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How to simplify this result in order it returns the correct answer i.e : sqrt(Pi)/2*exp(-2*abs(x))  -infinity<x<infinity.

int(exp(-t^2-x^2*t^-2), t = 0 .. infinity);

print(`output redirected...`); # input placeholder
1 |
- |
2 \
            /     /                    / 2            \
  1   (1/2) |     |                    |t  + csgn(x) x|
- - Pi      |limit|exp(4 csgn(x) x) erf|--------------|
  2         \     \                    \      t       /

                           /  2            \                  \\
                           |-t  + csgn(x) x|                  ||
   - exp(4 csgn(x) x) - erf|---------------| + 1, t = 0, right||
                           \       t       /                  //

   + Pi     | exp(-2 csgn(x) x)


It comes from Peirces's Tables No 510.

I have notice that Maple's integrator is very efficient.It is one  integral from these tables that Maple can't handle directly.

To be contined later.



I have some X-Y data, and I would like to calculate a definate integral of the data. In this case x_data and y_data are vectors.

I tried this method.


But when I try to calculate an integral like this, I get an error.

int(y, x0..x1)

Error, (in int) operator y cannot be evaluated at one variable.

What is this error trying to tell me? I have tested by function y for values x1 and x2. My data is smooth and includes x1 and x2. I have no reason to believe that the function cannot be evaluated for any value of x. 

Is there another (better) way to do what I want? This is a part of a large worksheet that reads data from an excel file, and I don't know how to reduce the worksheet for only this problem.


The following integral
f := u-> int(-1/(x*sqrt(-1+u^2*(x+1)^2*x^2)), x = (1/2)*(-u-sqrt(u^2-4*u))/u .. (1/2)*(-u+sqrt(u^2-4*u))/u);
arised in an applied research. I was asked about its properties:
plot on RealRange(4,infinity), limit(f(u),u=4,right), limit(f(u),u=infinity).
Unfortunately, I lost a file. As far as I remember it, I have had a problem with
the latter one only:

limit(f(u), u = infinity);

MultiSeries:-limit(f(u), u = infinity);

asympt(f(u), u, 2);

Error, (in asympt) unable to compute series

Hope my colleagues will make progress with it. The assumed value is Pi/2.

I would like integrate and plot the following double integral:


I enclosed


I'm trying to define a function by a definite integral. For this, first we define the following  procedure



and the map


So, for a given m, my desired  "function" should be fun(curva(m,t)). The problem here, is that this function not work because, for instance, for m=2 the command fun(curva(2,t)) returns the below expession, which i think is wrong (where is the expression on "sin" or "cos(2*Pi*t)" ???)

Somebody can help me??



LE_EQ.mwWhat is problem with this programme,why it does'nt calculate the values but only shows the solution with integral sign instead of calculating it, there is also arising a problem in plots

I'm trying to determine that f(x) = (a/2)*e^(-a|x|) is a pdf for which I have tried to calcuate the integral from -infinity to +infinity but I am no getting a result that converges(even the wolfram alpha widget said the integral doesn't converge). How do I correcly implement this?

why the the software can't solve the integral like ∫xdlnx?

Thanks in advance for your help.

hi.please help me for solve this integral


print(`output redirected...`); # input placeholder
evalf(Int(diff(Phi(x, theta, z, t), theta, theta), z = -(1/2)*h .. (1/2)*h));
print(`output redirected...`); # input placeholder
| / / /3 \\
| |(Phi[0]) . |sin|- Pi (x - 6)|| . (cos(theta))
| \ \ \2 //

cos(2 Pi z)| . (sin(omega t)) dz


How to calculate the integral

(symbolically or/and numerically) with Maple?


I would like to pay attention to an article " Sums and Integrals: The Swiss analysis knife " by Bill Casselman, where the Euler-Maclaurin formula is discussed.  It should be noted all that matter is implemented in Maple through the commands bernoulli and eulermac. For example,


eulermac(1/x, x);


eulermac(sin(x), x, 6);

BTW, as far as I know it, this boring stuff is substantially used in modern physics. The one is considered in

Ronald Graham, Donald E. Knuth, and Oren Patashnik, Concrete mathematics, Addison-Wesley, 1989.

The last chapter is concerned with the Euler-MacLaurin formula.


Hi everyone,

I have a great problem with the evaluation of following definite integral

> restart;

> int((t-x)^2)/(1+2t+(1/2)t^2-ln(t^2+2t+2)t-ln(t^2+2t+2)+arctan(1+t)t^2+2arctan(1+t)t+ln(2)t+ln(2)-(pi/4)t^2-(pi/2)t)^2,t=0..x)

I have tried different classical commands but Maple doesn't give an answer. Probably, it's just a silly fault.

Does anyone knows how to solve it?


Hi all,


I wonder if any of you guys can figure out why this integral is taking more than 2 hours to return a result??

I had similar problems in the past that were fixed creating a procedure, changing the solver and in case of trigonometric functions, changing the argument from float to rational number. 

Here it





ms := (1.141448075+9.645873109*10^(-11)*I)*(MeijerG([[], []], [[1/4, 1/4], [1/2, 0]], .3956862293*(-.70*x+1)^4)+(2.148399968-2.148399963*I)*MeijerG([[], []], [[1/4], [1/2, 1/4, 0]], -.3956862293*(-.70*x+1)^4)+(-12.48809431-3.188863063*10^(-9)*I)*MeijerG([[], []], [[0], [1/2, 1/4, 1/4]], -.3956862293*(-.70*x+1)^4)+(4.061500400*10^(-10)-8.649913391*I)*MeijerG([[], []], [[1/2], [1/4, 1/4, 0]], -.3956862293*(-.70*x+1)^4));

b := .7;



"H3p:=proc(ms,b) local Hcub;  Hcub := evalf(Int(diff((diff(ms, x))*(int((-x*b+1)*(int((ms')^2, x = 0 .. x)), x = 1 .. x)), x)*ms, x=0..1,method = _d01ajc)): return Hcub; end proc:   "



st := time(); ``*H3p(ms, b); time()-st




Hi, I'm currently from Mathematica and it starts to disappouint me because it cannot do what I can.

Can somebody try to calculate undefinite integral in Maple for x variable. a and b are parameters.


If Maple can do that then I would switch to Maple comunity.



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