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hi everyone..i would like to ask,why do we need to type in (101-100λ) in our maple program..why do we need the continuation..thanks in advance for answering..

I'm currently working on building a Grid Layout for a project, and I'm having trouble coding in the RunWindow and GetFile elements into buttons under the grid layout. I've gone through the overviews and examples for them, but had no luck. I'm using Maple 2016.1 for OS X.

Additionally, the structure of the code is slightly different as to how many of the example worksheets structure their Grid Layout code, since the code originated from a Maplet Builder file. I.e. in the example worksheets they would follow as:

maplet := Maplet('onstartup' = 'Action1', 'reference' = 'Maplet1',
         BoxLayout('background' = "#D6D3CE", 'border' = 'false', 'halign' = 'center', 'inset' = '5', 'reference' = 'BoxLayout1', 'valign' = 'center', 'vertical' = 'false', 'visible' = 'true',
                       BoxColumn( BoxCell('hscroll' = 'never', 'value' = 'Button1', 'vscroll' = 'never'),
         GridLayout('background' = "#D6D3CE", 'border' = 'false','halign'='center','inset'='5', 'reference' = 'GridLayout1', 'valign' = 'center', 'visible' = 'true',
                   GridRow('valign' = 'top', GridCell('height' = '1', 'hscroll' = 'never', 'value' = 'BoxLayout1', 'vscroll' = 'never', 'width' = '1' ))),
         Window('layout'= 'GridLayout1', 'reference' = 'W1', 'resizable' = 'true', 'title' = "Maplet"),
          Action('reference' = 'Action1', RunWindow('window'= 'W1'))

However the structure for the code I am working with has action at the very start of the code, follwed by the the code for the buttons then layouts/window.  E.g. (the code has been shortened)

with (Maplets[Elements]):
maplet :=
Maplet('onstartup'='Action1','reference'='Maplet1',
Action('reference'='clickButton1'),
Action('reference'='clickButton9',
Evaluate('function'='plot3d(x^2*cos(y),x = -1 .. 1,y = -2*Pi .. 2*Pi)','target'='Plotter1','waitforresult'='true')),
Action('reference'='clickButton11'),
Action('reference'='clickButton12'),
Action('reference'='clickButton10'),
Button('background'="#D6D3CE",'caption'="Insert Molecular Geometry",'enabled'='true','foreground'="#000000",'onclick'='clickButton1','reference'='Button1','visible'='true'),

....

BoxLayout('background'="#D6D3CE",'border'='false','halign'='center','inset'='5','reference'='BoxLayout1','valign'='center','vertical'='false','visible'='true',
BoxColumn(
BoxCell('hscroll'='never','value'='Button1','vscroll'='never'),
BoxCell('hscroll'='never','value'='BoxLayout2','vscroll'='never'),
BoxCell('hscroll'='never','value'='BoxLayout3','vscroll'='never'),
BoxCell('hscroll'='never','value'='BoxLayout9','vscroll'='never'),
BoxCell('hscroll'='never','value'='BoxLayout14','vscroll'='never')),
BoxColumn(
BoxCell('hscroll'='never','value'='Label3','vscroll'='never'),
BoxCell('hscroll'='never','value'='Plotter1','vscroll'='never'),
BoxCell('hscroll'='never','value'='Slider1','vscroll'='never'))),
GridLayout('background'="#D6D3CE",'border'='false','halign'='center','inset'='5','reference'='GridLayout1','valign'='center','visible'='true',
GridRow('valign'='top',
GridCell('height'='1','hscroll'='never','value'='BoxLayout1','vscroll'='never','width'='1'))),
Window('layout'='GridLayout1','reference'='Window1','resizable'='true','title'="Maplet"),
Action('reference'='Action1',
RunWindow('window'='Window1'))):

Maplets[Display](maplet);

 

If anyone would be able to provide an example of code or some guidance I could follow that would be greatly appreciated! 

