MaplePrimes - answers and comments on Question, how do I really unassume a variable in Maple?

assuming

Mariner — Wed, 26 Sep 2007 23:19:14 Z

You could try something like this: restart; f1 := alpha*(3*lambda^3*rho*d/(rho^2 + d^2)^(5/2)); I1 := int(f1,rho=a..b) assuming d>0; d := 3.0; I1; Hope this helps. J. Tarr

evaluating at d=3

Robert Israel — Wed, 26 Sep 2007 23:42:08 Z

Irrespective of the "assume" versus "assuming" issue, if you want to plug in a specific number for d in your expression, it's best to use "eval" rather than assigning a value to d. Thus:

> eval(I1, d = 3.0);

-3.0*alpha*lambda^3*(-(b^2+9.00)^(3/2)+(a^2+9.00)^(3/2)) /(a^2+9.00)^(3/2)/(b^2+9.00)^(3/2) If you really do want to remove assumptions on a variable, you can do that as follows:

> assign(d,'d'): unassign('d'):

Thanks for your help!

tintin — Thu, 27 Sep 2007 00:26:43 Z

Thanks for all your help! I did have in mind the removal of the assumption, so the suggested command assign(d,'d'): unassign('d'): will be quite useful! -Dan

unassume

SandorSzabo — Fri, 05 Oct 2007 21:08:30 Z

A shorthand version is a:='a': Sandor