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here a comlicated formula,how i simplify

thanks  a lot.


f := (kappa*omega^2+omega^3)*(Y+(-sqrt(N)*omega^(3/2)*sin(theta[2])*cos(varphi[2])*lambda__b+sqrt(N)*omega^(3/2)*sin(theta[1])*cos(varphi[1])*lambda__a)/(2*(kappa*omega^2+omega^3)))^2/(2*omega)+(-kappa*omega^2+omega^3)*(X+(sqrt(N)*omega^(3/2)*sin(theta[2])*cos(varphi[2])*lambda__b+sqrt(N)*omega^(3/2)*sin(theta[1])*cos(varphi[1])*lambda__a)/(2*(-kappa*omega^2+omega^3)))^2/(2*omega)+(Omega*N*cos(theta[2])*omega+Omega*N*cos(theta[1])*omega-P__X^2*kappa+P__X^2*omega+P__Y^2*kappa+P__Y^2*omega)/(2*omega)-(sqrt(N)*omega^(3/2)*sin(theta[2])*cos(varphi[2])*lambda__b+sqrt(N)*omega^(3/2)*sin(theta[1])*cos(varphi[1])*lambda__a)^2/(8*omega*(-kappa*omega^2+omega^3))-(-sqrt(N)*omega^(3/2)*sin(theta[2])*cos(varphi[2])*lambda__b+sqrt(N)*omega^(3/2)*sin(theta[1])*cos(varphi[1])*lambda__a)^2/(8*omega*(kappa*omega^2+omega^3))







    f is a complicated function,i want to make it more simplify,but i want to keep square style,

 let coefficients of X and Y keep one unit,and simplify terms  containd special symbol of omega



it what i wanted.

I want to reduce all solution of the equation sin(x)^2=1/4

sol:=solve(sin(x)^2=1/4, x, AllSolutions);


sol:=solve(k=1/4, x, AllSolutions = true, explicit);

How can I reduce solution sol := -1/3*Pi*_B3+1/6*Pi+Pi*_Z3 ?

How can I get x= pi/6+k*pi and x= -pi/6+k*pi?

Hi guys.

I want to know how can I make the maple to give final response of a simple trigonometric function, e.g sin(pi/6). When I type sin(pi/6) in the command line and then press enter, maple give the same, I mean sin(pi/6) at the next line. I want 0.5 as the final response not sin(pi/6) again. Simplify command does not work for me in this case.

Thanks in advance.

When I do simplify(LegendreP(n, 1, cos(t))), Maple gives me -sqrt(1-cos(t))*sqrt(cos(t)+1). Isn't it the same thing as -sin(t)? How can I have Maple further convert/simplify it to -sin(t)? (I tried simplify(%, trig) but it didn't work). I am new on Maple. Thanks in advance for anyone's help!


I'm looking at Maple as a possible alternative to Mathcad (which I've been using for years, but is now very jaded compared to other options like Maple and Mathematica).  I'm a civil engineer and for what I do, one of the better features of Mathcad is the way it handles units.  For example, if I specify an angle in degrees (say phi=30 degrees) and then ask for sin(phi), I get 0.5.  At face value, I though Maple would do the same kind of thing.  However, this doesn't appear to be the case (see attached worksheet).  The only workaround that I can see is to specify the angle in degrees (but without assigning ) and then multiply the specified value by pi/180 (to convert to radians) before passing it to the sin function.  Which is all a bit messy and not at all an attractive solution.

Am I misunderstanding the way units work in Maple and is there a clean way of specifying angles in degrees (which is what engineers work with) and using these values directy in trig functions?

Thanks in anticipation,


  Solving trigonometry Equations  sin^2(2x)-cos^2(8x)=0.5cos(10x)

There are two ways of expressing the solution to a cubic equation, one of them uses cos and arccos [1]. How do I / is there a way to ask Maple to get this form?

More generally, can Maple be instructucted to solve equations using trig identities?


How to solve the equation
2^(sin(x)^4-cos(x)^2)-2^(cos(x)^4-sin(x)^2) = cos(2*x)
symbolically? The solve command produces a weird answer. Evalfing all its values, one sees
0.7853981634, -0.7853981634, 2.356194490, -2.356194490,

1.570796327 - 1.031718534 I, -1.570796327 + 1.031718534 I,

1.570796327 + 1.031718534 I, -1.570796327 - 1.031718534 I,

0.7853981634, -0.7853981634, 2.356194490, -2.356194490,

1.570796327 - 1.031718534 I, -1.570796327 + 1.031718534 I,

1.570796327 + 1.031718534 I, -1.570796327 - 1.031718534 I

The identify command
interprets the real solutions on -Pi..Pi as -3*Pi/4, -Pi/4, Pi/4, 3*Pi/4
(for example,

3*Pi/4 ).
Is it possible to obtain these with Maple in a simpler way?

PS. Mathematica 10 does the job.

PPS. So does even Mathematica 7.

Is it possible to find all the solutions of the equation

abs(tan(x)*tan(2*x)*tan(3*x))+abs(tan(x)+tan(2*x)) = tan(3*x)

which belong to the interval 0..Pi with Maple?



eq2 :=

These equations are the same. yet simplify(eq1-eq2,trig);
The Mathematica COMMAND FullSimplify[..] gets zero.

How to calculate mul(sqrt(3)+tan((1/180)*Pi*j), j = 1 .. 29) exactly?
The command
simplify(mul(sqrt(3)+tan((1/180)*Pi*j), j = 1 .. 29), trig)
is spinning.

A reddit user posted an interesting question:

The problem is how to simplify, e.g. 2/3*37^(1/2)*sin(1/6*Pi+1/3*arccos(55/1369*37^(1/2)))+2/3 to 4.  I tried a few things and got nowhere.  Any suggestions?


with great interest and surprise I read the post
"Converting Half-Angle Trig Formulas to Radicals".
Isnt it possible to evaluate cos(arccos(13/14)/3) also
to an exact expression in radicals ?
I simply do not succeed with my humble knowledge of
the Maple commands/internal workings...
Would be great if someone finds a solution ( of an 
unsolvable problem ??? ).

[Edit: Excess white space deleted.---Carl Love]


I have a trigonometric series which contains 1D and 2D modes. It looks something like the following:

S:= Acos(mx)sin(nz) + Bcos(kz)sin(qx) + Csin(sz) for m,n,k,q,s=1,.....10.

I am iterested in obtaining the amplitudes of the 1D modes (i.e. C in the above expression). Is there a way to do this using the coeffs function? I would like to use this in such a way as to isolate the 1D modes from th series. Any suggestions?


Thanks for your help.

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