Hi

 

I want to write the functional Z of J Z = exp(Int(Int(J(x)*Delta(x-y)*J(y), x), y))with Delta(x) = Int(I*exp(-I*k*x)*(1/(k^2-m^2)), k) in terms of the fourier transform of J: J(x) = Int(J(p)*exp(-I*p*x), p).

Actually I'm in Minkowski space and all the integrals should be over 4 dimensions, x,y,k,p should all be four-vectors, but I wanted to keep things short. (The only way I have found to express a 4D integral is using Physics-Intc with the singleparameters of the four vector. Is there a more convenient way to get d^4x?) But still in 1D I cannot solve it.

To find the solution, an exponential of only one integral, is actually pretty easy, since there are integrals over e. g. exp(-I*x*(p-k)) deliver a delta distribution, but I cannot reproduce this in Maple since he doesn't perform the integral over x.

I have found that I can/have to use the command inttrans-fourier to gain the delta distribution, but when I try to use it for the problem mentioned above I run into all kinds of problems. Not to mention that I cannot manage to perform a fourier transformation in 4D.

Does anybody know how to solve this problem? Thanks!

Hi,

I am using the solve command to solve an equation of the form "linear over quadratic is equal to a constant" where the constant is assumed to be nonzero. This is easily solved by hand, of course, but I to use the solution in other computations. So I asked maple to solve it for me. But when I check maple's solution (i.e. just plug the two solutions in on the left hand side and simplify) maple does not return the original constant. Can anyone help me understand what is going wrong?

Since it's not every day we receive submission to the Maple Application Center that have words like "quantum entanglement" (and "teleportation"!) in the title, I thought I'd share this one:

Matrix Representation of Quantum Entangled States: Understanding Bell's Inequality and Teleportation

 

eithne

Hi everybody!

I am trying to find explicitely the relations between the columns of a matrix

of non-maximal rank. For example, if I have the matrix

M := Matrix([<1,2,3>, <2,4,6>, <5,6,7>]);

I would like that Maple finds that the second column is twice the first one: v_2 = 2*v_1.

How can I do?

Hello All,

(I also sent this fact to Maplesoft Support).

Since I updayed to 2016.1 the F1 key does bring a menu witch send to..F5 only.

No way to have a "full" Help Menu.(See the attached file)

I guess a silly bug jumped in :)

Kind regards,

 

Jean-Michel

 

 

Hello

 

I will try to be as specific as possible.

On my Ti nspire it is possible for me to calculate polar equations like on the buttom picture with the settings on the upper picture. But when I try this in Maple It is not possible. I have worked my way try for two days now and it does not work for me.

Does any body know how to get this solved? 

Regards

Heide

 

An update to Maple 2016 is now available. Maple 2016.1 provides:

  • Updated translations for Simplified and Traditional Chinese,  French, Greek, Japanese, Brazilian Portuguese, and Spanish
  • Updates to the new Maple Workbook
  • Enhancements to Maple’s context-sensitive menus
  • A variety of improvements to the math engine and interface

 

To get this update, use Tools>Check for Updates from within Maple, or visit the Maple 2016.1 downloads page.

 

eithne

Hi,

I'm not sure that I mean datatable component corectly.

I also consider that I was done somthing wrong

Thank you for advanced for any help.

restart

with(DocumentTools):

Oryginaly DataTable was inserted as a 3 x 3. I will traing to push maple to obtain 4 x 4 with specific row and column name.

``

SetProperty("DataTable0", visibleRows, 4);

DocumentTools:-SetProperty("DataTable0", visibleColumns, 4);

DocumentTools:-SetProperty("DataTable0", columnWidths, [20, 40, 80, 80]);

DocumentTools:-SetProperty("DataTable0", rowNames, [r1, r2, r3, r4]);

DocumentTools:-SetProperty("DataTable0", columnNames, [c1, c2, c3, c4]);

DocumentTools:-SetProperty("DataTable0", update)

``

``

``


wzel

Download datatable_problem.mw

The attached worksheet shows a small selection of new and improved results in integration for Maple 2016. Note that integration is a vast topic, so there will always be more improvements that can be made, but be sure that we are working on them.

