<rss xmlns:itunes="http://www.itunes.com/dtds/podcast-1.0.dtd" version="2.0">
  <channel>
    <title>MaplePrimes - answers and comments on Question, Kirchhoff and linear systems</title>
    <link>http://www.mapleprimes.com/questions/38536-Kirchhoff-And-Linear-Systems</link>
    <language>en-us</language>
    <copyright>2026 Maplesoft, A Division of Waterloo Maple Inc.</copyright>
    <generator>Maplesoft Document System</generator>
    <lastBuildDate>Tue, 09 Jun 2026 18:17:47 GMT</lastBuildDate>
    <pubDate>Tue, 09 Jun 2026 18:17:47 GMT</pubDate>
    <itunes:subtitle />
    <itunes:summary />
    <description>The latest answers and comments added to the Question, Kirchhoff and linear systems</description>
    <image>
      <url>http://www.mapleprimes.com/images/mapleprimeswhite.jpg</url>
      <title>MaplePrimes - answers and comments on Question, Kirchhoff and linear systems</title>
      <link>http://www.mapleprimes.com/questions/38536-Kirchhoff-And-Linear-Systems</link>
    </image>
    <item>
      <title>Circuit solver</title>
      <link>http://www.mapleprimes.com/questions/38536-Kirchhoff-And-Linear-Systems?ref=Feed:MaplePrimes:Kirchhoff and linear systems:Comments#answer69375</link>
      <itunes:summary>&lt;p&gt;You might check out the &lt;a href="http://www.maplesoft.com/applications/app_center_browse.aspx?CID=13&amp;amp;SCID=127"&gt;Syrup package&lt;/a&gt; in the application center; it can quickly solve this circuit.&lt;/p&gt;</itunes:summary>
      <description>&lt;p&gt;You might check out the &lt;a href="http://www.maplesoft.com/applications/app_center_browse.aspx?CID=13&amp;amp;SCID=127"&gt;Syrup package&lt;/a&gt; in the application center; it can quickly solve this circuit.&lt;/p&gt;</description>
      <guid>69375</guid>
      <pubDate>Sat, 18 Oct 2008 22:32:24 Z</pubDate>
      <itunes:author>Joe
 Riel
</itunes:author>
      <author>Joe
 Riel
</author>
    </item>
    <item>
      <title>My bad</title>
      <link>http://www.mapleprimes.com/questions/38536-Kirchhoff-And-Linear-Systems?ref=Feed:MaplePrimes:Kirchhoff and linear systems:Comments#answer69374</link>
      <itunes:summary>&lt;p&gt;I forgot to mention I need to solve this using a linear system.&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;</itunes:summary>
      <description>&lt;p&gt;I forgot to mention I need to solve this using a linear system.&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;</description>
      <guid>69374</guid>
      <pubDate>Sat, 18 Oct 2008 22:35:42 Z</pubDate>
      <itunes:author>Sam9530130</itunes:author>
      <author>Sam9530130</author>
    </item>
    <item>
      <title>I've been reading about</title>
      <link>http://www.mapleprimes.com/questions/38536-Kirchhoff-And-Linear-Systems?ref=Feed:MaplePrimes:Kirchhoff and linear systems:Comments#answer69373</link>
      <itunes:summary>&lt;p&gt;&lt;span&gt;&lt;a href="http://mapleoracles.maplesoft.com:8080/maplenet/primes/worksheet/6892_Kirchhoff.mw"&gt;View 6892_Kirchhoff.mw on MapleNet&lt;/a&gt; or &lt;a href="http://www.mapleprimes.com/files/6892_Kirchhoff.mw"&gt;Download 6892_Kirchhoff.mw&lt;/a&gt;&lt;br /&gt;
&lt;a href="http://www.mapleprimes.com/viewfile/2837"&gt;View file details&lt;/a&gt;&lt;/span&gt;&lt;br /&gt;
&lt;br /&gt;
I've been reading about it since this morning. I made a linear system using only Kirchhoff's Current Law. ( The current entering a junction is equal to the current leaving it )&lt;br /&gt;
