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Hi,

I have a problem with the adaptive question designer: when I use the multiple choice question type then occasionally parts of the question environment appear multiple times in the text, duplicating each time I reopen the question to edit. This happens in particular if the answers are a bit longer (4-5 lines each). So far I couldn't figure out how to fix this, does anyone have a similar problem? 

Many thanks for your help!

Dear  i want to plot the graphs for different values of R[2,5,6.5]   here is the codes: Either ido loop or array i have to use or other procedure 

The graph display should be at R=2, one graph, R=5 another and R=6.5 

onemore graph

 

restart:
with(DEtools):
eta:=1+k*x+epsilon*sin(2*Pi*x):
A1(x):=-exp(-alpha*x)*J^2*R/(2*eta^3+6*xi*J^2*eta^2):

psi0:=A1(x)*y^3:
psi:=delta*psi0:
V:=-diff(psi,x):
delta:=0.1:
epsilon:=0.01:
alpha:=1:
xi:=0.001:
k:=0.1:
As:= [0, 2, 4]:
x:=0.2
plot([seq]([eval(V, J= A), y, y= 0..eval(eta, J= A)], A= As),title=" velocity at R=2.0 ",labels= ["v", "y"],color= [green, red, blue], linestyle= [solid, dash, dot],legend= [seq](J = A, A= As), axes=boxed);

 

 

 

 

 

 

hi , kindly guide me how to draw combine graphs for velocity profile at different values of one parameter.  For example we have 3rd order ODE and A is parameter that is multiple of equation. now we want to see the effects of that parameter on this 3rd  order ODE.  Now  how can i sketch the  combine graph of Df(o) at A=1, 2, 3. (for example.)

 

thanks 

How do I solve this in Maple:

 

M(k,n)=M(k,n-1)+M(k-1,n-1)+M(k-2,n-2) and

M(k,1)=1 and M(1,n)=n

 

?

 

Thank you, Jan

 

Dear,

I have a perfectly working when all parameters are known (figure 1), however I want to perform a sensitivity analysis by derivating the code if one parameter is unknown. Because of multiple possible answers and because of the complexity of the formula, I cannot run this script and get solutions. Any ideas how I can this calculation lighter so it is able to run? Values should be real and positive (so 1 or 2 solutions are the only one I'm interested in)

Any ideas, how I can make this code runnable? (file is below)

I'm stuck on this for a while now :/ So I hope someone will be able to help me

Many thanks in advance!l

Question.mw

Figure 1: [URL=http://s1240.photobucket.com/user/laggstar/media/Parameter%20f%20known.png.html][IMG]http://i1240.photobucket.com/albums/gg494/laggstar/Parameter%20f%20known.png[/IMG][/URL]

 

Figure 2: [URL=http://s1240.photobucket.com/user/laggstar/media/Parameter%20f%20unknown.png.html][IMG]http://i1240.photobucket.com/albums/gg494/laggstar/Parameter%20f%20unknown.png[/IMG][/URL]

I've got the following code:

with(plots):
a:=seq(combinat[fibonacci](k), k=2..10);
for i from 1 to 5 do
#with(plots):
multiple(plot,[sin(a[i]*x),x=-2..2,-2..2,color="Red",legend=typeset("Curve1:",sin(a[i]*x))],[sin(a[i+1]*x),x=-2..2,-2..2,color="Green",legend=typeset("Curve2:",sin(a[i+1]*x))],title=typeset("Lissajous",i));
end do;

 

that plots the sine functions of consecutive fibonacci numbers pairwise. Now, if I had to use the display command to plot these pairs together, how would I be able to do so?

 

I've got the following equations :

x^3-4x=y, y^3-3y=x that I want to plot together over an appropriate range for x and y

I've tried plots[multiple]([eq1,x=-2..2,y=-2..2],[eq2,x=-2..2,y=-2..2]) 

but that doesn't seem to work. How can I rectify this error?

Hi, all

I use INT to calculate multiple integration as below. It runs more than 20 hours without results. I wander is there any problem in my codes.

restart;
A := sin(k*Pi*(x-h*cos(theta))/a)*sin(l*Pi*(y-h*sin(theta))/b)*sin(k[0]*h)*sin(k*Pi*x/a)*sin(l*Pi*y/b);

W := evalf[5](int(int(int(int(A, h = 0 .. (x-a)/cos(theta)), theta = Pi+arctan((b-y)/(a-x)) .. 3*Pi*(1/2)), x = 0 .. a), y = 0 .. b, numeric))

 

Thanks

Hi there,

I am trying to display multiple pointplots in the same plot. I would like to either distinguish the plots by their color or by the symbol (square, traiangle, circle) at each data-point. May be both, although I ignore whether using symbols at data-points is possible in Maple.