Maple2016_Integration.mw

A selection of new and improved integration results for Maple 2016

New answers in Maple 2016

 

 

Indefinite integrals:

 

int(sqrt(1+sqrt(z-1)), z);

(4/5)*(1+(z-1)^(1/2))^(5/2)-(4/3)*(1+(z-1)^(1/2))^(3/2)

(1.1)

int(arctan((-1+sec(x))^(1/2))*sin(x), x);

-arctan((-(1/sec(x)-1)*sec(x))^(1/2))/sec(x)+(1/2)*(-1+sec(x))^(1/2)/sec(x)+(1/2)*arctan((-1+sec(x))^(1/2))

(1.2)

int(((1+exp(I*x))^2+(1+exp(-I*x))^2)/(1-2*c*cos(x)+c^2), x);

-x-2*x/c-x/c^2+I*exp(I*x)/c-I*exp(-I*x)/c-I*c*ln(exp(I*x)-1/c)/(c-1)-I*ln(exp(I*x)-1/c)/(c-1)-I*ln(exp(I*x)-1/c)/(c*(c-1))-I*ln(exp(I*x)-1/c)/(c^2*(c-1))+I*c*ln(-c+exp(I*x))/(c-1)+I*ln(-c+exp(I*x))/(c-1)+I*ln(-c+exp(I*x))/(c*(c-1))+I*ln(-c+exp(I*x))/(c^2*(c-1))

(1.3)

int(x^4/arccos(x)^(3/2),x);

(1/4)*(-x^2+1)^(1/2)/arccos(x)^(1/2)-(1/4)*2^(1/2)*Pi^(1/2)*FresnelC(2^(1/2)*arccos(x)^(1/2)/Pi^(1/2))+(3/8)*sin(3*arccos(x))/arccos(x)^(1/2)-(3/8)*2^(1/2)*Pi^(1/2)*3^(1/2)*FresnelC(2^(1/2)*3^(1/2)*arccos(x)^(1/2)/Pi^(1/2))+(1/8)*sin(5*arccos(x))/arccos(x)^(1/2)-(1/8)*2^(1/2)*Pi^(1/2)*5^(1/2)*FresnelC(2^(1/2)*5^(1/2)*arccos(x)^(1/2)/Pi^(1/2))

(1.4)

 

Definite integrals:

int(arcsin(sin(z)), z=0..1);

1/2

(1.5)

int(sqrt(1 - sqrt(1+z)), z=0..1);

((4/5)*I)*(2^(1/2)-1)^(3/2)*2^(1/2)+((8/15)*I)*(2^(1/2)-1)^(3/2)

(1.6)

int(z/(exp(2*z)+4*exp(z)+10),z = 0 .. infinity);

(1/20)*dilog((I*6^(1/2)-3)/(-2+I*6^(1/2)))-((1/60)*I)*6^(1/2)*dilog((I*6^(1/2)-3)/(-2+I*6^(1/2)))+(1/20)*dilog((I*6^(1/2)+3)/(2+I*6^(1/2)))+((1/60)*I)*6^(1/2)*dilog((I*6^(1/2)+3)/(2+I*6^(1/2)))+((1/120)*I)*6^(1/2)*ln(2+I*6^(1/2))^2-((1/120)*I)*6^(1/2)*ln(2-I*6^(1/2))^2+(1/40)*ln(2+I*6^(1/2))^2+(1/40)*ln(2-I*6^(1/2))^2+(1/60)*Pi^2

(1.7)

simplify(int(sinh(a*abs(x-y)), y=0..c, 'method'='FTOC'));

(1/2)*(piecewise(x < 0, 0, 0 <= x, 2*exp(-a*x))+piecewise(x < 0, 0, 0 <= x, -4)+2*piecewise(c <= x, -cosh(a*(-x+c))/a, x < c, (cosh(a*(-x+c))-2)/a)*a-exp(-a*x)+piecewise(x < 0, 0, 0 <= x, 2*exp(a*x))+4-exp(a*x))/a

