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How does one adjust the aspect ratio for Maple plot? I actually searched for aspect ratio for Maple on google and not able to find much of anything. Help does not have such phrase. May be it called something else in Maple? The reason I ask, is that when I change the size of bode plot, the aspect ratio become bad. So I need a way to adjust that. Here is an example

restart:
alias(DS=DynamicSystems):
sys:=DS:-TransferFunction(5*s/(s^2+4*s+25)):
DS:-BodePlot(sys,range=0.1..100);

Now if I do

DS:-BodePlot(sys,range=0.1..100,size=[300,"default"]);

I am finding so many problems with Bodeplot in Maple, but this is for another time. I think it needs much more polishing

Maple 18, windows 7

I have some data for a model in MapleSim that I would like to use a time look up table with.  I've found that the two options for interpolation are linear and 1st derivative, but the data was intended to be interpretted as piecewise constant.  Is there any way to acheive this option in MapleSim?

I am trying to find out the stiffness matrix of composite by using iterative loop that sums over each laminate and adds the result to the previously calculated matrix 

D=null matrix

for i to 4 do Dply := evalf(evalm((1/3)*Q[i]*(z(i+1)^3-z(i)^3))); D := evalm(D+Dply) end do;
evalm(D);

although the values are coming out fine but in the diagonalm elements, it shows the true value + _rtable[4456495426] which I am not able to figure out why is it coming?

 

data table export...

June 17 2014 wo0olf 15

hi,

I want to solve this to data table , i can plot but i need data in table 

 

sol1 := dsolve([diff(u(theta),theta) = 427.2461*u(theta)+385620.123/u(theta)-25671.3871, u(0) = .6], numeric);

plots[odeplot](sol1, 0..0.18, color = red);

 

thanks.

Hello

 

Is it me or is it not possible to hide table borders in Maple 18?

I can not hide the borders when I make tables ind Maple 18..

 

Jakob

Hello Hello everybody 
   I have to solve the following differential equation numerically 


``

 

restart:with(plots):

mb:=765 : mp:=587 : Ib:=76.3*10^3 : Ip:=7.3*10^3 : l:=0.92 : d:=10: F:=490: omega:=0.43 :

eq1:=(mp+mb)*diff(x(t),t$2)+mp*(d*cos(theta(t))+l*cos(alpha(t)+theta(t)))*diff(theta(t),t$2)+mp*l*cos(alpha(t)+theta(t))*diff(alpha(t),t$2)+mp*(d*diff(theta(t),t)^2*sin(theta(t))+l*(diff(theta(t),t)+diff(alpha(t),t))^2*sin(alpha(t)+theta(t)))-F*sin(omega*t)=0;

1352*(diff(diff(x(t), t), t))+587*(10*cos(theta(t))+.92*cos(alpha(t)+theta(t)))*(diff(diff(theta(t), t), t))+540.04*cos(alpha(t)+theta(t))*(diff(diff(alpha(t), t), t))+5870*(diff(theta(t), t))^2*sin(theta(t))+540.04*(diff(theta(t), t)+diff(alpha(t), t))^2*sin(alpha(t)+theta(t))-490*sin(.43*t) = 0

(1)

eq2:=(mp+mb)*diff(z(t),t$2)-mp*d*(sin(theta(t)+alpha(t))+sin(theta(t)))*diff(theta(t),t$2)-mp*l*sin(alpha(t)+theta(t))*diff(alpha(t),t$2)+mp*(d*diff(theta(t),t)^2*cos(theta(t))+l*(diff(theta(t),t)+diff(alpha(t),t))^2*cos(alpha(t)+theta(t)))+9.81*(mp+mb)-F*sin(omega*t)=0;

1352*(diff(diff(z(t), t), t))-5870*(sin(alpha(t)+theta(t))+sin(theta(t)))*(diff(diff(theta(t), t), t))-540.04*sin(alpha(t)+theta(t))*(diff(diff(alpha(t), t), t))+5870*(diff(theta(t), t))^2*cos(theta(t))+540.04*(diff(theta(t), t)+diff(alpha(t), t))^2*cos(alpha(t)+theta(t))+13263.12-490*sin(.43*t) = 0

