MaplePrimes - answers and comments on Question, Parametric Surface - Axes Question

Wow, that looks horrible; I

ihayles — Fri, 13 Mar 2009 22:28:24 Z

Wow, that looks horrible; I thought the Preview Feature was broken, but apparently not. The code looks cleaner in plain text...

S5:=PositionVector([uv,u+v,u-v],cartesian[x,y,z])

PlotPositionVector(S5,u=-1..1,v=-sqrt(1-u^2)..sqrt(1-u^2))

ihayles — Fri, 13 Mar 2009 23:22:04 Z

This seems to only be an issue when the bounds of one parameter are the function of another parameter. That is, if I do

PlotPositionVector(S5,u=-1..1,v=-1..1)

then the axes are unlabeled.

Robert Israel — Sun, 15 Mar 2009 13:13:47 Z

plots[display](%, labels=[x,y,z]);