I want to take two numbers, for example 37665432 and 59374696 (later extrapolate to 3 or 4 etc... sets of numbers) and take each individual number alternately and put them into a list. 

Here's what I have

a:=37665432;

b:=59374696;

c:=convert(a,base,10);

d:=convert(b,base,10);

e:=ListTools:-Reverse(c);

f:=ListTools:-Reverse(d);

So now I have the numbers all in a list and I want to select each one alternately into another list.

g:=seq(e[i],f[i],i=1..8); 

I am going to simplify the following formula:

sqrt(a^2*p*(1-p)*(N-n)/(n^2*(N-1)))

I wrote simplify(sqrt(a^2*p*(1-p)*(N-n)/(n^2*(N-1))),symbolic), the output was:

Hi,

I have a series solution to a differential equation. The recurrence relation is such that knowing the first four coefficients is sufficient to determine all the other coefficients. Now I want to represent this solution in terms of f(x)*c0+g(x)*c1+h(x)*c2+k(x)*c3 where f,g,h,k are all polynomials in x. I tried searching for commands related to simplify, but I was unable to solve my problem. 

p.s : i am not aware if this has already been discussed so please bear with me

Hello,

I am having trouble with posing an integration for the following function, wrt z.

u:= sin (theta)  * ((s^2 + z^2)/2 +h*z)

I want to be able to change the values of h, s, and theta.

I would like to integrate u, wrt z, from s to h.

I have tried the basics, such as....

int(u, z)   and

int(u, z=s..h)

I get the integrand symbol and a general setup but I am not posing it clearly enough to get Maple to perform the integration.

Thanks for any help you can offer.

Based on some older Math group thread my problem is the following (0 < t):

F:= (x,t) -> Int(exp(-t*eta^2+x*eta)/(1+exp(eta)),eta = -infinity .. infinity);

satisfies 0 = 'diff(F(x,t),t) + diff(F(x,t),x$2)' and for that PDE Maple gives

  pdsolve(PDE, f(x,t),build): combine(%):
  subs(_c[1]=c,_C1=c1,_C2=c2,_C3=c3,%): rhs(%);
  S:=unapply(%, x,t);

    S := (x, t) -> c3*c1*exp(c^(1/2)*x-c*t)+c3*c2*exp(-c^(1/2)*x-c*t)

by separation of variables.

I am interested in t=1/2 ( to get (F(x,1/2) ) and for that define

I have a procedure that I use frequently. I tried to include this procedure in other Maple sessions so that I can reuse that procudure. I tried the command $include but received the following error message:

$include "c:/myworks/myplot.wm"

Error, unexpected string
 

where myplot.wm is a file that contains a procedure which I want use repeatedly.  What is wrong there?

Thanks.

assume(u::real)

assume(v>0)

assume(lambda>0)

Im( u+i v / u+i v+lambda )   is ok.

Im( (u+i v / u+i v+lambda)^2 )   is ok.

Im( (u+i v / u+i v+lambda)^3 )   is ok.

Im( (u+i v / u+i v+lambda)^4 )   is not ok.

Maple gives back the input.  

What is the problem with my input?

Sandor

Hi,

I need some help.  I have a system of ODE's subject to a system of Boundary Conditions.  I can't figure out the sequence of commands to get MAPLE to generate a solution.

ODE System:

SYS1 := {diff((C[10])(z), `$`(z, 2)) = (BR[1]+BR[2])*(C[10])(z)-BR[3]-(BR[4]+BR[5])*C[50], diff((C[51])(z), `$`(z, 2)) = Ped*u[0]*C[50*x]-BR[5]*(C[10])(z)+BR[3]*C[50]}

Boundary Conditions:  I am going to be evaluating from z=s to z=h

BC1 := {(C[10])(h) = 1, diff((C[10])(s), s) = 0, diff((C[51])(h), h) = 0, diff((C[51])(s), s) = Da[1]*(C[50]-J3)}

I write a lot of maple code that my advisor uses, and I'm wanting to make it easier for him to use with as little extra work on my side as possible. Most recently I've started using modules to hold the procedures that go together. For example, I may have something like this

Resultants := module()
  description "This uses various methods to find resultants.":
  export UResultant, MacaulayResultant:

  MacaulayResultant := proc(F,vars)
    -- description and code
  end proc:

I am running the student version of maple, the one for hundred, and my final question is wondering if we could solve second order de as in a spring mass system.

The problem reads,  a mass weighing 32 lb stretches a spring 2 ft. The mass is initially relesed from a point 1 foot above equilibrium position with an upward velocity of 2 ft/s

I would like to simplify (automatically...) a sum containing constant terms, as in the trivial one:

Sum((A*x[i]+B)^2, i = 1 .. n) = A^2*(sum(x[i]^2, i = 1 .. n))+2*A*B*(sum(x[i], i = 1 .. n))+n*B^2

I can reach this result easily enough by:

- Using the "student" package

- Then expressing the sum underits inert form (Sum(...))

- Expanding it

- Taking its value.

Now the "student" package is "deprecated".... How can I do this without it?

I get to the point  error (in dsolve), required an indication of the dependent variables in the given system. i do not know what this means..

What i did is type in y''+4y'+5y=0

than i entered the initial conditions y(pi/2)=1/2 and y'(pi/2)=-2

than i dsolved 1 and 2 and recieved that error, what am i doing wrong, i am brand new to maple and would almost rather do it by hand

1. y''+4y'+5y=0  IV= y(pi/2)=1/2 and y'(pi/2)=-2  I can get to the dsolve and than I run into errors.

2.y''+2ty'+3y=0,  t=0 is an ordinary point of the equation and how is it possible to find a power series solution?

3. Is it possible to solve a problem like this is maple?

A mass weighing 32lbs stretches a spring 2 ft, the mass is initially relesed from a point 1 foot above equilibrium position with an upward velocity of 2ft/s/

 A. Find amplitude and period of motion

I'm considering buying Maple but I need to know something...

Does the functionality Maple provides (like the equation editor) allow for writing out math as quickly and effeciently as doing it on paper? I ask because I have a rather unique disability that has left me without the ability to write, making it difficult to learn math. I'd like to find software that will allow me to write math on the PC like you might see on paper.

let me show a little problem i've found in physics package (if it really is the problem in package), and especially in Bra, Ket, and in product operators

first

lets calculate a product of a projector and a Ket:

sum(Ket(Psi,s).Bra(Psi,s),s=-n..n).Ket(Psi,1)

in this case the result would be obviosly Ket(Psi,1) and it's true.

Let's modify it now:

sum(Ket(Psi,s+1).Bra(Psi,s),s=-n..n).Ket(Psi,1)