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Hi, as the title says I am animating an implicitplot and want a different color for each curve left by the trace. I realize it may be easier to build plot structures using seq and display(..,insequence=false) but I thought I should learn more Maple ha ha. Plus  it seems easier to implement.

 Forgot to say I use Maple 15

For equation sol[2][1]=constant A,

 

 

> animate(implicitplot, [sol[2][1] = A, x = -6 .. 15, y = -15 .. 15, numpoints = 10^5], A = -10 .. 10, trace = 2, frames = 20);

 

 

I'm taking calculus and my professor introduced us to maple software. The professor asked us to plot the families of curves for this orthogonal equation:

dy/dx = (x^2) - (2y^2) - C = 0

This is what I had so far:

 

restart;

with(DEtools):

with(plots):

 

Function:=unapply(simplify(x^2-2y^2-C),(x,y)):

'Function'(x,y) = Function(x,y);

plotFunction:=C->implicitplot(eval(F(x,y),a=C),x=-5..5,y=5..5,scaling=constrained):

plot1:=display(seq(plotFunction(a),a=-5..5)):

display(plot1);

 

This is only display one family. How do I code for it plot the other families?

(The graph should look like curves converging from left, top and right sides toward to the origin of the axes)

Please help.

I used implitplot to plot solutions to some (tricky) equations in 2 variables, of the form implicitplot([f(x,y)=0]).  Now I have a (tricky) change of parameterization G:R^2->R^2 of the form G(x,y)=(g(x,y),h(x,y)). I'd like to plot the image of the solution set of f(x,y)=0 under the map G. Of course, if I could invert G I'd implicitplot           G^(-1)(f(x,y))=0, but the functions I have dont lend themselves to this.

 

Presumably MAPLE stores the points it plots somewhere, and I should be able to apply G to this set of points. But I don't know how to approach this. Anybody know? 

Hello there,

 

I have some troubles with plotting implicit functions , aswell with plotting polar ones.

When I ask the plot of my function it's not ''smooth'' , it has edgdes everywhere that aren't suposed to be there (I think).

 

These are 2 examples:

K:=x^2*(x^2+y^2)=a^2*y^2;a:=1;
implicitplot(K,x=-2..3,y=-6..6,colour=red);

 

Both curbes

K:=(x^2+y^2)^3=a^3*x*(x^2*3*y^2);

implicitplot(K,x=-6..6,y=-6..6,colour=red);

 

Can somebody help me out on how to draw them smoothly?

Maybe I have to change settings?

 

Thanks alot!

 

Thanks

i want to plot the region D={(x,y)|0<=x<=1,0<=y<=1-x} in a 2d plot. how to i do this in the most possible way?

 

i know im supposed to use with(plots) and then implicitplot() but i cant seem to get it right...

 

 

any help is appreciated :)

Hello!

I need help plotting the volume of revolution generated by the curves x=0 and x=(2*y^3)-y^4 around the y=-2 axis. I tried using parametric equations, x(t)= (2*t^3)-t^4 and y(t)=t for t between 0..2, and the VolumeofRevolution command with StudentCalculus 1. To be more precise, I used:

VolumeOfRevolution(2*t^3-t^4,t, t = 0 .. 2, output = plot, axis = horizontal, distancefromaxis = -2);

However, the volume I'm getting is not the one I'm looking for....

Hello Folks:

I'm trying to generate a plot of a procedure that uses fsolve and I get the following error message:

> implicitplot(IC(2, x, y, 1, 1), .1 .. .9, -1 .. 1, filled = true, numpoints = 10);
Error, (in fsolve) x is in the equation, and is not solved for

It seems that Maple is passing x to the procedure IC and not the numerical value of x.

I tried, without success,  to delay the evaluation as suggested here

 

Hi,

I obtain  curve pH = f(Vb) with following code

 

restart;with(plots);

 Vtot := V0+Vb+Vind;h := 10^(-ph);C0 := 10^(-2);Cind := .83;Vind := 0.1e-1;V0 := 10;Ka1 := 10^(-4.8);Ka2 := 10^(-9);Cb := 0.1e-1;Kaind := 10^(-8);

eq := h+Cb*Vb/Vtot = 10^(-14)/h+C0*V0/(Vtot*(1+h/Ka1))+Cind*Vind/(Vtot*(1+h/Kaind));

 implicitplot(eq, Vb = 0 .. 40, gridrefine = 3, ph...

Dif_Out_plot.mwWhy this difference in the results of the graphics?There are differences between the command smartplot and the command smartplot implicitplot, to display the graph of the function.Following the line of site: web

I need to view in log scale the y-axis of the plot I get using the command implicitplot. Any solution?

Francesco

How to plot x versus theta of the following implicit function

sin(theta)-2*sin(2*x-theta+(1/3)*Pi)/sin(x+(1/3)*Pi-theta)=0

where x is the implicit function of theta

now how can I plot the relationship between x and theta(condition:-Pi<theta<Pi,-Pi<x<Pi)

Hello,

I need to plot M vs phi from the following ode. For this I am using implicitplot but unfortunately

I am getting empty plot. Please guide me through this issue.

Thanks 

eq1 := 1/(1-phi)^2.5/(1+4117/783*phi)*diff(f(eta),`$`(eta,3))+1/2*f(eta)*diff(f(eta),`$`(eta,2))

+M*(1-diff(f(eta),eta)) = 0;

bc:=f(0)=0,D(f)(0)=beta/(1-phi)^(2.5)*(D@D)(f)(0),D(f)(N)=1;

respar:=dsolve({eq1,f(0)=0,D(f)(0)=beta/(1-phi)^(2.5)*(D@D)(f)(0)},numeric,

Hello, 

I am trying to analyse a nonlinear ode. To see the behaviour,

I am using implicit plot (suggested by @Preben Alsholm).

The problem is that every time I need to search for the value of N

(=infinity) to have some sort of graph (needed for analysis).

The other thing is, if we have an output of the implicitplot, How we can be sure

that it is the correct one?

Two variants...

September 24 2012 Kitonum 2930

My answer in this topic does not load for some reason, so I had to create this post.

Variant of solution:

I want to graph the portion of the plane 2x + 3y + z = 6 that are located in the first octant of a xyz coordinate system. The following implicitplot3d should in principle do it:

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