But I don't see how I will get to use the Voltage law yet.&lt;br /&gt;
Also when I solve the system, it gives me that I&lt;sub&gt;9&lt;/sub&gt;=0.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&amp;nbsp; edit : Would it be good if I started at either V&lt;sub&gt;1&lt;/sub&gt; or V&lt;sub&gt;2&lt;/sub&gt; and I'd do 9 different ways and come back at the starting point. I'd have equations that would look like this :&amp;nbsp; V&lt;sub&gt;2&lt;/sub&gt; - R&lt;sub&gt;10&lt;/sub&gt;*I&lt;sub&gt;9&lt;/sub&gt; - R&lt;sub&gt;2&lt;/sub&gt;*I&lt;sub&gt;3&lt;/sub&gt; = V&lt;sub&gt;1&lt;/sub&gt; &lt;br /&gt;
or something like that.&lt;br /&gt;
&lt;br /&gt;
Am I in the good way or I didn't understand the concept? &lt;/p&gt;</itunes:summary>
      <description>&lt;p&gt;&lt;span&gt;&lt;a href="http://mapleoracles.maplesoft.com:8080/maplenet/primes/worksheet/6892_Kirchhoff.mw"&gt;View 6892_Kirchhoff.mw on MapleNet&lt;/a&gt; or &lt;a href="http://www.mapleprimes.com/files/6892_Kirchhoff.mw"&gt;Download 6892_Kirchhoff.mw&lt;/a&gt;&lt;br /&gt;
&lt;a href="http://www.mapleprimes.com/viewfile/2837"&gt;View file details&lt;/a&gt;&lt;/span&gt;&lt;br /&gt;
&lt;br /&gt;
I've been reading about it since this morning. I made a linear system using only Kirchhoff's Current Law. ( The current entering a junction is equal to the current leaving it )&lt;br /&gt;
But I don't see how I will get to use the Voltage law yet.&lt;br /&gt;
Also when I solve the system, it gives me that I&lt;sub&gt;9&lt;/sub&gt;=0.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&amp;nbsp; edit : Would it be good if I started at either V&lt;sub&gt;1&lt;/sub&gt; or V&lt;sub&gt;2&lt;/sub&gt; and I'd do 9 different ways and come back at the starting point. I'd have equations that would look like this :&amp;nbsp; V&lt;sub&gt;2&lt;/sub&gt; - R&lt;sub&gt;10&lt;/sub&gt;*I&lt;sub&gt;9&lt;/sub&gt; - R&lt;sub&gt;2&lt;/sub&gt;*I&lt;sub&gt;3&lt;/sub&gt; = V&lt;sub&gt;1&lt;/sub&gt; &lt;br /&gt;
or something like that.&lt;br /&gt;
&lt;br /&gt;
Am I in the good way or I didn't understand the concept? &lt;/p&gt;</description>
      <guid>69373</guid>
      <pubDate>Sat, 18 Oct 2008 23:56:50 Z</pubDate>
      <itunes:author>Sam9530130</itunes:author>
      <author>Sam9530130</author>
    </item>
    <item>
      <title>Put aside this circuit for a while</title>
      <link>http://www.mapleprimes.com/questions/38536-Kirchhoff-And-Linear-Systems?ref=Feed:MaplePrimes:Kirchhoff and linear systems:Comments#comment82715</link>
      <itunes:summary>&lt;p&gt;Begin with simpler circuits, of one or two loops. You have two basic standard methods for writing the system of equations: by branch current and by mesh current. Besides your textbooks, you may find by googling for these methods plenty of tutorials. Just as a sample I have found these ones:&lt;/p&gt;
&lt;p&gt;http://www.allaboutcircuits.com/vol_1/chpt_10/2.html&lt;/p&gt;
&lt;p&gt;http://www.allaboutcircuits.com/vol_1/chpt_10/3.html&lt;/p&gt;</itunes:summary>
      <description>&lt;p&gt;Begin with simpler circuits, of one or two loops. You have two basic standard methods for writing the system of equations: by branch current and by mesh current. Besides your textbooks, you may find by googling for these methods plenty of tutorials. Just as a sample I have found these ones:&lt;/p&gt;
&lt;p&gt;http://www.allaboutcircuits.com/vol_1/chpt_10/2.html&lt;/p&gt;
&lt;p&gt;http://www.allaboutcircuits.com/vol_1/chpt_10/3.html&lt;/p&gt;</description>
