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I have a finite difference method used to solve my problem.  My unknown function u(x,y,t) is found using the finite difference method, i would like to plot the solution for different time, and I can do this...



Only I want to make an animation in time if it's possible, and someone can help me.


Thnaks for helping me.


Hi all.

Assume that we have partitioned [0,a], into N equidistant subintervals and in each subinterval we have M sets of poly nomials of the following form:

where Tm(t)=tm( namely Taylor Series) and tf is a(final point)
for Example with N=4, M=3 we have:

now we want to approximate a function, asy f(t), in this interval with following form:

How can we do this with maple????

how can we find the ci's?????

Thanks a lot

Mahmood   Dadkhah

Ph.D Candidate

Applied Mathematics Department

has anybody any idea for this?  been stuck on it for a while now.


let f0 € V be any given function and define a sequence (fn)n€(No) of functions fn € V by 

f:= f0 and fn+1 =Af for all n € (N0)        #A could be the average of the four surrounding points to (i,j) or it could be an N x N matrix with spectral radius less than 1.  not entirely sure. I dont know what it should be but im sure one of you guys know.

prove that this sequence converges pointwise,

 i.e that for all i,j €  [N] x [N], foo(i,j) := limn-> oo fn(i,j) exists.   and that Δfoo=0 


it  says to be in the notation of ("")  but it doesnt matter if its not.  I can adapt to what its meant to be if I can get any way to prove it

Thanks in advance.



Plz help me friends ...

I gave this function ...


i wanna extract coeffitions from this function ... for example what is the coeffition of phi(X)*psi(x)?

i used coeff ... but it had an error ..

unable compute coeff ...

i used collect ... but it had an error

what am i doing with this problem?




I open a discussion about convolution and Fourier coefficients in Fourier series.


I have a function defined by f(x)=0 if x in [-Pi,0[ and 1 if x in [0,Pi[, of course f 2*Pi periodic function.

My goal is compare the Fourier coefficients of f*f ( * convolution ) and The Fourier Coefficient of f.


Thanks for your help.




the question


I already finished part a, my question is how do i define the function g with the variable k being any real value so that maple will find <f,g> = 0 (using the inner product defined)?


Hi all;

Hope all of you  be in good health

I want to construct a special function b_{nm}(t) like:

with piecewise command i did it but the result is incorrect.

any one can help me to do it?

Best wishes


Mahmood   Dadkhah

Ph.D Candidate

Applied Mathematics Department


I open a new subject about Fredholm Integral equation. My code work correctly.

But, I need some modification to get a nice display of the matrix found using
MatA,Vectb := GenerateMatrix(convert(sys3,list),Sol_phi);

such as Sol_phi is my solution that I want to find.

I introduced two function alpha1 and alpha2 in the code  see Equation (9) can I write all the coeficient of my matrix using the two function alpha[1] and alpha[2], it's better to see and read the matrix form.


I have to simplify a piecewise function and Maple gets a more complicated solution than needed.

I don't know how to handle this kind of problems with Maple?
I don't understand why Maple doesn't see this?
Am I doing something wrong?

Thanks in advance for your help / advice.

# the code of my example
# Make a dimensionless function:
# -    Mf(x):= Mf(xi)*F*L
# -    variable ξ  ( xi:=x/L )
# F is the Force and L is the Length of the beam:
Mf(xi):=simplify(Mf(xi)) assuming F>0,L>0;
print("When I simplify this function by hand it will be");

Hi all,

I will use the following dummy example.

with function,f



and a complicated term, myterm



'if' i have some previous knowledge, or know a bit of the term, i can find the structure by doing this

repar:=[f(1,1),f(2,2),f(3,4)];  # Or with more f(xid,yid) terms

simplify(myterm,{tmp});          # This is fine, gives me what i want


But, can we go further, and more 'obvious'


Given the fucntion f, same as before, and the same 'myterm'

can I have this
iwant:=(f(3,4)+f(2,2))*f(1,1);  # as a result, straightforward

so I dont have to go back to 'repar' and find that the terms exactly are.




Hi say I have the vector V1.


and function myfun.


how do i use it as the input to the function my fun, by taking away each element in turn?
myfun(V1[2..]);              # 1st element removed
myfun(V1[[1,3..]]);         # 2nd element removed
myfun(V1[[1,2,4..]]);      # 3rd element removed

and so go

is there a more efficient way?


Many thanks,

This has been buggin me all day, but if i define a variable with an expresion say "a:=3 x+5" and i then want to assign this expression to a function like so "f:=x->a". if i then call f(7), maple return with "3 x+5" so just returning the value of a without substituting x with 7.

Is there any way in which i can define a function this way?

I am new user of Maple. I have an expression like f(x,y)/g(x,y) and I want to have Maple name f(x,y) as something simple like "h" so that later equations write h/g(x,y) instead of the complete f(x,y)/g(x,y), and also to be able to simplify other equations in terms of h.

For example, a=(x+1)(y-5)^2/(x+y-3). Can I get Maple to let h=(x+1)(y-5)^2, so that I get h/(x+y-3) when I ask for a?

Sorry if this question is basic (and my math terminology incorrect), but I have been trying for a while.

Hi all

In matlab software we have a command namely fmincon which minimizes any linear/nonlinear algebric equations subject to linear/nonlinear constraints.

Now my question is that: what is the same command in maple?or how can we minimize linear/nonlinear function subject to linear/nonlinear constraints in maple?

thanks a lot

Mahmood   Dadkhah

Ph.D Candidate

Applied Mathematics Department

Hi all,
I need to find mina(w) then a=-1,0,1 and

w := piecewise((x-a)/t <= -10, 202*a-200*x-(202001/101)*t, (x-a)/t <= -910/101, 3*a-x-(1011/101)*t, (x-a)/t <= 910/101, 2*a-t, (x-a)/t <= 10, a+x-(1011/101)*t, 10 < (x-a)/t, -198*a+200*x-(202001/101)*t)

Also need to plot it, i think it should look like this 





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