@666 basha 

I said to replace mul with (`*`@op), but you have just replaced it with op. Just using op will remove all the cross-product terms from the model.

"Model is not of full rank" generally means that the data has insufficient variation in at least one of the input parameters. The input parameters in this case are  [S, Ha, Rd, Ec, Nt, Nb]. The data is collected over the course of running the worksheet. Each plot varies at most 2 parameters. If you run all the plots in the worksheet as I presented it, there will be about 15,000 data points with sufficient variation for Fit to not give the warning. If you continue to have this problem, let me know.

@666 basha The one-argument forms of mul and add were added after Maple 18. To retrofit, replace mul with (`*`@op).

@666 basha The plot that you show is generated by procedure ParamPlot3d. Inside that procedure, a 2D version of the contour plot is created and assigned to local C. So, you just need to make the first line of the body of the procedure (i.e., after the local declarations) 

return C;

Why is there no Spam button on this? And there is no Delete option on the More pull-down.

I don't think that this is ever supposed to happen: I get different results from using `assuming` in infix operator form:

int(GAMMA(a,s)*exp(-b*x), s= 0..infinity) assuming b > 0, a > 0

This gives me the simple result that you were expecting. However, the functional form,

`assuming`([int(GAMMA(a, s)*exp(-b*s), s = 0 .. infinity)], [b > 0, a > 0])

returns unevaluated. I believe that assuming commands entered in 2D Input are always converted to the functional form before execution. Note that `assuming` is a Maple-language procedure on which you can run showstat, trace, etc. I've done that, but I can't figure out what's going on.

@tomleslie wrote:

• What you have is a simple substitutional code which converts a supplied integer to a text message. Pretty sure this has nothing to do with any RSA cryptosystem.

The steps for encrypting via RSA (and other cryptosystems based on modular arithmetic) are

1. Break the plaintext up into string chunks of a length such that when they're converted to numbers, the modular arithmetic will be injective (i.e., one-to-one).
2. Convert each chunk into an integer. Simply converting the bit pattern into a binary integer is sufficient.
3. Apply the mathematical part of the algorithm to those integers.
4. Output the new integers in a suitable format (possibly encoding as characters).

To decrypt, those steps are simply done in reverse (of course with some variation of the mathematical part). The OP's procedure is the second-to-last of those steps.

@dharr I'm saying that the same mechanism does work in a Code Edit Region.

@dharr Thanks, that's helpful. In a Code Edit Region, if you hover over the wavy line, a tooltip appears in a few seconds to say what the error is. But I almost always know what the problem is anyway.

@vv Yes, agreed, there's not much point in doing this for end-use in1D Input. But it's useful to program it in 1D for a 2D end user.

An unevaluated return allows a bit more finesse:

`⨂`:= (A,B)-> 
   `if`([A,B]::[rtable$2], LinearAlgebra:-KroneckerProduct(A,B), 'procname'(A,B))
:

@vv Since the symbol in question in ASCII is `⨂`, you might as well just do

`⨂`:= LinearAlgebra:-KroneckerProduct;

In other words, the OP's desired symbol is already a neutral operator.

@acer Thank you, that's useful information. I recall the Question and Answer to which you referred. I wouldn't have intentionally put a blank line at the top, nor was I aware of one being there unintentionally, but I understand how my typing and mousing could lead to a stray one getting there. Also, I didn't intentionally collapse the Region, but I can also see that accidentally happening. From my POV, I was working elsewhere in the worksheet, far enough down that the Region (which was fully expanded) was off-screen. When I scrolled back up, it was gone.

@Kitonum Certainly there are some nontrivial combinations of the parameters Pr, lambda, and s for which Maple can "do" the integral that dsolve returns. One that works is Pr= 1, lambda= 1, s= 1.

@student_md You forgot about making X a Vector. Do something like X:= tau-> Vector(n, i-> xi[i](tau)).

I think that using x for gamma is a bad and confusing choice! How about gamma__0 (the 0 could be anything else)?

I don't think that there's hope for a symbolic solution because of the summation in f. I don't think that there'll be any problem getting a numeric solution (except perhaps if M is singular for some parameter values).

Although it's not an error, in the f definition you should change (i,j)-> to i->. Maple syntax allows unused extra parameters, but clearly in this situation there's no reason, plus it's confusing to the reader.

This is totally not your fault---just an unfortunate aspect of the various languages in use here (English, Maple jargon, and Maple code)---that you cause confusion both for yourself and others by using the word "table". There is perhaps no other word that's commonly used in all three of those languages that has as many different meanings.

Rather than listing the numerous possible meanings, perhaps it'd be easier if I asked you to simply define precisely what you mean by "table". And perhaps it'd be even better if you said precisely what you intend to do with a "table" once I show you how to obtain one from your graph.

@Rohith The following two situations are completely different, and require totally separate treatment:

1. The function appears as a factor of the denominator, e.g., ln(x)/(a*sin(x))^2
2. The function appears as a term of the denominator, e.g., 1/(a+2*sin(a)^2)

So, which of these is your situation?