(1.8)

int(ln(x+y)/(x^2+y), [x=0..infinity, y=0..infinity]);

infinity

(1.9)


Definite integrals with assumptions on the parameters:

int(x^(-ln(x)),x=0..b) assuming b > 0;

(1/2)*erf(ln(b)-1/2)*Pi^(1/2)*exp(1/4)+(1/2)*Pi^(1/2)*exp(1/4)

(1.10)

int(exp(-z)*exp(-I*n*z)*cos(n*z),z = -infinity .. infinity) assuming n::integer;

undefined

(1.11)


Integral of symbolic integer powers of sin(x) or cos(x):

int(sin(x)^n,x) assuming n::integer;

` piecewise`(0 < n, -(Sum((Product(1+1/(n-2*j), j = 1 .. i))*sin(x)^(n-2*i-1), i = 0 .. ceil((1/2)*n)-1))*cos(x)/n+(Product(1-1/(n-2*j), j = 0 .. ceil((1/2)*n)-1))*x, n < 0, (Sum((Product(1-1/(n+2*j+1), j = 0 .. i))*sin(x)^(n+2*i+1), i = 0 .. -ceil((1/2)*n)-1))*cos(x)/n+(Product(1+1/(n+2*j-1), j = 1 .. -ceil((1/2)*n)))*ln(csc(x)-cot(x)), x)

(1.12)

int(cos(x)^n,x) assuming n::negint;

-(Sum((Product(1-1/(n+2*j+1), j = 0 .. i))*cos(x)^(n+2*i+1), i = 0 .. -ceil((1/2)*n)-1))*sin(x)/n+(Product(1+1/(n+2*j-1), j = 1 .. -ceil((1/2)*n)))*ln(sec(x)+tan(x))

(1.13)

int(cos(x)^n,x) assuming n::posint;

(Sum((Product(1+1/(n-2*j), j = 1 .. i))*cos(x)^(n-2*i-1), i = 0 .. ceil((1/2)*n)-1))*sin(x)/n+(Product(1-1/(n-2*j), j = 0 .. ceil((1/2)*n)-1))*x

(1.14)

Improved answers in Maple 2016

 

int(sqrt(1+sqrt(x)), x);

(4/5)*(1+x^(1/2))^(5/2)-(4/3)*(1+x^(1/2))^(3/2)

(2.1)

int(sqrt(1+sqrt(1+z)), z= 0..1);

-(8/15)*2^(1/2)-(8/15)*(1+2^(1/2))^(3/2)+(4/5)*(1+2^(1/2))^(3/2)*2^(1/2)

(2.2)

int(signum(z^k)*exp(-z^2), z=-infinity..infinity) assuming k::real;

(1/2)*(-1)^k*Pi^(1/2)+(1/2)*Pi^(1/2)

(2.3)

int(2*abs(sin(x*p)*sin(x)), x = 0 .. Pi) assuming p> 1;

-2*(sin(Pi*p)*signum(sin(Pi*p))*cos(Pi/p)-p*sin(Pi/p)*cos(Pi*(floor(p)+1)/p)+sin(Pi*(floor(p)+1)/p)*cos(Pi/p)*p-sin(Pi*p)*signum(sin(Pi*p))-sin(Pi*(floor(p)+1)/p)*p+sin(Pi/p)*p)/((cos(Pi/p)-1)*(p^2-1))

(2.4)

int(1/(x^4-x+1), x = 0 .. infinity);

-(sum(ln(-_R)/(4*_R^3-1), _R = RootOf(_Z^4-_Z+1)))

(2.5)


In Maple 2016, this multiple integral is computed over 3 times faster than it was in Maple 2015.

int(exp(abs(x1-x2))*exp(abs(x1-x3))*exp(abs(x3-x4))*exp(abs(x4-x2)), [x1=0..R, x2=0..R, x3=0..R, x4=0..R], AllSolutions) assuming R>0;

