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Maybe many questions on forum because method is not universal. What about this one:

JA1S := (2*sqrt(2*y+3)*y+3*sqrt(2*y+3)-3*sqrt(3))/((2*y+3)^(3/2)*y);

 

simplify(JA1S, power, radical, symbolic); - nothing

combine(JA1S, power, radical, symbolic); - nothing

 

Moreover, can i somehow also reduce by y?

I was trying to use the LeviCivita in the physics package to type the left side of the following equation and let maple compute the right side, where it considers the totally antisymmetric tensor identity which reduces to 4 Kronckers. Then the Kroneckers disappear and give rise to the right hand side. But I don't know how to tell maple to do this. There is also another Levi_Civita command in the tensor package.

 

main.mw

Please, start attach from beginning till that place where 

How to speedup them? There are more than 20 functions that are evaluated one by one. Is option 'remember' + permanent remembered item of pure symbolic calculation can speedup this process? How also efficiently to do simlify itself? Can i actually use more kernels in one session or to paralilize available one?

Hello, I´m trying to solve a system of 15 non linear equations and 8 unknown variables {r0,u0,w0,v0,q0,n0,t0,m0}, all of my equations ase symbolic with variables 10 {x,y,r,u,w,v,q,n,t,m}.

The Solve command does not work, I've been reading the other posts regarding this issue, but I don't believe they work for my case.

I would really appreciate if someone has an idea to help me solve this issue.

Im posting the worksheet with the system of 15 equations

I need maple to perform the following:

"int((1+m^2*(alpha-theta)^2*sin(theta)^2/sin(alpha)^2/alpha^2)^(1/2),theta = 0 .. alpha)"

but maple does not integrate. I have tried assuming that the term inside the square root is positive, with no result. What else can I do?

Hello,

I would like to write some functions and algebra that work with dual numbers.

http://en.wikipedia.org/wiki/Dual_number 

http://en.wikipedia.org/wiki/Dual_quaternion 

I have not found a library that supports this.

The basis of dual numbers it is epsilon^2=0, similar to i,j,k in complex algebra where i^2=-1,i*j=-1 etc.

Hi.

I have a procedure that takes multiple parameters, in which I want to fix all but one, and then define a single variable function that maps x to this remaining unspecified parameter, so I can give it to the plot() routine. I would like to define a number of such single variable functions for different values of the parameters and plot them all on the same axes.

Ideally, I would like to find a way to make the following, instead of returning 14, return 21,...

I am a novice user in Maple with some previous Matlab experience. My question is the following: I am thinking about doing some Maple calculations. The  calculations will involve (in the easiest case) about 15 (symbolic) variables , and it will require all kinds of symbolic differantation, integration etc. such as F(x)=b(t) where x is the symbolic variables and t is the differentiation parameter (all symbolic).   I would like to know how many variables Maple can deal...

There have been many times when I want to see what the graph a function looks like, but don't have numbers to put in there. Sure, I could just plug in numbers, but that often affects the graph - such as slope. Is there any way for Maple to show me the shape of a graph with a symbolic function?

Why does this happen to Maple 15?

    `assuming`([sum(k*p*Beta(k, p+1), k = 1 .. infinity)], [p > 1]); eval(%, p = 2)

Is it possible to show with Maple that for any real p>1 the series converges to p/(p-1), e.g.,

    `assuming`([sum(k*p*Beta(k, p+1), k = 1 .. 1000)], [p > 1]): subs(p = 2, %): evalf(%)

How do I show this symbolically? Thanks.

Maple evaluates

> sum(1/z^2, z = 1 .. infinity)

to (1/6)*Pi^2. What do I do when sumation is over all even positive integers? Is there any  closed-form symbolic formula for this case?

Above is the minimal example. What I need is to compute 

> sum(2*binomial(m-1, k-1)*binomial(n-1, k-1)/binomial(m+n, m), k = 1 .. infinity)

where k belongs to a set of only even positive integers, not any posint. The second expression evaluates to 2*m*n/((m+n-1...

I am trying to calculate inverse laplace of a 3*3 matrix (answer1 matrix). Find below the maple commands i used.

>with (linear algebra):

A:=<alpha,p11,e11|0,o11,-e11|a,m11,0>

N:=<s,0,0|0,s,0|0,0,s>

k:=N-A

Z:=MatrixInverse(k)

B:=<0,-m11,0>

C:=<1,0,0>

X0:=<isalpha0,ilalpha0,vcalpha0>

answer1:=Z.(X0+(ScalarMultiply(B,uinvalpha/s))+(ScalarMultiply(C,ealpha/s)))

I would like to generate a symbolic sum of the first "n" derivatives of a function.

For example, f = 1/(1-x^4)

sum(f^(n),n=0..3)

The response from Maple is not as expected.  The first term is:  -1/(4*(x-1)) and the subsequent terms are less recognizable.

If I use "seq" with the same syntax, I end up with a list that includes the function and the first 3 derivatives.

I have also tried:

sum(diff(f,x$n),n=0..3)

With f := i->`if`(i = 0, 1, alpha), I'd like to evaluate expression A below entirely symbolically, i.e. with l=1..3 being replaced with l=1..h in

sum('sum(sum(f(i)*f(i+j), i = 0 .. l-1), j = 1 .. h-l)', l = 1 .. 3); subs(alpha = .3, h = 3, %);#A

but using  A with l= 1 .. h provides a different number, the one one obtains with

sum(sum(sum(f(i)*f(i+j), i = 0 .. l-1), j = 1 .. h-l), l = 1 .. h); subs(alpha = .3, h = 3, %); #B

Expressions...

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