I am trying to create a procedure that can solve integrals using the Composite Simpson's 3/8 rule. However when I test my procedure against maple's ApproximateInt I am getting the wrong results.

Here is my attempt:

restart;

f:= x -> exp(x)*sin(4*x); # function I am using

simp := proc(a, b, n) local h, sum, i, single: h := (b-a)/n: sum := 0: single := (3*h/8) * (f(a) + f(b)): # this is the end points for i from a+h by h to b-h do sum := sum + (3*h/8) * (3*f(i)): end do: print(evalf(sum + single));end proc:

simp(0,1,12); 0.6224486445evalf(Student:-Calculus1:-ApproximateInt(f(x), 0..1, method = simpson[3/8], partition=12));

0.5323516717

As you can see my answer is not very close to the answer given by Maple. I am not sure why my procedure simp is wrong.

Hi there,

I'm quite new to Maple so please forgive me! I have a system of partial differential equations I'm trying to solve in Maple as such below

df/dt = f(1-f) - f * h

dg/dt = g(1-g) * Gradient(1-f * gradient(g))

dh/dt = (g - h) + Laplacian(h),

where f,g,h are functions of space and time (i.e. f(x,y,z,t)). I guess my first question is - is this possible in Maple to evaluate? (I'm currently unsure on ICs as I'm figuring it out from the model - it's a model for cancer growth I'm trying to evaluate but have a rough idea of what I'd use).

If it is possible, can you please share how I'd write this? Everytime I've tried I seem to be failing to define anything properly, so your expertise would be greatly appreciated!

and x have range=(0 to 2),the y have range = (2,3),follow when the x=(3 to 4),so the y=(3 to -3) how to implement the title's function

still the x and y have variability value and variability number

i assign

seta := [x+1, x^2]

setb := [x^3, 2*x+5]

does morphism mean that

i use card_prod

to get

(x+1, x^3)

(x+1, 2*x+5)

(x^2, x^3)

(x^2, 2*x+5)

such that i composite each of 4 sets still satisfy F(f o g) = f o g

example

subs(x=x^3, x+1)

How to find inverse function of a multivariable function

for example

f := x^2 + y + z^3

f := x^2 + y^3

How to test associativity?

How to determine which of below has associativity?

The definition x*(y*z) = (x*y)*z.

asso := -(1/2)*(x+y+sqrt(x^2+2*x*y-3*y^2))/y;asso := -(1/4)*(2*x+y+sqrt(4*x^2+4*x*y-7*y^2))/y;asso := -(2*x+y)/(y+z);asso := (1/2)*(-y-z+sqrt(y^2-2*z*y+z^2-8*z*x))/z;asso := (1/2)*(-z+sqrt(z^2-4*z*x-4*z*y))/z;

what is the difference between endomorphism and identity map?

http://mathfaculty.fullerton.edu/mathews//n2003/hornermod.html

i find a program above,

if no general method, how about specific to convert it

if have general method, how is it?

assume f:= x^2*y^3/z^7

would like to get [x^2, y^3, z^(-7)]

Hi

I have been trying to find a way to present results from engineering calcs to 2 decimal places (i.e.: 350.50) but the round function rounds to the nearest integer. Is there a specific statement for specifying the number of decimal places you want to present some results?

thanks

Hello

I calculated following two expressions, x1,and x2.

x1:=map(f,a+b);

x2:=map(f,y=a+b);

The results of these are

f(a) + f(b)

f(y) = f(a + b)

for each. And, I can understand the logic of this.

If I want to derive the result of x2 as f(y)=f(a)+f(b), how should I do about x2?

Isn't there other way than to write

map(f, lhs(x2))=map(f,rhs(x2))

?

Please teach me this.

Thank you in advance.

Taro

Hi everyone,

I have a very complicated function y with only one independent variable x, and want to fit or approximate it by a simpler function, say polynomial. Many books or maple reference seem to tell how to fit a set of data instead of a given function. But the argument x in the function is assumed to be continuous other than discrete, so I don't know whether it is possible to express datax in form of x's range such as 0..1, and express datay in form of the function. After that , maybe I can fit the two created data sets by a polynomial function.

Or, does anyone have a better or more direct way to do the fitting linking two fucntions?

I am appreciated for your help.

Best,

GOODLUCK

hello. before I used Mapple 15. But then I`ve run Mapple 16 and now I`ve a problem. I can`t use this program. I open the program, everthing is in the rule, but if I want to write any mathemathical function, or a letter, such as- x or x+2, the program does`t give any reaction. program only gives reaction the numbers.

Please, help me. (my english isn`t very good, and I don`t know I`ve explained my opinion).

Hi all,

I am quite new to maple. Thanks for your help in advance.

Could I define a general function f of a single variable x, f(x), without specifying its explicit form? I know it is simple to define functions of specific forms, e.g., f(x)=2*x (In maple: f:=x->2*x). I try to define a function without knowing its form, e.g., f:=x->f(x), expecting maple return f(y) if I type >>f(y). But this does not work (Maple says:

Error, (in temp) too many levels of recursion).

Is it possible to define a general function f(x) without specific form in maple? Thank you again.

Hello,my question may be simple but I don't find the answer in any help guide.when I define a function I cannot use a linearalgebra expression such as Trace.Here is an example of what I would like to do:

If anyone can help me...Thank you

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