You get the original list mod 33. If you add 99 (which is 0 mod 33), you get the original list. But that might be different in other examples, including letters a, b, and spaces.

Alec

Check Sage.

Alec

If there was a voting, I would vote for 25 (the default value). There is no much of a difference between that and 20 (which also seems like a good choice), but that would be consistent with the command-line setting.

Alec

If there was a voting, I would vote for 25 (the default value). There is no much of a difference between that and 20 (which also seems like a good choice), but that would be consistent with the command-line setting.

Alec

Now, I don't want to rush or anything, but March (and the 1st quarter) ended last week...

Alec

Originally u had 2 terms and length 17.

1. After the 1st step - 8 terms and length 131;
2. After the 2nd step - 105 terms and length 3390;
3. After the 3rd step - 3360 terms and length 273198.

With such a rate, the number of terms and the length after the 10th step will be astronomical (or, as Richard Feynman called such numbers, financial :)

Alec

Originally u had 2 terms and length 17.

1. After the 1st step - 8 terms and length 131;
2. After the 2nd step - 105 terms and length 3390;
3. After the 3rd step - 3360 terms and length 273198.

With such a rate, the number of terms and the length after the 10th step will be astronomical (or, as Richard Feynman called such numbers, financial :)

Alec

That's a nice idea! And it works.

Alec

That's a nice idea! And it works.

Alec

That depends on what you mean by a spreadsheet. If it's in a file, it can be imported to Maple as a Matrix. After that, X and Y can be defined as the rows or columns of that matrix and entered in the ScatterPlot command by their names, X and Y.

If you had an example, someone would show how to do that in that example. Without an example, it's not easy to understand the problem you are having.

If you meant the Maple's spreadsheet, it can't have more than 100 rows, and assuming that 100 rows in columns A and B of the spreadsheet named s are filled with data, the Matrix can be extracted as

Spread:-SetSelection(s,1,1,100,2);
M:=Spread:-GetValuesMatrix(s);
X:=M[..,1];
Y:=M[..,2];

Alec

That depends on what you mean by a spreadsheet. If it's in a file, it can be imported to Maple as a Matrix. After that, X and Y can be defined as the rows or columns of that matrix and entered in the ScatterPlot command by their names, X and Y.

If you had an example, someone would show how to do that in that example. Without an example, it's not easy to understand the problem you are having.

If you meant the Maple's spreadsheet, it can't have more than 100 rows, and assuming that 100 rows in columns A and B of the spreadsheet named s are filled with data, the Matrix can be extracted as

Spread:-SetSelection(s,1,1,100,2);
M:=Spread:-GetValuesMatrix(s);
X:=M[..,1];
Y:=M[..,2];

Alec

For Windows, AutoHotkey would do the trick.

Alec

Q.1. It is easier to convert a string,

convert("abc",bytes);

                             [97, 98, 99]

A list of characters can be converted using the following procedure,

f:=L->map(op@convert,L,bytes):

Another solution:

f:=curry(map,StringTools:-Ord);

For example,

L:=["a","b","c"]:
f(L);

                             [97, 98, 99]

Q.2.i)

F:=(a,b,L)->map(x->x&^b mod a,L):

Q2. ii)

L:=[$0..32];

  L := [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17,

        18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32]

L1:=F(33,3,L);

  L1 := [0, 1, 8, 27, 31, 26, 18, 13, 17, 3, 10, 11, 12, 19, 5, 9, 4,

        29, 24, 28, 14, 21, 22, 23, 30, 16, 20, 15, 7, 2, 6, 25, 32]

F(33,3,L1);

  [0, 1, 17, 15, 25, 20, 24, 19, 29, 27, 10, 11, 12, 28, 26, 3, 31, 2,

        30, 7, 5, 21, 22, 23, 6, 4, 14, 9, 13, 8, 18, 16, 32]

Nope. On the other hand,

F(33,7,L1);

  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18,

        19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32]

That matches the original list.

Alec

Q.1. It is easier to convert a string,

convert("abc",bytes);

                             [97, 98, 99]

A list of characters can be converted using the following procedure,

f:=L->map(op@convert,L,bytes):

Another solution:

f:=curry(map,StringTools:-Ord);

For example,

L:=["a","b","c"]:
f(L);

                             [97, 98, 99]

Q.2.i)

F:=(a,b,L)->map(x->x&^b mod a,L):

Q2. ii)

L:=[$0..32];

  L := [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17,

        18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32]

L1:=F(33,3,L);

  L1 := [0, 1, 8, 27, 31, 26, 18, 13, 17, 3, 10, 11, 12, 19, 5, 9, 4,

        29, 24, 28, 14, 21, 22, 23, 30, 16, 20, 15, 7, 2, 6, 25, 32]

F(33,3,L1);

  [0, 1, 17, 15, 25, 20, 24, 19, 29, 27, 10, 11, 12, 28, 26, 3, 31, 2,

        30, 7, 5, 21, 22, 23, 6, 4, 14, 9, 13, 8, 18, 16, 32]

Nope. On the other hand,

F(33,7,L1);

  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18,

        19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32]

That matches the original list.

Alec

close(filename);
readbytes(filename,18);

  [70, 105, 108, 101, 84, 111, 111, 108, 115, 32, 101, 120, 97, 109,

        112, 108, 101, 13]

Alec