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Hello,

Good day.

How to avoid float(undefined) for v3, v4,v5 in this problem.

Thank you in advance.

Try_for_Second_Grade_Fluid.mw

I'm trying to use Maple to show that the Hilbert transform of the natural log of |H(jw)| is -arctan(H(jw))

for a minimum phase network; The network I choose is the simplest filter there exists i.e. a low pass RC-filter

with transfer function H(jw)=1/(1+tau*j*omega) therefore |H(jw)|=1/sqrt(1+(tau*omega)^2))

Here is what I did:

assume(omega > 0); assume(tau > 0); interface(showassumed = 0);

result5 := (int((1/2)*log(1+(tau*nu)^2)/(nu-omega), nu = -infinity .. infinity, CauchyPrincipalValue))/Pi

simplify(result5, symbolic)

 

unfortunately this does not give me the expected result: -arctan(w*tau*omega)

can anyone here tell me what the right way to do it is?

 

thanks in advance

hugo

I am trying to recreate journal work for validating using another computer program so I am trying to use maple to solve the ODE, based on further research I found using laplace might be the best but I am having some trouble.

 

eq8:=d*(n(t)+C(t))/drho = -rho(t)/(l*alpha*K_c)

given the initial conditions of:

ICs:= n(0) = n_0, rho(0) = rho_0, C(0) = (beta-rho_0)*n_0/(l*lambda)

therefore: 

equation9 := dsolve({equation8, ICs}, {C(t), n(t)}, method = laplace)

 

Following this process I get the error: 

Error, (in dsolve) invalid initial condition

 

According to the journal work the solution I am looking for is: 

C(t)=-n(t)+(rho_0^2+rho(t)^2)/(2*l*alpha*K_c)+((Beta+l*lambda-rho_0)*n_0)/(l*lambda)

 

is there something that I'm doing wrong or missing? 

Any help would be greatly Appreciated! 

 

Dear all,

I have a question, why is the output of the inverse Laplace transformation if the signal is multiplied by itself not just convoluted in time domain:

restart:
with(inttrans):
u0(s):=laplace(u0(t),t,s):
ul(s):=laplace(ul(t),t,s):

invlaplace(u0(s)*ul(s),s,t);
invlaplace(u0(s)*u0(s),s,t);

 

Thanks!

 

I have a long expression with different order derrivatives, that is written in form like that:

-(D[1](f))(x, y)

I'd like to transform it into standard maple form like:

diff(f(x,y),x)

Is there any special procedure to achieve this goal?

Can anyone tell me where I can find tutorial explaining how to solve laplace transform? I need a tutorial that explains starting with simple resolution to advanced resolution.

I need to know if the Software Maple solve, step-by-step series of Fourier and Laplace transforms? The Maple command has to solve step by step series of Fourier and Laplace transforms? or commands show only the direct solution?

I'm trying to solve this system of ODEs by Laplace transform. 

> de1 := d^2*y(t)/dt^2 = y(t)+3*x(t)

> de2 := d^2*x(t)/dt^2 = 4*y(t)-4*exp(t)

with initial conditions 

> ICs := y(0) = 2, (D(y))(0) = 3, x(0) = 1, (D(x))(0) = 2

 

Using 

> deqns := de1, de2

and

> var := y(t), x(t)

 

I need to solve it for both y(t) and x(t), I have tried this by:

> dsolve({ICs, deqns}, var, method = laplace)

And

> dsolve({ICs, deqns}, y(t), method = laplace)

> dsolve({ICs, deqns}, x(t), method = laplace)

 

However I get this error message:

Error, (in dsolve/process_input) invalid initial condition

 

Any help is appreciated

Hello everyone,

 

how exactly do i 3-d plot some data that i have to back-transform first. in 2-d it is so easy. why isnt it in 3d? all i end up with is an all black diagram

transformIT.mw

please see the file attached

Grateful for some hints

Goon

 

i have a work on Magic Squares , and i need to rotate or flip them to all 8 possible directions .
but i am confused to find such special commands in maple for doing my purpose !

may you guide me how can i do this programmaticaly ?

 

order4 := Array(1 .. 4, 1 .. 4, {(1, 1) = 8, (1, 2) = 11, (1, 3) = 14, (1, 4) = 1, (2, 1) = 13, (2, 2) = 2, (2, 3) = 7, (2, 4) = 12, (3, 1) = 3, (3, 2) = 16, (3, 3) = 9, (3, 4) = 6, (4, 1) = 10, (4, 2) = 5, (4, 3) = 4, (4, 4) = 15}, datatype = anything, storage = rectangular, order = Fortran_order)

order4 := Array(1..4, 1..4, {(1, 1) = 8, (1, 2) = 11, (1, 3) = 14, (1, 4) = 1, (2, 1) = 13, (2, 2) = 2, (2, 3) = 7, (2, 4) = 12, (3, 1) = 3, (3, 2) = 16, (3, 3) = 9, (3, 4) = 6, (4, 1) = 10, (4, 2) = 5, (4, 3) = 4, (4, 4) = 15})

(1)

``


Download magicsquare4.mw

R dJ(t)/dt+J(t)/C=f(t)

where f(t) is a driving electromotive force. Use the fourier transform to analyze this equation as follows.

 

 

Find the transfer function G(alpha)  then find g(t) .

 Thanks ....

 

Dear all

 

Please I need your help to simplify by the coefficient a in this Matrix

I have The matrix A defined by  A:=Matrix(2,2, [[a,a],[3*a,4*a]]);

I want with maple transform A to  A:=a*Matrix(2,2, [[1,1],[3,4]]);

Thanks for your Help.

 

Dear all;

Please Have some one an idea to transform or convert 2nd order ODE to system of First ODE ( of course using maple).

Thanks

 

Please advise as to the proper coding entries needed in the triple integration palette  to transform from the Cartesian placeholders x;y;z to spherical coordinates rho; theta; phi so that the triple integration palette can be used in spherical coordinmates. Dr. Lopez alreadyb has a standalone template which does this but I would like to set a palette option for spherical  calculations.

 

Thanx

Hello, I am trying to do a fourier transfrom using the package < DiscreteTransfroms >.

The function is an gaussian function for now,

Here is the code I tried

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

restart

with(DiscreteTransform):

> X := Vector(1000, proc (k) options operator, arrow; (1/200)*k-5/2 end proc);
> Y := Vector(1000, proc (k) options operator, arrow; evalf(exp(-10*((1/100)*k-5)^2)) end proc);

> X2, Y2 := FourierTransform(X, Y);
Vector[column](%id = 18446744080244879358),

Vector[column](%id = 18446744080244879478)
> plot(X2, Re(Y2));

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

The program returns two vector, X2 and Y2 who are supposed to be the fourier transforme of a gaussian so.. a gausian but when I plot the result X2 on the horizontal and Y2 on vertical, the graph doesn't resemble a gaussian function or any function at all.

 

Please help!!

Alex

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