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EDIT:EDIT: I found what I was looking for. Thanks!

 

eq:=(V^(1-r/(r-s))*V*k/(r-2*s)+_C1)*V^(r/(r-s))=0;

 

equation 1

 

solve(eq,C1);

 

Can anyone tell me why nothing happens when I solve the above equation for C1.

I've been coming across this problem a few times lately, but sometimes when the equations are less complicated it does work from time to time. 

Any help would be greatly appreciated.

 

EDIT:  Thanks Markiyan Hirnyk

But I'm still having some trouble.

 

f:=t->(-r*t+s*t+V)^(r/(r-s));

eq2:=diff(C*f(t),t)+C*f(t)*r/(V+s*t-r*t)=s*k*t;

solve(eq2,C);

 


When I try solving eq2 nothing happens. 


This time C is just a variable I used and not one Maple generated.

So why doesn't it work with this particular equation?

 

 

Hi. I'd like to find the solution closest to zero for sum(abs(f(k, m, n)+g(k, m, n)), n = i .. j) , when a < m, n < b . 

Have trouble wrapping my head around how to do that and would appreciate any help.

Even better would be to find a solution where the maximum absolute value of f(k, m, n) + g(k, m, n) is minimized for n = i .. j) and when a < m, n < b , but I'm guessing the sum would be easier, and close enough.

Maybe I'm barking up the wrong tree getting this done with Maple, but I'm hopeful.

Thank you for looking

Hi
In connection with recent developments in the Physics package, we now have mathematical typesetting for all the inert functions of the mathematical language. Hey! This is within the Physics update available on the Maplesoft Physics: Research & Development webpage

I think this is an interesting development that will concretely change the computational experience with these functions: it is not the same to compute with something you see displayed as %exp(x) instead of the same computation but flowing with it nicely displayed as an exponential function with the e in grey, reflecting that Maple understands this object as the exponential inert function, with known properties (all those of the active exp function), and so Maple can compute with the inert one taking these properties into account while not executing the function itself - and this is the essence of the inert function behaviour.

Introducing mathematical display, copy and paste for all these inert functions of the mathematical language concretely increases the mathematical expressiveness of the system, for teaching, working and also for presenting ideas.

Attached is a brief illustration.

Edgardo S. Cheb-Terrab
Physics, Maplesoft

InertMathematicalFun.mw  InertMathematicalFun.pdf

This is just a question on terminology. The name "combine" implies pulling terms together. Yet, when applied to something like sin(x)^2 it has the effect of expanding it:

r:=sin(x)^2;
combine(r);

 

Which seems counter-intutive to me. I tried first expand(r) but that did not expand it.

Fyi, in Mathematica the function to do the above is called

Sin[x]^2;
TrigReduce[%]

    1/2 (1 - Cos[2 x])

As Mathematica does not have a Combine[] function.

So, I am just wondering about the naming, that is all. I would never have thought first that a command called combine() will expand sin(x)^2.

 

 

Hi, all

I want to get some formular by the maple. I have some S domain transfer function, want to transform to the Z domain, but I don't know the way to realize it, is there any library function like "c2d" as in the Matlab? but "c2d" can not deal with the expression.

Thanks for replay to me!!!

New user. How do I launch the clickable math interface as in the demo video in maple 17 student? I also need help with entering/ solving simultaneous equations step by step.

Hi,

I'm preparing for GRE and i came across this question from 800score.com while reviewing concepts for probability.

In a deck of 52 standard playing cards, what is the probability that pulling a single card from the deck 
will produce a black card?

http://www.800score.com/content/gre/guidec7dview1a.html

Please...

I have bracket matching turned on but donot get the rectangular yellow box around matching brackets as shown in the attached picture. Can anyone help me how to turn this feature on for both input and output?

I have the following equation, I want to solve it for b keeping a and c fixed.

5*b^5+(60-5a)*b^4+(125+50c-80a)*b^3+(594c-445a-775)*b^2+(2324c-1005a-3270)*b+3000c-750a-3000=0.

How to solve it in maple?

 

 

 

I am using Maple 15 and every time I try to plot this equation it doesnt seem to want to plot. This is the code I keep trying to input:

plot(3*e^(-x)*x-e^(-x)-1.5*e^(-x)*(x^2)+e^(-x)*(x^2)*log(x),x=0..9,y=-1..0.6);

Every time I get "Plotting Error, empty plot"

The equation came from the original differential equation .5(d^2y/dx^2)+(dy/dx)+.5y(x)=ln(x)e^(-x)

 Also When i try to plot this equation:

-.5*e^(-10*x)*sin(10*x)-.5*e^(-10*x)*cos(10*x)+(3/2)=300

Hello,

I've been trying to force maple to find a solution of this differential equation:

ode := -((D@@2)(y))(r)-2*y(r)/r+y(r) = (2-V(r))*u[0](r)

dsolve(ode, y(r));

gives

y(r) = r exp(-r) _C2 + (exp(r) + 2 exp(-r) Ei(1, -2 r) r) _C1 - 4 

/ / /
|1 | |
exp(-3 r) |- | |
|2 | |
\ \/

/ 2 \ \

For a math class, we have to create a roller coaster. Part of the coaster consists of two banked curves. I've tried looking it up but Maple isn't very clear on how to create the. So, how do you create banked curves in Maple?

Today's SMBC strip by Zach Weinersmith is a silly math joke but it was pretty much begging for implementation.

So, here is a simple brute force Maple program to compute the Fouriest transform of an integer.

fouriest := proc(n::posint, ob::posint:=10)
local b,f,cap,i,rdx,fc;
...

Hi,

 

I have two differential equations describing a solar sail in 2D.

One is my radial direction and one is the tangential direction.

I have plotted r(t) and theta(t) but I want r(theta) so I have assigned my two differential equations and initial conditions, have my two plots for r and theta in terms of t and then I have used the following command to plot in polar coordinates:

 

Hi,

I'm new in Maple and i've a project to do. I've to find at what time is 90% of the steady-state concentration of C achieved. And the eq is 

z'=k(1/2-z)(1/3-z), where k=0.3. 

So i had worked in Mathematica before and i know that it would look something like that in there: 

eqn1 = 0 == k (1/2 - z[t]) (1/3 - z[t])

DSolve[Evaluate[{eqn1}], z[t]].

But i have no idea how to find this 90%. I hope that someone will...

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