(2)

eq3:=mp*(d*cos(theta(t))+l*cos(alpha(t)+theta(t)))*diff(x(t),t$2)-mp*(l*sin(theta(t)+alpha(t))+d*sin(theta(t)))*diff(z(t),t$2)+(Ip+Ib+mp*(d^2+l^2)+2*mp*d*l*cos(alpha(t)))*diff(theta(t),t$2)+[Ip+mp*l^2+mp*d*l*cos(alpha(t))]*diff(alpha(t),t$2)-mp*sin(alpha(t))*(l*d*diff(alpha(t),t)^2-l*d*(diff(alpha(t),t)+diff(theta(t),t))^2)+mp*9.81*l*sin(alpha(t)+theta(t))+mp*9.81*d*sin(theta(t))=0;

587*(10*cos(theta(t))+.92*cos(alpha(t)+theta(t)))*(diff(diff(x(t), t), t))-587*(.92*sin(alpha(t)+theta(t))+10*sin(theta(t)))*(diff(diff(z(t), t), t))+(142796.8368+10800.80*cos(alpha(t)))*(diff(diff(theta(t), t), t))+[7796.8368+5400.40*cos(alpha(t))]*(diff(diff(alpha(t), t), t))-587*sin(alpha(t))*(9.20*(diff(alpha(t), t))^2-9.20*(diff(theta(t), t)+diff(alpha(t), t))^2)+5297.7924*sin(alpha(t)+theta(t))+57584.70*sin(theta(t)) = 0

(3)

eq4:=mp*l*cos(alpha(t)+theta(t))*diff(x(t),t$2)-mp*l*sin(alpha(t)+theta(t))*diff(z(t),t$2)+(Ip+mp*l^2+mp*d*l*cos(alpha(t)))*diff(theta(t),t$2)+(Ip+mp*l^2)*diff(alpha(t),t$2)-mp*9.81*l*sin(alpha(t)+theta(t))+l*d*mp*diff(theta(t),t$1)^2*sin(alpha(t))=0;

540.04*cos(alpha(t)+theta(t))*(diff(diff(x(t), t), t))-540.04*sin(alpha(t)+theta(t))*(diff(diff(z(t), t), t))+(7796.8368+5400.40*cos(alpha(t)))*(diff(diff(theta(t), t), t))+7796.8368*(diff(diff(alpha(t), t), t))-5297.7924*sin(alpha(t)+theta(t))+5400.40*(diff(theta(t), t))^2*sin(alpha(t)) = 0

(4)

CI:= x(0)=0,z(0)=0,theta(0)=0,alpha(0)=0,D(x)(0)=0,D(alpha)(0)=0,D(z)(0)=0,D(theta)(0)=0;

x(0) = 0, z(0) = 0, theta(0) = 0, alpha(0) = 0, (D(x))(0) = 0, (D(alpha))(0) = 0, (D(z))(0) = 0, (D(theta))(0) = 0

(5)

solution:=dsolve([eq1,eq2,eq3,eq4, CI],numeric);

Error, (in f) unable to store '[0.]/(0.17571268341557e16+[-0.25659510610770e15])' when datatype=float[8]

 

 

 

I don't know why it says : Error, (in f) unable to store '[0.]/(0.17571268341557e16+[-0.25659510610770e15])' when datatype=float[8]

 

Help pleaase!

thank you !!!

Download systéme_complet.mw

 

In order to make worksheets more interactive in a teaching environment I have begun playing around with the Tables the standard GUI provides. The idea is that in the left column is the script we are working through while in the right column is space a student can work with the equations and formulae from the left side to, e.g., plot, change parameters etc. without affecting the script too much.

To build the tables I copy-pasted code from a normal worksheet (in document mode) into the left column, creating rows of appropriate length to have a logically coherent section in one row. Usually one row is one Section (in the technical sense of Maple Sections). The student gets to play in the right column.

In principle this seems to work quite well in my preliminary testing. I did find out rather quickly that on the right side one needs to be in 1-d input mode with a prompt for anything to be calculated interactively. Ok, actually probably easier to do. The table is set to evaluate by row so the right-left correspondence is preserved.

A potential issue I am facing however is with equation numbering: I use equation numbers extensively to reference back to upstream results. In the Table, it appears that equation numbers are not unique; in each row of the Table, eq. numbers start as (1.1), (1.2) etc. I am able to reference back to results from a prior row, even though the same equation number will show up again later in the new row. But I am concerned that eventually this all ends up in a big mess and my references point to the wrong expression or equation. Non-unique line numbers seem like a Really Bad Idea, and I'd like to avoid that if possible.

