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We know that the set f:={(1,2),(2,a),(3,b)} can introduce a function from {1,2,3} to {2,a,b}. I want Maple to know f as a function. Is this job possible at Maple? I thought to find the Cartesian product of above latter sets and then try to select "f" as one of its subset but this did not help me to force Maple to take "f" as a function. Indeed, I want to work with this kind of function (like plotting and doing f+g, f-g, fog for two functions for example).

Thanks for your time and help.

 

Can someone please advise me how to solve the following for 'beta'. Solve function is not able to do that, or at least I dont know how.

-9999990000000000000000*cos(166*beta)*sinh(166*beta)*cosh(88*beta)^2-9999990000000000000000*cos(88*beta)^2*sin(166*beta)*cosh(166*beta)+9999990000000000000000*sinh(166*beta)*cos(88*beta)^2*cos(166*beta)+9999990000000000000000*cosh(88*beta)^2*cosh(166*beta)*sin(166*beta)+10000010000000000000000*cos(166*beta)*sinh(166*beta)+10000010000000000000000*sin(166*beta)*cosh(166*beta)+9999990000000000000000*sinh(88*beta)*cos(166*beta)*cosh(166*beta)*cosh(88*beta)-9999990000000000000000*sinh(88*beta)*sin(166*beta)*sinh(166*beta)*cosh(88*beta)+9999990000000000000000*sin(88*beta)*cos(88*beta)*sinh(166*beta)*sin(166*beta)+9999990000000000000000*cos(88*beta)*cos(166*beta)*sin(88*beta)*cosh(166*beta)-9980010000000000000000*cosh(88*beta)^2*sinh(166*beta)*cos(88*beta)^2*cos(166*beta)-9980010000000000000000*cosh(88*beta)^2*cosh(166*beta)*sin(166*beta)*cos(88*beta)^2+9980010000000000000000*sinh(88*beta)*cos(88*beta)^2*sin(166*beta)*sinh(166*beta)*cosh(88*beta)-9980010000000000000000*cos(88*beta)*cosh(88*beta)^2*sin(88*beta)*sin(166*beta)*sinh(166*beta)+9980010000000000000000*sinh(88*beta)*cosh(88*beta)*cosh(166*beta)*cos(88*beta)^2*cos(166*beta)+9980010000000000000000*cosh(88*beta)^2*cosh(166*beta)*cos(88*beta)*sin(88*beta)*cos(166*beta)-9980010000000000000000*cos(88*beta)*sinh(88*beta)*cos(166*beta)*sin(88*beta)*sinh(166*beta)*cosh(88*beta)+9980010000000000000000*cos(88*beta)*cosh(88*beta)*sin(88*beta)*sin(166*beta)*cosh(166*beta)*sinh(88*beta)=0

Hello those in Mapleprimes,

 

What I want to know is whether this is possible or not, and if possible, how should I write a code?

 

The following code works properly:

 

U:=(x,y)->(x^theta+y^theta+X)^(1/theta);

diff(U(x,y),x)/diff(U(x,y),y)=p/q;simplify(%);

But, what I want to ask is this. As for the part of simplify(%), I want to do it with a way which has me 

feel more being from the former to latter.

That is, if ,for example, "diff(U(x,y),x)/diff(U(x,y),y)=p/q;@simplify;" works, it is better to me, though this does not work.

As the second part, @simplify, receives the result of the first part"diff(U(x,y),x)/diff(U(x,y),y)", it seems more 

natural to me than to write simplify(%).

 

Can't I do this, in a meaning, reversal of operator to argument?

 

taro

Hi every body:

i will plot this function in maple in domain x=0..1,but when use the plot commond i see this warning:

Warning, unable to evaluate the function to numeric values in the region; complex values were detected

how can I plot it?

eq := 4.728139762*10^(-14)*sqrt((-5.905404581*10^83*x^4-1.382542004*10^88*x^2+2.271592177*10^92+1.631888578*10^79*x^6+2.795756904*10^23*sqrt(-1.317535223*10^121*x^8+6.370084310*10^125*x^6-7.852926774*10^129*x^4+2.223707894*10^132*x^2-1.592721566*10^134))^(1/3)*(-(1.114348319*10^53*I)*x^4-6.433693022*10^52*x^4+(2.688368867*10^57*I)*x^2+1.552130489*10^57*x^2+5.072945110*10^26*x^2*(-5.905404581*10^83*x^4-1.382542004*10^88*x^2+2.271592177*10^92+1.631888578*10^79*x^6+2.795756904*10^23*sqrt(-1.317535223*10^121*x^8+6.370084310*10^125*x^6-7.852926774*10^129*x^4+2.223707894*10^132*x^2-1.592721566*10^134))^(1/3)-3.723246850*10^61-6.448852713*10^61*I+(1.732050808*I)*(-5.905404581*10^83*x^4-1.382542004*10^88*x^2+2.271592177*10^92+1.631888578*10^79*x^6+2.795756904*10^23*sqrt(-1.317535223*10^121*x^8+6.370084310*10^125*x^6-7.852926774*10^129*x^4+2.223707894*10^132*x^2-1.592721566*10^134))^(2/3)+1.231339558*10^31*(-5.905404581*10^83*x^4-1.382542004*10^88*x^2+2.271592177*10^92+1.631888578*10^79*x^6+2.795756904*10^23*sqrt(-1.317535223*10^121*x^8+6.370084310*10^125*x^6-7.852926774*10^129*x^4+2.223707894*10^132*x^2-1.592721566*10^134))^(1/3)-1.*(-5.905404581*10^83*x^4-1.382542004*10^88*x^2+2.271592177*10^92+1.631888578*10^79*x^6+2.795756904*10^23*sqrt(-1.317535223*10^121*x^8+6.370084310*10^125*x^6-7.852926774*10^129*x^4+2.223707894*10^132*x^2-1.592721566*10^134))^(2/3)))/(-5.905404581*10^83*x^4-1.382542004*10^88*x^2+2.271592177*10^92+1.631888578*10^79*x^6+2.795756904*10^23*sqrt(-1.317535223*10^121*x^8+6.370084310*10^125*x^6-7.852926774*10^129*x^4+2.223707894*10^132*x^2-1.592721566*10^134))^(1/3)

