June 19 2006
yya 8
Hi, all.
I want to write viewer/converter for mw/mws, so mw/mws format description needed. Google say nothing about mw/mws format. search.maplesoft.com likewise.
Can somebody help me with mw/mws format description? Is it possible to obtain such info from Maple developers? Is reverse engineering of mw/mws prohibited?

May 24 2006
matt 4
Recently I met problems like these (shown here in minimal, stripped down examples no longer doing

anything useful except illustrating the problem). Any suggestions about what is going on here would be appreciated. Thanks.

**> interface(version);restart;**

Maple 10.03 gets stuck on my machine (Mac OS X, version 10.6.4) evaluating the first execution group below,t hough in Maple 6 on Mac OS 9.1 one gets only some strange output (?s, similar to those in output below). In the procedure f, the parameter W is intended to be a module exporting a procedure W:-m; the behaviour is not improved by careful type declarations, so for simplicity I've left them out.

With this Generation of MapleStudio you can also plot complex functions in 2D and also 3D. For doing this, MapleStudio uses the **conformal **and the** conformal3d** comands of Maple 10. The following example will show you, how it works.

I used to be able to do this copy/paste ... Here, I got an integral, then copied the output and pasted onto the next line. I wanted Maple input format, of course. Is it a change for Maple 10.03? for Mac? Or what? Have I got some setting wrong?

Finding the period is simple enough, but gets really irritating once the number of terms in the continued fraction expansion gets large. I've scoured the help files and cannot find anything on it. All I have managed to do is right click on the output and convert it to a list. But then I don't know what the command is to find the number of elements in that list.

Here's a frustrating problem I've been having with "assume".

You'll see below that I assume that v'(m) >0 and v''(m) <>

Maple clearly remembers that v'(m) > 0 (as seen in the assumptions list and by looking at the first "is" in (4)), however, it now can't figure out that v'(m) > 0 implies !(v'(m) <>

Strangely, this worked perfectly fine before the additional assumption was added, and looking up the property (6) reveals the correct answer.

Moreover, maple seems to have two sets of assumptions on v'(m) (for six total assumptions, when I would expect four).

Any maple geniuses have an idea as to why Maple's "is" function is confused?

I am brand new to MAPLE. I have a large file full of equations which I want to put into a paper. Is there software, or a facility within MAPLE, to convert all these equations into WORD, or at least to TECH, without typing everything in again? Please respond with any help to Jerry Epstein jepstein@poly.edu

Is this a way to convert a routine in Maple internal format back to the human-readable format?

Thanks

I was wondering if someone can help me solve a problem of kirchoff's law using maple, heres the problem:

Use maple and Laplace transform to find the charge q(t) on the capacitor in an RC series circuit with the following conditions; graph q(t) on the interval 0<t<6 and use the graph to estimate the time and value of the maximum charge

q(0)=0

R=50 ohms

C=.01 farads

E is a piecewise where 1<x<3 = 100, everywhere else is zero

I'm assuming that since nothing is said about the inductance in the initial conditions, L=0

heres what i got so far:

>i(t):= diff(q(t),t);

>KirchoffLaw:=E[R]+E[L]+E[C]-E[emf]=0;

Consider the following three problems:
1) given a list [a,b,c,d,e], return the list [a=1,b=2,c=3,d=4,e=5]
2) given a nested list [a, [b, [c, [d, [e]]]]] return the list [a,b,c,d,e]
3) given an integer in base 10, compute it's base b representation
First I will show you what not to do:

L := [a,b,c,d,e];
M := [];
for i from 1 to nops(L) do
M := [op(M), L[i]=i];
end do;

Building up lists (and sets) incrementally is quadratic time, because each iteration of the loop allocates linear storage to hold the new list. The standard solution is a loop with a temporary variable, assigning to a table:

April 11 2006
JanE 28
The following interactive worksheet gives you the possibility to plot functions in 2D and 3D. There is also an interactive version available on the MapleNET - Server. You find it here. You can also download the worksheet here and run it in your Maple.

I will try to publish further versions with more possibilities to plot in the next weeks.

Ten days playing with Maple has proven that skills in one system don't necessarily translate to another. I have encountered a number of frustrations which are not so much a problem with Maple as my inability to match the subtleties of the new system. Some of the issues I have encountered:

- periodic locking up of the interface in document mode (this may be due to something I am doing wrong)
- getting used to the maple syntax and command list (it is further than the syntax of Mathematica than I originally suspected yet similar enough to completely mess me up)
- occasional odd state like behavior (which is, again, probably due to my ignorance than a problem with Maple)

Hey all
I would like to know if after solving a Matrix Differntial Equation (general form, no initial conditions) there is a way to convert the solution matrix to equation form (i.e. y(t)= C_1e^(3t)+C_2e^(-t)+... etc).
see yas
david

I haven't been to mapleprimes for awhile and noticed that the "convert worksheet" option is no longer available. Are the "file manager" and "upload file" options very different from the previous worksheet converter, and are they also any more difficult ?

I'm working on some basic complex number equalities in engineering class, and was practicing converting from cartesian to polar coordinates. Maple can help by telling me if my conversions are correct by telling me whether the equality is true. For example, for the complex number: 5 + 3*I maple will verify the following:
is(5+3*I = polar(sqrt(5^2+3^2), arctan(3/5)))
true
it will also verify:
is(polar(sqrt(5^2+3^2), arctan(3/5)) = sqrt(5^2+3^2)*exp(I*arctan(3/5)))
true
lastly, it will of course verify transitively:
is(5+3*I = sqrt(5^2+3^2)*exp(I*arctan(3/5)))
true