## 202 Reputation

15 years, 295 days

## Thanks...

With your help, I could solve my problem.

Thank you very much.

Try this:

Good Luck

Try this

Good Luck

Try this.

Good Luck.

Good Luck.

## solve...

Try using solve.

solve(equation,var);

good luck.

## yes, that´s the...

First, you define the function F(t):

>F:=t->200*sqrt(t):

Now, you can find the rate of change when t=1:

>D(F)(1);

## D...

F:=t->200*sqrt(t)

D(F)(1);

## PLOT(POINTS(...

i don´t know why you get that message.

Try this:

restart:
with(plots):
f:=n->sum(sum((-1)^(k-j)*binomial(k,j)*j^(n), k=1..n ), j=1..k):
PLOT(POINTS(seq([n,f(n)],n=4..10)));

Good Luck

## pointplot...

with(plots):
f:=n->sum(sum((-1)^(k-j)*binomial(k,j)*j^(n), k=1..n ), j=1..k):
pointplot([seq([n,f(n)],n=4..10)], axes = normal,thickness=5,color=blue);

Good Luck

## Plot and Display...

with(plots):
triangle1:=plot([[0,0],[2,0],[0,2],[0,0]],color=blue,thickness=2,scaling=constrained,axes=framed):
triangle2:=plot([[0,0],[-2,0],[0,-2],[0,0]],color=red,thickness=2,scaling=constrained,axes=framed):
line:=plot(-x,x=-2..2,color=green,thickness=2,axes=framed):
display(triangle1,triangle2,line);

Good Luck.

## Sintaxis...

> f:=x->(-exp(-1)-x*exp(x))/(x*exp(x)*(x+1));
> limit(f(x),x=-1);

## Piecewise...

f:=(x,y)->piecewise(x<>0 or y<>0,x*y /(x^2+y^2),x=0 and y=0,0):

good luck.

## View...

You could use the View Option.

Good Luck

## solve...

> restart:
> P:=x->a*x^3+b*x^2+c*x+d:
> ec:=P(X[0])=e,D(P)(X[0])=f,P(X[1])=g,D(P)(X[1])=h:
> solve([ec],[a,b,c,d]);
> assign(%):
> solve(P(x)=0,x);

Good Luck.

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