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Hi all,


I tried to find the real solution of the unlinear integral equation:


exp(-h^2/T)*(Int(exp(-x^2/T)*BesselI(0, h*x/T)*x, x = 0 .. 1))/T


but I got the warning and an complex solution:


 solve(subs(T = 1, eq)-.99 = 0, h)

Warning, solutions may have been lost



Can anyone help me to find a real solution for this issue (if possible)...?

I would like to thank you in advance.


In the following problem though b and c are same (except the way denominator 2 is hanfled), command ' a-b ' readily answers zero, but a-c not so. Why? Only on condition of assumption real it gives zero!

a := (1/2)*(kappa*omega^2+omega^3)*(Y+(1/2)*(-sqrt(N)*omega^(3/2)*sin(theta[2])*cos(varphi[2])*lambda__b+sqrt(N)*omega^(3/2)*sin(theta[1])*cos(varphi[1])*lambda__a)/(kappa*omega^2+omega^3))^2/omega:

b := (1/2)*(kappa*omega^2+omega^3)*(Y+(1/2)*(-sqrt(N)*omega^(3/2)*sin(theta[2])*cos(varphi[2])*lambda__b+sqrt(N)*omega^(3/2)*sin(theta[1])*cos(varphi[1])*lambda__a)/(kappa*omega^2+omega^3))^2/omega:




c := (1/2)*(kappa*omega^2+omega^3)*(Y+(-sqrt(N)*omega^(3/2)*sin(theta[2])*cos(varphi[2])*lambda__b+sqrt(N)*omega^(3/2)*sin(theta[1])*cos(varphi[1])*lambda__a)/(2*(kappa*omega^2+omega^3)))^2/omega:








Why the answer is not given as zero?





What difference therms b and c make for Maple? Are they not same?

Ramakrishnan V

hi all

i have a set of complex numerics, so:

1- i want the numeric with least valence(potency) in imagin particle,

2- i want print the real particle of this numeric.

for example:

A:= .5464691235-.4473247264*I, -.4563184747+1.*10^(-14)*I, .5464691235+.4473247264*I

i want print: -.4563184747


plz help



If for example I type :

`assuming`([dsolve({-7 = a(x)^2*b(x), a(x) = 3*b(x)}, {a(x), b(x)})], [(b(x))::real])

It gives out this :

`assuming`([dsolve({-7 = a(x)^2*b(x), a(x) = 3*b(x)}, {a(x), b(x)})], [(b(x))::real])

I want dsolve to know I'm using real numbers so it gives out something like :

[{a(x) = -21^(1/3)}, {b(x) = (-21^(1/3))*(1/3)}]

I tried some assumptions and stuff like assume(a,real), but I didn't manage to figure it out.


If that matters, I'm using Maple 18 student.


EDIT : I know dsolve is not necessary for this particular example, but I want to know if it's possible with dsolve or maybe an other tool that can handle ODE.


Thank you in advance !


I have this matrix

A := Matrix([[x+I*y, z+I*w], [-z+I*w, x-I*y]])

and I want a matrix which components are de real parte of the components of A. I have tried this:


but it doesn't work.

What is wrong?

Thank you so much.


I would like to assume a matrix to have only real components.

I have seen that the function assume has some features to assume properties for matrix. But, I didn't find the one that I want : "assume a matrix to have only real components".

This assumation should allow me to suppress this kind of choice in my code :

if A::{complexcons, undefined} then
elif A::rtable and ArrayTools:-NumElems(A) = 1 then
end if;

Do you have some ideas ?

P.S: The matrix should be also a square matrix. So, the first code line will probably be : assume(a, 'SquareMatrix')

Thanks a lot for your help.

consider quadratic equation ax^2+bx+c =0 :
the coefficients vary between -1 and +1 . just like this :
-1<a<+1 , -1<b<+1 , -1<c<+1 ;
how can some one proove that this equation should have real answers ?! can anybody help ? thanks in advance.

Can I use Maple to solve equation like |a-b|+\sqrt{2b+c}+c^2-c+1/4=0 for a,b,c?


a,b,c are real numbers and I need to solve it in real domain.

I have the following characteristic equation by use of maple. How do I find a condition on x, that will return real eigenvalues and complex eigenvalues?




So here is the issue: I have a 50 by 50 tridiagonal matrix. The entries in the first row, first column are -i*x and the last row last column is -i*x; these are along the main diagonal, where i is complex and x is a variable. Everything in between these two entries is 0. Above and below the main diagonal the entries are -1. My issue is that I have to find a conditon on x that makes the eigenvalues real. I am completely new to maple and have no programming experience.. Can someone show me how to this?


I got the Real and Imaginary of an expression J1 




J1mod:=simplify((Re(J1))^2+(Im(J1))^2): (I works here this amont is real)


but when I change the expression  for J1 to be



J1mod here is complex(I dont know why? it doesnt separate the real and the im )

Any comments will help



I need you help to understand this problem.


Let alpha=0.1.;

When I do :  (-0.2)^alpha I get a complex number.


I must find a real number.

What's the problem

Thanks for your idea.


Hi all.

I try to get the real part from the complex expression. But it turns out to not be the simplest result:


convert(exp(-I*k[0]*h), sin);


Maple results in:


while the simplified result should be:



I wander how to get the simplifyed result in maple. Thanks

If we a complex number in Maple, like for example:



How can we make maple rewrite it like this?



I tried using the comands Re(%) and Im(%) but Re just gives the whole expression again and Im gives 0.

I have a characteristic equation. some times It has polar roots . sometimes It has real roots and sometimes both of them.

I want to extract real roots and extract polar roots if they are.

for instance:



I want to know how can I use if in this part ?

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