Konstantin@

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16 years, 290 days
Kharkov
PhD in Numerical Optimization.

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These are questions asked by Konstantin@

Dear friends!

My question does not concern essential functioning of Maple and does not influence on any computation performance. But I ask you to pay attantion to it.

For a long time ago I noticed, that representation of some elements of Maple worksheets does not correspond to settings. For example, I would like to have 2D Ouput style in bold font, which I used in Classic interface in the years of my youth. I adjusted this style as needed:

0

1

Nevertheless, output font has a normal (no-bold) style:

1

Is it possible to fix the problem?

I solve numerically very simple boundary value problem for the following ordinary diff. equation:

-1.2*y''(t)+0.8*y(t)=2,

y(0)=1, y(1)=0.

So := dsolve([-1.2*diff(y(x), x$2)+0.8*y(x) = 2, y(0)=1, y(1)=0], y(x), 'numeric', 'output' = listprocedure);

Solution looks as needed

u := unapply(rhs(So[2])(x), x): plot(u(t), t=0 .. 1);
pic

and can be numerically integrated in usual way:

evalf(int(u(t), t = 0..1));

0.6041717543123311

But integral of u^2(t)  (evalf(int(u(t)^2, t = 0..1))) returns:

pic1

How to avoid this issue?

Cannot calculate derivative (gradient) of a procedure returned by dsolve.

Say, I solve the equation:

S1 := dsolve([diff(y(x), x$2)-1.0325*diff(y(x), x)+1.36*y(x)=sin(2*x), y(0)=0, y(1)=1], numeric, y(x), 'output' = listprocedure);

Its solution easily can be retrieved and looks fine:

H:=rhs(S1[2]); 

plot(H(t), t = 0..1, thickness = 4);

3

But when I try to calculate the gradient of H, I receive the error:

H1 := codegen[GRADIENT](H);

Error, (in intrep/statement) unable to translate Array(1..4, {(1) = proc (outpoint) local X, Y, YP, yout, errproc, L, V, i; option `Copyright (c) 2000 by Waterloo Maple Inc. All rights reserved.`; X := Vector(8, {(1) = .0, (2) = .14817993189456188, (3) = .31785812820433257, (4) = .47163479035679234, (5) = .6130306894371967, (6) = .7460958115245858, (7) = .8741894219027533, (8) = 1.0}, datatype = float[8], order = C_order); Y := Matrix(8, 2, {(1, 1) = .0, (1, 2) = .47692145669848085, (2, 1) = 0.7710429970702501e-1, (2, 2) = .5707930170882397, (3, 1) = .1866916935738028, (3, 2) = .7299040171277492, (4, 1) = .3128649714509215, (4, 2) = .9171936...

Gradient of procedures defined by  ":= proc()" is calculated properly.

I experienced strange operation of "union" for sets of vectors.

Mt1:=Matrix(2, 4, [[ 0,1, 0, 0], [ 0,  0,  1, 1]]); Ms := Vector[column](4, [8,4,2,1]); St1 := {}:

St1:= `union`(St1, {Mt1 . Ms});

I am surprised, because each execution of union adds new and the same vector <4 | 3> to set St1:

1

But after copying any set in the clipboard and pasting the set St1 has only one instance of vector <4 | 3>:

2

What does it mean?

Dear friends,

Recently I was surprised when discovered the following error in using the function solve. If I run the simlest example from the help system for the first time (or after restarting), the following error occurs:

If I run this example repeatedly, this brings the following:

1

Previously in earlier versions I used solve many times for very complex computations and have never seen something similar.

Any suggestions are welcomed.

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