&gt;
&lt;p&gt;&lt;span&gt;&lt;a href="http://www.mapleprimes.com/viewfile/4326"&gt;&lt;img src="http://www.mapleprimes.com/scripts/image.php?image=http://www.mapleprimes.com/files/4541_sol4.jpg&amp;amp;width=300&amp;amp;height=300" alt="" /&gt;&lt;/a&gt;&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;&lt;span&gt;As you can see, something &lt;/span&gt;strange happens to f(z).&amp;nbsp; &lt;br /&gt;
It turns out that (e(z)^2-.27*(1+z)^3) hits 0, resulting in df/dz going to infinity, at around z = .7867866833.&amp;nbsp; Because of the square root, I think the singularity should still be integrable, so f won't go to infinity, but it's going to be very hard for numerical methods to accurately reflect what does happen.&amp;nbsp; &lt;/p&gt;</description>
      <guid>88315</guid>
      <pubDate>Fri, 07 May 2010 09:39:00 Z</pubDate>
      <itunes:author>Robert Israel</itunes:author>
      <author>Robert Israel</author>
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    <item>
      <title>Series and singularities</title>
      <link>http://www.mapleprimes.com/questions/35604-Singularitys?ref=Feed:MaplePrimes:singularitys:Comments#comment88316</link>
      <itunes:summary>&lt;p&gt;If there is a singularity, the series solution will have the radius of convergence equal or less than the distance from the center of the series to the singularity (perhaps, there are exceptions, but that's what usually happen), so it can not be used for continuation after the singularity. That can be cleary seen both here and in the example that you cited.&lt;/p&gt;
&lt;p&gt;Alec&lt;/p&gt;</itunes:summary>
      <description>&lt;p&gt;If there is a singularity, the series solution will have the radius of convergence equal or less than the distance from the center of the series to the singularity (perhaps, there are exceptions, but that's what usually happen), so it can not be used for continuation after the singularity. That can be cleary seen both here and in the example that you cited.&lt;/p&gt;
&lt;p&gt;Alec&lt;/p&gt;</description>
      <guid>88316</guid>
      <pubDate>Fri, 07 May 2010 17:21:36 Z</pubDate>
      <itunes:author>alec</itunes:author>
      <author>alec</author>
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