      <guid>82715</guid>
      <pubDate>Sun, 19 Oct 2008 00:52:55 Z</pubDate>
      <itunes:author>jakubi</itunes:author>
      <author>jakubi</author>
    </item>
    <item>
      <title>mesh analysis</title>
      <link>http://www.mapleprimes.com/questions/38536-Kirchhoff-And-Linear-Systems?ref=Feed:MaplePrimes:Kirchhoff and linear systems:Comments#comment82716</link>
      <itunes:summary>&lt;p&gt;I'd use a mesh analysis, that requires only four equations:&lt;/p&gt;
&lt;pre&gt;
eqs := {NULL
&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; , R2*M1 + R1*(M1-M2) + R3*(M1-M3)
&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; , R1*(M2-M1) + V1 + R5*M2 + R6*(M2-M4) + R4*(M2-M3)
&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; , R3*(M3-M1) + R4*(M3-M2) + R7*(M3-M4) - V2 +R10*M3
&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; , R6*(M4-M2) + R8*M4 + R9*M4 + R7*(M4-M3)
&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; };

sol := solve(eqs,{M1,M2,M3,M4});
&lt;/pre&gt;
&lt;p&gt;To solve for a particular current in a branch, express it in terms of the meshes. For example,&lt;/p&gt;
&lt;pre&gt;
I5 = M3 - M2:
&lt;/pre&gt;
&lt;div&gt;To get numerical values, create a set of equations for the parameters, and substitute them in, along with the solution:&lt;/div&gt;
&lt;pre&gt;
params := {R1 = 5, R2 = 200, ... }:
subs(sol, params, M3-M2);
&lt;/pre&gt;</itunes:summary>
      <description>&lt;p&gt;I'd use a mesh analysis, that requires only four equations:&lt;/p&gt;
&lt;pre&gt;
eqs := {NULL
&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; , R2*M1 + R1*(M1-M2) + R3*(M1-M3)
&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; , R1*(M2-M1) + V1 + R5*M2 + R6*(M2-M4) + R4*(M2-M3)
&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; , R3*(M3-M1) + R4*(M3-M2) + R7*(M3-M4) - V2 +R10*M3
&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; , R6*(M4-M2) + R8*M4 + R9*M4 + R7*(M4-M3)
&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; };

sol := solve(eqs,{M1,M2,M3,M4});
&lt;/pre&gt;
&lt;p&gt;To solve for a particular current in a branch, express it in terms of the meshes. For example,&lt;/p&gt;
&lt;pre&gt;
I5 = M3 - M2:
&lt;/pre&gt;
&lt;div&gt;To get numerical values, create a set of equations for the parameters, and substitute them in, along with the solution:&lt;/div&gt;
&lt;pre&gt;
params := {R1 = 5, R2 = 200, ... }:
subs(sol, params, M3-M2);
&lt;/pre&gt;</description>
      <guid>82716</guid>
      <pubDate>Sun, 19 Oct 2008 00:53:30 Z</pubDate>
      <itunes:author>Joe
 Riel
</itunes:author>
      <author>Joe
 Riel
</author>
    </item>
    <item>
      <title>an advise</title>
      <link>http://www.mapleprimes.com/questions/38536-Kirchhoff-And-Linear-Systems?ref=Feed:MaplePrimes:Kirchhoff and linear systems:Comments#comment82717</link>
      <itunes:summary>&lt;p&gt;If you do not know yet what Kirchhoff laws are, it seems prudent that you learn them reading your textbook of Electricity and Magnetism and then begin solving simpler circuits.&lt;/p&gt;</itunes:summary>
      <description>&lt;p&gt;If you do not know yet what Kirchhoff laws are, it seems prudent that you learn them reading your textbook of Electricity and Magnetism and then begin solving simpler circuits.&lt;/p&gt;</description>
      <guid>82717</guid>
      <pubDate>Sat, 18 Oct 2008 22:56:46 Z</pubDate>
      <itunes:author>jakubi</itunes:author>
      <author>jakubi</author>
    </item>
  </channel>
</rss>