The plot i would like to achieve is this: 

Maple says that my points are not in the correct format: MapleSimulation_test6.mw

 

My data array N has two parameters, and the free variable. The two parameters are also varied over a certain range. For plotting purposes, I would like to have one of the variables fixed, select three parameters for the other variable, and plot all data-points for them.

The resulting data array N seems to be OK, but I am aware that my attempt for plotting multiple arrays may be wrong. May be pointplot is not even the best choice.

 

Any ideas?

 

Thank you,

jon

 

 

Is it possible to evaluate a function at multiple points described by an array or something of that sort and have Maple return the evaluations as an array. I need approximations of a function at various values of its argument so it would be nice to do it with a single command.

Thanks

Say I have

a.mpl

b.mpl

c.mpl

each of them can be ran seperately. While I am running a single file, it looks like that the machine is not "using" too much computation power. I wonder if it's possible to run multiple at the same time ?

My CPU is i7 940X, with 4 dual core processors, so it has 8 threads.

I know that the GUI can run multiple worksheets seperately, but if in one of the worksheet, i click "run all" (!!! botton),  I will have to run each line separtely by clicking one at a time.

Is there a better way to do this? What's the best way to do this? I hope to somehow 'maximize' the full use of my CPU (without changing the code).

 

casper

I want to sum over several variables at once.

 

For example, something like

add(add(add(f(k1,k2,k3),k1=range1),k2=range2),k3=range3);

sums over 3 variables. But this can only be done if I know the number of variables in advance. I want to write a code that will sum over m variables, with m being supplied on demand.

 

Maple can do this for integrals. If I write

int(f(seq(k[i],i=1..m)),[seq(k[i]=range[i],i=1..m)]);

the integral is computed over m variables, for any m.

 

How can something like this be implemented for summation?

 

¿How can I substitute multiple variables with the alsub command at the same time?

For example, if I want to substitute  x=x1, y=x2, .... into the expression f=x*y+x^2+.... using just one command

How can I plot multiple numeric plots, such that numeric solutions belong to different differential equations?

i want to plot two difrent graph in one diagram.. anyone how to do it?

restart; with(plots); n := .2; B := .5; Ec := 2.0; Pr := 1.0; N := .5; l := 1; rho := .5; c := 1; T := .5; T1 := .5; c1 := .2; c2 := .2; Gr := .5; blt := 5;

Eq1 := diff(f(eta), eta, eta, eta)+f(eta)*(diff(f(eta), eta, eta))-(diff(f(eta), eta))^2+l*B*H(eta)*(F(eta)-(diff(f(eta), eta)))+Gr*theta(eta)-Mn*(diff(f(eta), eta)) = 0;

Eq2 := G(eta)*(diff(F(eta), eta))+F(eta)^2+B*(F(eta)-(diff(f(eta), eta))) = 0;


Eq3 := G(eta)*(diff(G(eta), eta))+B*(f(eta)+G(eta)) = 0;

Eq4 := G(eta)*(diff(H(eta), eta))+H(eta)*(diff(G(eta), eta))+F(eta)*H(eta) = 0;
                 
Eq5 := diff(theta(eta), eta, eta)+Pr*((diff(theta(eta), eta))*f(eta)-2*(diff(f(eta), eta))*theta(eta))+N*Pr*(theta1(eta)-theta(eta))/(rho*c*T)+N*Pr*Ec*(F(eta)-(diff(f(eta), eta)))^2/(rho*T1) = 0;

Eq6 := 2*F(eta)*theta1(eta)+G(eta)*(diff(theta1(eta), eta))+c1*(theta1(eta)-theta(eta))/(c*c2*T) = 0;

bcs1 := f(0) = 0, (D(f))(0) = 1, (D(f))(blt) = 0, F(blt) = 0, G(blt) = -f(blt), H(blt) = n, theta(0) = 1, theta(blt) = 0, theta1(blt) = 0;

L := [0, 1, 2];

for k to 3 do R := dsolve(eval({Eq1, Eq2, Eq3, Eq4, Eq5, Eq6, bcs1}, Mn = L[k]), [f(eta), F(eta), G(eta), H(eta), theta(eta), theta1(eta)], numeric, output = listprocedure); Y || k := rhs(R[3]); YP || k := rhs(R[5]); YR || k := rhs(R[6]); YQ || k := rhs(R[7]); YA || k := rhs(R[8]); YB || k := rhs(R[10]) end do;

plot([Y || (1 .. 3)], 0 .. 10, labels = [eta, (D(f))(eta)]);

 

this comands will comeout to diffrent graph in two diagram.. but i want two graph in one diagram.. any one know how to do it.. beside that.. i want to know how to insert arrow in diagram..

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