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hello,

I'm trying to solve the equation of a form like,

diff(eta(tau), tau, tau)+(8/(4*tau^2+1)-32/(4*tau^2+1)^2)*eta(tau) = 0,

when I'm doing solve DE, I get a solution as:=

eta(tau) = _C1*sqrt(4*tau^2+1)*LegendreP((1/2*I)*sqrt(7)-1/2, I*sqrt(7), (2*I)*tau)+_C2*sqrt(4*tau^2+1)*LegendreQ((1/2*I)*sqrt(7)-1/2, I*sqrt(7), (2*I)*tau

which is combination of Legendre Polynomials with imaginary arguments,May I change this form,

How can I plot this solution on real plane, as this is imaginary,

Is the only option remaining NUMERIC PLOT??

Recently I was presented with some code that had a seq command that used i as the index variable. While this code had been used in a number of applicaitons, it was now giving trouble.

seq( i^2, i=1..10 );
Error, illegal use of an object as a name

After a stroke of fortune it was discovered that the problem was that Maple's imaginary unit had been changed from I to i. Given that this change was made, the error message now made sense.

How do I use the letter I as a variable, not an imaginary number (the square root of -1) ?

I am trying to solve two differential equations numericaly:

I am trying to get the real and imaginary part of a complex expression but it appears that the evalc(Im(F)) does not work. My guess is that i have to manipulate the expression before i use the evalc, but the simplify command for example did not give a result either. My funstion is F:=1+2*zs*I-w^2/ws^2-w^2/ws^2*ks*(1+2*zs*I)*(K3*(1+2*z3*I)-H*K2(1+2*z2*I)+H*(H*K1*(1+2*z1*I)-K2*(1+2*z2*I)))/(K1*(1+2*z1*I)*K3*(1+2*z3*I)-K2^2*(1+2*z2*I)^2);

As you see I have imaginary I...

consider:

assume(kf1>0,kf2>kf1,q>kf1,q<kf2);

1/2*q*Pi^2*(ln(kf1)*kf1^2-ln(kf2)*kf2^2-ln(q)*kf2^2-arctanh(1/(kf1^2+q^2)^2*(kf1^4+q^4-6*q^2*kf1^2))*kf1^2+ln(q)*kf1^2-ln(2)*kf1^2+ln(-kf1+q)*kf1^2+ln(kf1^2-q^2)*q^2-ln(kf1-q)*q^2+2*kf1^2-2*q^2-1/2*ln((q-kf2)^2)*kf2^2+3*ln(kf2+q)*kf2^2+4*q*kf2-3*q^2*ln(kf2+q)+ln(2)*kf2^2+arctanh((kf2^4+q^4-6*kf2^2*q^2)/(kf2^2+q^2)^2)*kf2^2+ln(-q+kf2)*q^2-ln(kf2^2-q^2)*q^2-4*q*kf1-3*ln(q+kf1)*kf1^2+2*arctanh((-kf1^2+q^2...

It is pretty easy to get the principal value of the logarithm of the imaginary unit, say. Is it just as easy to get all values of the logarithm of the imaginary unit?

Forgive me if this is a duplicate, but I couldn't find a similar questions.

Thanks!

On the usenet newsgroup sci.math.symbolic Prof. Richard Fateman posted a question (or here) recently about what mechanisms a math application could use to handle the situation of negligible imaginary parts of computed data when plotting.

An example could...

Hello All,

How may I have Maple accept and output J, rather than I, for imaginary numbers?

Thanks,

Dave

 

My contour of integration is a semi circle whose diameter rests on the imaginary axis from -ri to ri.  The arc of radius r is on the positive real axis going from -ri to ri.  On the curve I want to have directional arrows indicating that I am traversing this contour in the positive direction.  How do I create this figure in MAPLE?

Hi,

I am trying to simplify the expression s as given below. (I am not sure why it comes up with all the vector caclulus notation in it but it should display okay when you enter it)

Because of the presence of the exponential imaginary fucntions I thought evalc might be useful but when I use it I get a huge expression with csgn appearing in it. To my knowledge csgn appears when assumptions are not correctly specified - is this so? I can't see any assumption...

Hi,

 

I'm trying to model a magnetic field with maple.

In order to do that, I compute a (huge) sum and integrals of real and posive numbers.

The problem is that for some points, when I compute the norm of this field I get an imaginary number with a very small imaginary part (egs -2, 27293.1844462+1.42305652280*10^(-84)*I ).

 

How can I get rid of it?

thx in advance 

Dear Sir / Madam,

Would you recommend me how to isolate the real and imaginary part and simplify the equation A? Maple cannot evaluate this equation to numeric value...

A := evalf(sqrt((Re(B))^2 + (Im(B))^2));
A := evalf(abs(B));

are not working.

I have attached my equation function.txt

Im quite new to Maple, how do I extract the imaginary part of sqrt(I)? Im sure it is just Im(sqrt(I)) and Re(sqrt(I)), but the Im part just returns the real part againg for some reason, does anyone know what I am doing wrong here?

 

I'm using maple 9 by the way

>sqrt(I);

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