Does anyone know how the lines numbers work for code in Tables and how I make sure they are unique? I suppose I could explicitly assign results I need in other rows to names, but that does not prevent a reference to an eq. number from pulling in the wrong one from a prior row (assuming for the moment that Maple will never look forward to resolve a reference).

Thanks,

Mac Dude

Dear all;

Please I have maybe a simple question. I need to point these nodes in R^3 using Maple. Thanks for your help.

Tab := [[0, 0, 0], [1/5, 0, 0], [2/5, 0, 0], [0, 1/5, 0], [1/5, 1/5, 0], [2/5, 1/5, 0], [0, 2/5, 0], [1/5, 2/5, 0], [2/5, 2/5, 0], [0, 0, 1/5], [1/5, 0, 1/5], [2/5, 0, 1/5], [0, 1/5, 1/5], [1/5, 1/5, 1/5], [2/5, 1/5, 1/5], [0, 2/5, 1/5], [1/5, 2/5, 1/5], [2/5, 2/5, 1/5], [0, 0, 2/5], [1/5, 0, 2/5], [2/5, 0, 2/5], [0, 1/5, 2/5], [1/5, 1/5, 2/5], [2/5, 1/5, 2/5], [0, 2/5, 2/5], [1/5, 2/5, 2/5], [2/5, 2/5, 2/5]]

This table contains some point of R^3. How can I put these point.

Consider the ring R of upper-triangular matrices over the field of 3 elements.  I would like to have a multiplication table for this ring. Is it possible to generate such a table in Maple?  Thank you.

table of newton raphson...

December 10 2013 pinky 5

how to make a table of newton raphson ? 
working is below 
printf("No           root                   x[i+1]                 abs(x[i+1]-x[i])\n"); for i to n do y[i] := evalf(x[i]+(-D1(x[i])+sqrt(D1(x[i])^2-2*f(x[i])*D2(x[i])))/D2(x[i])); x[i+1] := evalf(y[i]-f(y[i])/sqrt(D1(x[i])^2-2*f(x[i])*D2(x[i]))); printf("%d         %10.10f     %10.10f       %10.10e \n", i+1, x[i+1], f(x[i+1]), abs(x[i+1]-x[i])); if abs(x[i+1]-x[i]) < tol then print("approximate solution" = x[i+1]); print("No of iterations" = i+1); break end if end do
please help me 

Is there a way to swap the names of two Arrays without creating unnecessary copies?

 

The scenario is as follows. I want to repeatedly apply a function to a large Array. The new value in each cell depends on seveal cells of the old Array.  So on each iteration I need to keep track of two Arrays: A_old and A_new. At the end of the iteration I would like to swap A_old and A_new efficiently. This way I will only need the memory for two Arrays and will...

sol[2] := [[2, 1], [3, 4]];

for i from 1 to nops(sol[2]) do

sol[2][i] := [seq(op(k,sol[2][i]), k=nops(sol[2][i])..1, -1)];

T := T + table([seq(op(k,sol[2][i])=op(k-1,sol[2][i]), k=2..nops(sol[2][i])),op(1,sol[2][i])=op(nops(sol[2][i]),sol[2][i])]);

od;

final result should be

1 2 3 4

2 1 4 3

Let A be a table. I give following sequence of commands:

>>B:=A;
>>A[x]=34:

Then surprisingly (at least for me) it turns that B has also changed its value for B[x]. Would someone help me understand this? What is it called? How we can stop this behaviour i.e. A and B should behave as independent tables?

regards

I have two lists viz.

m:=[0,1,2,3,4,5]; n:=[0,1,2,3,4,5,6,7,8,9];

I have to define a mapping (i.e. a Maple table) say `p` such that

(1) p(0)=0,

(2) p(max(m))=p(max(n)) and

(3) For all other i in m p(i) is a random choice from n but with condition that p(i)>=p(i-1).

Help is desperately needed. regards

I have a set X={a,b,c,d,e} and a table as follows:

M[2]:=TABLE([e = {2,3}, a = 5, c = 1]);

Afterwards I want to add to this table all those elements (e.g. b={3,4} and d=4) of X which are unassigned in M[2]. How I can do this?

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