MaplePrimes - answers and comments on Question, animate3d, is this possible using pointplots?

animate should work for this

Doug Meade — Thu, 14 May 2009 20:52:56 Z

animate3d has been replaced with animate. The animate command is pretty powerful but can take a little time to learn to use.

Suppose you generate the individual frames with the command

pointplot3d( plotter[1], other options );

then you would create the animation of the 20 frames with

animate( pointplot3d, [plotter[i], other options], i=1..20 );

Now, it sounds as though you want each frame to simply add one more set of points to the overall image. For this, use the trace option of the animate command:

animate( pointplot3d, [plotter[i], other options], i=1..20, trace=1 );

There is also a background option that allows you to specify a common background for all frames in the animation.

See the help for plots,animate for complete details and some examples.

Doug

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Douglas B. Meade  <><
Math, USC, Columbia, SC 29208  E-mail: mailto:meade@math.sc.edu
Phone:  (803) 777-6183         URL:    http://www.math.sc.edu

I appreciate your help, it

Matthew S — Thu, 14 May 2009 21:41:33 Z

I appreciate your help, it sounds like exactly what I want, but I get this for output:

> animate(pointplot3d, [plotter[c], style = line, linestyle = solid, thickness = 5], c = 1 .. 15);
Error, (in plots/animate) points are not in the correct format

It must be a syntax error of sorts, because when i do this:

> pointplot3d(plotter[1],style=line,linestyle=solid,thickness=5);

I get an output of this:

http://s77.photobucket.com/albums/j71/MisterHomes/?action=view&current=polygon.png

That worked perfectly.

Matthew S — Thu, 14 May 2009 23:36:00 Z

That worked perfectly. Thanks very much for your help.

more animate ideas - define your own custom plot proc

Doug Meade — Thu, 14 May 2009 23:59:21 Z

Here is how I would continue to do this, with animate. Define your own command to create individual frames in the animation:

PlotFrame := i -> plots:-pointplot3d( plotter[i], style=line, linestyle=solid, thickness=5 );

Once you have debugged PlotFrame, you can call animate as follows:

animate( PlotFrame, [c], c=[$1..N], trace=N-1 );

where N is the total number of frames. Note the use of a list to avoid the problem Robert pointed out with Maple using a float for the parameter range. (Maybe you can replace N with an appropriate dimension of plotter.)

Lastly, the trace option should be set to N-1 (not 1 as I wrote in my original post). The total number of frames to be shown at the end of the animation is one more than this setting, so N-1 means that all N frames will be shown at the end.

I think this should be pretty close to what you are trying to do.

Doug

---------------------------------------------------------------------
Douglas B. Meade  <><
Math, USC, Columbia, SC 29208  E-mail: mailto:meade@math.sc.edu
Phone:  (803) 777-6183         URL:    http://www.math.sc.edu

Doug, you are my hero.

Matthew S — Fri, 15 May 2009 00:21:00 Z

Doug, you are my hero. You are the greatest.

Hello. I would greatly

wirefree — Sat, 20 Mar 2010 07:10:27 Z

Hello. I would greatly appreciate assistance with the procedure for defining a 1D array where each element is a 3D coordinate, as has been referred to in the first post of this thread by Poster Matthew by the name "plotter[1..20]". Please note that I have attempted the following code to no avail: plotter := array((10, 2, -3), (5, -5, 6), (17, -8, 1)); Look forward to a prompt response. Best regards, wirefree