Items tagged with function function Tagged Items Feed

Hi,

I have a 4-D function that I have found an analytic expression for in Maple, but I want to generate a numerical 4-D array, which I can export for use in Matlab. However, I don't think I'm using a very good solution, because it is extremely slow (several minutes for even 10x10x10x10 elements). My code is

NumRange:=10:
NumElements:=10:
dx:=2*NumRange/(NumElements-1):
A:=Array(1..NumElements,1..NumElements,1..NumElements,1..NumElements,[seq([seq([seq([seq(evalf(rho(ws1,ws2,ws1p,ws2p)),ws2p=-NumRange..NumRange,dx)],ws1p=-NumRange..NumRange,dx)],ws2=-NumRange..NumRange,dx)] , ws1=-NumRange..NumRange,dx)],datatype=float);

Rho is an exponential with 10 terms in the exponents.

I also tried using four for-loops but that was even slower!

Thanks for any input

Hello Maplers, i have encountered a little annoyance with Maple, that i would like to ask, whether it can be solved. 

 

It's when i try to define a function, like f(x)=2x and try to define it with a command f(x):=2x, a pop-up box comes up, asking me whether i'd like to use a 'function definition', or 'remember table assignment', and i would like to make Maple remember my choice that i want a function. 

 

I know i can write it like f:=x->2x, but i hate to look at that, to be frankly..

 

So, is there any way to solve this?

 

so we have to Write a function that diagonalises a complex (2x2) matrix if possible,  

we need the argument to be a (2x2) matrix say A.   and we need the return value to be a list [a1 ;a2 ;b1;b2] of two complex numbers followed by two 2-vectors such that {b1,b2} is a basis for C^2 and so that  

Ab1 =a1b1 , Ab2=a2b2  if these exist. if not then the function should return an empty list []

also, the thing is that we're not allowed to load any maple packages, we have to do it by hand :'(

thanks <3

 

Dear Maple users,

 

i have a set of 2 Lines: L1 (determined by the intersection of plane x + y -1=0 and plane x - z - 1=0), 

L2 ( intersection of plane x + y-7=0 and plane x-y+1 = 0 ).

which functions or commands of maple should I use "visualize" those 2 lines L1 and L2?

 

thanks for your help,

 

JJ

I am trying to create a procedure that can solve integrals using the Composite Simpson's 3/8 rule. However when I test my procedure against maple's ApproximateInt I am getting the wrong results.

Here is my attempt:

restart;


f:= x -> exp(x)*sin(4*x); # function I am using

simp := proc(a, b, n)
  local h, sum, i, single:
  h := (b-a)/n:
  sum := 0:
  single := (3*h/8) * (f(a) + f(b)): # this is the end points
    for i from a+h by h to b-h do
       sum := sum + (3*h/8) * (3*f(i)):
    end do:
print(evalf(sum + single));
end proc:


simp(0,1,12);
                                                                                0.6224486445
evalf(Student:-Calculus1:-ApproximateInt(f(x), 0..1, method = simpson[3/8], partition=12));

                                                                                0.5323516717

 

As you can see my answer is not very close to the answer given by Maple. I am not sure why my procedure simp is wrong.

Hi there,

I'm quite new to Maple so please forgive me! I have a system of partial differential equations I'm trying to solve in Maple as such below 

 

df/dt = f(1-f) - f * h

dg/dt = g(1-g) * Gradient(1-f * gradient(g))

dh/dt = (g - h) + Laplacian(h),

where f,g,h are functions of space and time (i.e. f(x,y,z,t)). I guess my first question is - is this possible in Maple to evaluate? (I'm currently unsure on ICs as I'm figuring it out from the model - it's a model for cancer growth I'm trying to evaluate but have a rough idea of what I'd use).

If it is possible, can you please share how I'd write this? Everytime I've tried I seem to be failing to define anything properly, so your expertise would be greatly appreciated!

and  x have range=(0 to 2),the y have range = (2,3),follow when the x=(3 to 4),so the y=(3 to -3) how to implement the title's function 

still the x and y have variability value and variability number

 

is it Morphism?...

February 13 2014 rit 200

i assign 

seta := [x+1, x^2]

setb := [x^3, 2*x+5]

 

does morphism mean that

i use card_prod

to get

(x+1, x^3)

(x+1, 2*x+5)

(x^2, x^3)

(x^2, 2*x+5)

such that i composite each of 4 sets still satisfy F(f o g) = f o g

example

subs(x=x^3, x+1)

How to find inverse function of a multivariable function

for example

f := x^2 + y + z^3

f := x^2 + y^3

How to test  associativity?

How to determine which of below has associativity?

 

The definition x*(y*z) = (x*y)*z.

asso := -(1/2)*(x+y+sqrt(x^2+2*x*y-3*y^2))/y;
asso := -(1/4)*(2*x+y+sqrt(4*x^2+4*x*y-7*y^2))/y;
asso := -(2*x+y)/(y+z);
asso := (1/2)*(-y-z+sqrt(y^2-2*z*y+z^2-8*z*x))/z;
asso := (1/2)*(-z+sqrt(z^2-4*z*x-4*z*y))/z;

what is the difference between endomorphism and identity map?

http://mathfaculty.fullerton.edu/mathews//n2003/hornermod.html

i find a program above, 

if no general method, how about specific to convert it

if have general method, how is it?

assume f:= x^2*y^3/z^7

 

would like to get [x^2, y^3, z^(-7)]

Hi

I have been trying to find a way to present results from engineering calcs to 2 decimal places (i.e.: 350.50) but the round function rounds to the nearest integer. Is there a specific statement for specifying the number of decimal places you want to present some results?

thanks

Hello

I calculated following two expressions, x1,and x2.

x1:=map(f,a+b);

x2:=map(f,y=a+b);

 

The results of these are

f(a) + f(b)

f(y) = f(a + b)

for each. And, I can understand the logic of this.

 

If I want to derive the result of x2 as f(y)=f(a)+f(b), how should I do about x2?

Isn't there other way than to write

map(f, lhs(x2))=map(f,rhs(x2))

?

Please teach me this.

Thank you in advance.

Taro

 

 

2 3 4 5 6 7 8 Last Page 4 of 21