(1/8)*exp(4*R)-29/8+(7/2)*exp(2*R)-5*R*exp(2*R)+2*exp(2*R)*R^2-(5/2)*R

(2.6)

Austin Roche
Mathematical Software, Maplesoft


with(PDEtools, casesplit, declare)
``

L := 1651.12; m := 3205.12; r1 := .1875; r2 := 2; z1 := 0; z2 := 12; ld := 4.5

NULL

declare(u(r, z), w(r, z))``

with(DEtools, gensys)

rr := (L+2*m)*(diff(u(r, z), r))+L*(diff(w(r, z), z))+L*u(r, z)/r

zz := L*(diff(u(r, z), r))+(L+2*m)*(diff(w(r, z), z))+L*u(r, z)/r

rz := m*(diff(u(r, z), z))+m*(diff(w(r, z), r))

BCS := {rr(r1, ld) = 0, rz(r1, z) = T, w(r, 0) = 0, zz(r, z2) = 0}

{3205.12*(diff(u(r, z), z))(.1875, z)+3205.12*(diff(w(r, z), r))(.1875, z) = T, 8061.36*(diff(u(r, z), r))(.1875, 4.5)+1651.12*(diff(w(r, z), z))(.1875, 4.5)+1651.12*(u(r, z))(.1875, 4.5)/r(.1875, 4.5) = 0, 1651.12*(diff(u(r, z), r))(r, 12)+8061.36*(diff(w(r, z), z))(r, 12)+1651.12*(u(r, z))(r, 12)/r(r, 12) = 0, w(r, 0) = 0}

(1)

``

NULL

sys3 := [(L+2*m)*(diff(u(r, z), r, r))+(L+m)*(diff(w(r, z), r, z))+(L+2*m)*(diff(u(r, z), r))/r-(L+2*m)*u(r, z)/r^2+m*(diff(u(r, z), z, z)) = 0, (L+m)*(diff(u(r, z), r, z))+m*(diff(w(r, z), r, r))+(L+2*m)*(diff(w(r, z), z, z))+(L+m)*(diff(u(r, z), z))/r+m*(diff(w(r, z), r))/r = 0]

pdsolve(sys3, BCS, numeric)

 

 

``

``


Download PDE_equation2.mw

Hi all,

I have the following PDE, is it solveable by Maple or not. Do I need a boundary condition and how many or I can get a general solution? I am new to Maple. Any help will be appreciated.

Thank you.

 

 

 

Can we get it in MapleSim, not in exactly this form, but in substance? (Not in Maple)
The line of intersection of surfaces:
(x1-0.5) ^ 4 + x2 ^ 4 + x 3 ^ 4-1. ^ 2 = 0.;
x1 ^ 2 + (x2-0.25) ^ 2 + x3 ^ 2-1. ^ 2 = 0.;
(Red) rotates about an axis oX3. During rotation, the line intersects with the fixed sphere ((0., 1.5, 0 .5); R = 1.725). One of the points of intersection is drawn in green. Green Dot and the center of the sphere connected to the blue segment.  In the sphere  of  fixed  trajectory of  the green point.
In other words, the geometric model  3d  cam mechanism and its kinematics.


Here is a simple program.

t:=(a/b)^2*x*y;

st:=cat(``,`t:=`,t,`;`);

fprintf(`outfile`,"%A\n",st);

Running this on Maple 2015 gives a correct Maple statement for t in outfile which can be read into another Maple session.

Running on another computer with Maple 17 gives

t:= || (a^2/b^2*x*y) || ;

in outfile which is not a valid statement.

I know that I can avoid this problem by using the save statement but I want to understand why the code gives the wrong result in Maple 17 and how to change it so it works on both versions.

Thanks.

Hello All.

Why Maple can’t do this Simple indefinite integral?

I'm have a integral :

 

Please compare to Mathematica:

Thanks in advance for your help.

 

I_Mariusz

test.mw

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