I didn't notice that, but that still doesn't matter. As I showed, the only way this works is if the units of L and C match, and they don't.

Doug is a strange contraction of Georgios 8-).

Doug is a strange contraction of Georgios 8-).

As you have shown, [almost] any tangent line to the graph of f satisfies

  {(x,y)| y = f'(p)*(x-p) + f(p)},

You know that the point (x2,y2) lies on that line.  That is, (x2,y2) satisfies the tangent line equation.  From that you should be able to solve for p.

As you have shown, [almost] any tangent line to the graph of f satisfies

  {(x,y)| y = f'(p)*(x-p) + f(p)},

You know that the point (x2,y2) lies on that line.  That is, (x2,y2) satisfies the tangent line equation.  From that you should be able to solve for p.

Of course, for that particular expression one can either use fsolve on its derivative, or, because the series rapidly converges, just truncate and pass to Maximize:

Optimization:-Maximize(subs(infinity=100,g),x=0..2);
                           [0.397154744381517599, [x = 0.915476564653636027]]

The max value extracted from the plot agrees to 5 decimal places.

Of course, for that particular expression one can either use fsolve on its derivative, or, because the series rapidly converges, just truncate and pass to Maximize:

Optimization:-Maximize(subs(infinity=100,g),x=0..2);
                           [0.397154744381517599, [x = 0.915476564653636027]]

The max value extracted from the plot agrees to 5 decimal places.

You are correct.  My purpose was to demonstrate the possiblity of such an extension, not to suggest that the example was anything other than a toy.  Extending convert, via convert/floor, seems to make more sense.  At least it would be benign.

That fails when the number of elements is odd.

That fails when the number of elements is odd.

You can extend simplify.  Here is a simple approach, it won't handle the second case:

restart;
`simplify/ceil` := proc(ex)
    evalindets(ex, 'specfunc(anything,ceil)', x -> -floor(-op(x)));
end proc:

simplify(floor(-x) + ceil(1+x));
                                                     1

Using lists seems reasonable.  I'd avoid the strings, though, by using convert/base:

use ListTools in map(Reverse,Reverse([LengthSplit](convert(12300678,base,10),3))) end use;

Using lists seems reasonable.  I'd avoid the strings, though, by using convert/base:

use ListTools in map(Reverse,Reverse([LengthSplit](convert(12300678,base,10),3))) end use;

You are also given a point, say (x2, y2), that is not on the graph but lies on the tangent.  So what is an equation that relates it to what you know?

You are also given a point, say (x2, y2), that is not on the graph but lies on the tangent.  So what is an equation that relates it to what you know?