given differntial equation with boundary conditions.
{f'(x)}^2 - f(x)f''(x) = f'''(x) - 100 * f'(x) - 0.001 * [2 * f'(x) * f'''(x) - f(x) * f''''(x) - {f''(x)}^2] = 0
boundary conditions:
f(0)=0, f''(0)=0, f'(1)=1, f(1)=0
how i will calculate this?
tanx
