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Has anyone seen this form of a nonlinear equation with respect to X, but linear with respect to Y & Z?  I provided a contour plot within the region for all 3 variables between -2 & 2.  The plot is actually Z*conjugate(Z) so that the magnitude is above ZERO.  If I am correct I may have seen this before in orbital mechanics, but my undergrad years are a bit...

As many of you know now the MRB constant = sum((-1)^n*(n^(1/n)-1),n=1..infinity).

Here are some equations involving various forms of that summation.

The first one involves convergent series and is too obvious. The others involve divergent series.

The last two, however, are new!


Let c=MRB constant and a, c~, x, and y = any number.


sum((-1)^n*(c~*n^(1/n)-c~),n=1..infinity)= c*c~.

evalf(sum((-1)^n*(n^(1/n)-a),n=1..infinity)) gives c-1/2*(1-a).

evalf(sum((-1)^n*(x*n^(1/n)+y*n),n=1..infinity)) gives (c-1/2)*x-1/4*y.

And it appears that

evalf(sum((-1)^n*(x*n^(1/n)-a),n=1..infinity)) gives (c - 1/2)*x + 1/2*a.

I would like to know if there is any way to coax maple into spitting out the solution (1,1,1) for the system of equations {x2+y2+z2=3, x+y+z=3}. So far all I have come up with is


This produces


as desired, but I would like to accomplish this without specifying the polynomial...

I'm new to using Maple. I'm trying to evaluate an equation where all unknowns are given. So to say use Maple

as a kind of desktop calculator with the possibility to change certain input variables and see what the outcome is.


I'm wondering why the trigonometric functions are not evaluated.


I want to solve the equation (1 + 1/x)*(1 + 1/y)*(1 + 1/z)=2 with integer solutions. I tried 

isolve((1 + 1/x)*(1 + 1/y)*(1 + 1/z)=2);

and I get {x = -1, y = -2, z = 0}. Is this a bug?

I have a differential equation having a parameter say 'a'.

If I increase 'a' by 10%, got change in the solution as well.

How to calculate change in percentage in the solution?.


 I am conveting ordinary differntial equations into polynomial using differential tranformed method and also after using pade arroximants for finding converge point at infinity. because differential transform cannot satisfy boundary at infinity. EQ1 and EQ2 does not built up fromt he preceeding iterations. its pade approximants diagonal value results like pade[3,3],[4,4],[5,5] and so on. i can solve this type for single equations but when  i solve coupled equations...


recently I was helped on this forum when I asked how to work with exterior products:

Now I would like to know how I can efficiently let Maple solve systems of equations between wedge products.


For instance, I would ask Maple to solve 



I'm currently working on the modelling of a thermodynamic process.

Briefly, I cool down a solution (water + polymer) from -5°C to -15°C to induce a phase separation. At the end (and after removing of the water by lyophilisation) I obtain a porous sponge like material.

The process uses a home made cooling system which can be described like this:

- A Peltier module

- An aluminium layer recovered by teflon (And also a layer of ethanol)

I want to graph the portion of the plane 2x + 3y + z = 6 that are located in the first octant of a xyz coordinate system. The following implicitplot3d should in principle do it:

Hello everyone,

I'm trying to solve the following nonlinear differential equation with the given boundary conditions.


I'm currently working on chemical process thermal exchange and particularly on the solving of the heat equation using a time dependant boundary condition.

Briefly, the process consists in two layers of different materials (M1 and M2, thickness L1 and L2). The bottom part of the material M1 (z=0) is cooled down from Ti to Tf with the function T(0,t)=Ti-R*t (R is the cooling rate in °C.min-1) until T(0,t)=Tf. Here the equilibrium is reached in t=(Tf-Ti...

Hi There,


Wondering if anyone was able to assist...


I'm trying to differentiate the following equation with respect to Qin:




I have tried using the diff command but with no luck, Maple is returning D(T)(Qin-Qp1)*(Qp2-Qin)/(Qp2-Qp1)-T(Qin-Qp1)/(Qp2-Qp1) which is not complete. 


Any assistance would be much appreciated.

Hi, I got a problem that "Warning, solutions may have been lost" when I solve 

eqns := {a+r*t*ln(l)+(1-l)^2*m-b-r*t*ln(s)-(1-s)^2*n = 0, a+r*t*ln(1-l)+l^2*m-b-r*t*ln(1-s)-s^2*n = 0}
vars := {l, s}
solve(eqns, vars)
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