with regards...

Hi All. Hope all is well.

Assume that we have partitioned [0,a], into N equidistant subintervals and in each subinterval we have M sets of polynomials of arbitrary form[say bij(t)](a.e Taylor series, or Bernstein series,…)

for Example with N=4, M=3 and by Taylor series we have:

 

now we want to approximate a function, asy f(t), in this interval with following form:

 

If we have:

(Tau is a constant number)
then: How can  we find L and Z matrices using maple? Is it any way? (or other softwares?)

Regards

 

Mahmood   Dadkhah

Ph.D Candidate

Applied Mathematics Department

 

The help documents read,

 The function unames returns an expression sequence consisting of all the active names in the current Maple session which are ``unassigned names''.

 

But what unames() returns is obviously not the contents one expects:

 

Hi all,

 

As we know that the differential of conjugate(z) is non-analytic.

But it seems that the diff gives the solution about the complex function conjugate(z)

 

What does it mean?

how to singularize existing function?

any group theory can describe the singularity function?

Hello everybody, i need to graphic a couple of functions just like this one:

 http://temasmatematicos.uniandes.edu.co/Casquetes_cilindricos/Pags/Anim_1.htm

i have been watching this:

 http://www.maplesoft.com/teachingconcepts/detail.aspx?cid=12 VISUALIZATION --> Animation 2

i've tried with (plots) (plottools) animate, etc. but i can't figure out how to do it. 

It would be very helpful if someone explain me how to do this.

Thank you all!

Hello guys,

 

I think that the title explains the question very well. Is there any function in MAPLE that allows me to generate N random numbers considering a mean value, standard deviation and a percentile?

 

Thank you,

f:=piecewise(x>0,1+x,x=0,2,x<0,1+x^2)

in my work i must use some parts of this piecewise function.

But i don't know how can i call the part that i will use.

How can i do that ?

Thanks for help

 

Hi,

I have a code compute some function : 

         alpha1:(n, m,1) -> (n + 1) (int(K(|m h - y|), y = n h .. (n + 1) h))

              int(K(|m h - y|) y, y = n h .. (n + 1) h)
            - -----------------------------------------
                                  h                    
         alpha2:  (n, m,2) -> -n (int(K(|m h - y|), y = n h .. (n + 1) h))

                int(K(|m h - y|) y, y = n h .. (n + 1) h)
              + -----------------------------------------
                                    h                    
and  I have a Matrix "MatA" .

 

 

My aim, when I give the value of the Kernel K used in alpha1, and alpha2, like K(x,y)=ln|x-y| , I want a numerci Matrix.

How can I do it.

Many thinks.

Fred.mw

 

assume f and g are unknown

and assume solve(f, x) = solve(g, x)

f -> a

g -> a

b -> f

b ->g

if assume f = (x+1)*(x+2), g = (x+2)*(x+3)

and a = (x+1)*(x+2)*(x+3)

would like to find map from (x+1)*(x+2) to (x+1)*(x+2)*(x+3)

 

is it the solution subs(x=(x+1)*(x+2),(x+1)*(x+2)*(x+3)) by composition?

 

subs(x=(x+1)*(x+2),(x+1)*(x+2)*(x+3))


subs(x=1, (x+1)*(x+2));
subs(x=2, (x+1)*(x+2));
subs(x=1, (x+1)*(x+2)*(x+3));
subs(x=2, (x+1)*(x+2)*(x+3));


6 -> 24
12 -> 60

subs(x=1, ((x+1)*(x+2)+1)*((x+1)*(x+2)+2)*((x+1)*(x+2)+3)); # not 24
subs(x=2, ((x+1)*(x+2)+1)*((x+1)*(x+2)+2)*((x+1)*(x+2)+3)); # not 60

it seems composition is wrong

more difficult and general case should be

f(x,t)  -> a(x,t)

g(x,t)  -> a(x,t)

b(x,t) -> f(x,t)

b(x,t) -> g(x,t)

 

solve(f(x,t), x) = solve(g(x,t), x) = in terms of t

 

 

R dJ(t)/dt+J(t)/C=f(t)

where f(t) is a driving electromotive force. Use the fourier transform to analyze this equation as follows.

 

 

Find the transfer function G(alpha)  then find g(t) .

 Thanks ....

Hi,

I have a finite difference method used to solve my problem.  My unknown function u(x,y,t) is found using the finite difference method, i would like to plot the solution for different time, and I can do this...

 

 

Only I want to make an animation in time if it's possible, and someone can help me.

Sol_animation.mw

 

Thnaks for helping me.

 

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