@pvrbik I always use 1d-input (also known as Maple Input), so that is why.

I tried doing the whole thing with 2d-input and the result was that the input in the tex-file looked like this:

\begin{mapleinput}
\mapleinline{active}{2d}{for i to 10 do f := proc (x) options operator, arrow; x^2 end proc; f(x) end do; 1}{\[\]}
\end{mapleinput}

but nothing of that turned up in the dvi-file, only the 10 results.

@pvrbik I always use 1d-input (also known as Maple Input), so that is why.

I tried doing the whole thing with 2d-input and the result was that the input in the tex-file looked like this:

\begin{mapleinput}
\mapleinline{active}{2d}{for i to 10 do f := proc (x) options operator, arrow; x^2 end proc; f(x) end do; 1}{\[\]}
\end{mapleinput}

but nothing of that turned up in the dvi-file, only the 10 results.

test.pdf

@pvrbik 

No images. See the file test.pdf which I produced from your Maple code. It should be attached.

test.pdf

@pvrbik 

No images. See the file test.pdf which I produced from your Maple code. It should be attached.

@pvrbik Well, I'm using Windows.

My latex is handled by Scientific Workplace. It produced a dvi-file, which I printed to file (postscript).

The postscript file I converted to pdf using gsview/ghostscript.

The result looked nice.

Of course you can export to pdf directly from Maple, but that is not what you want, I guess.

@pvrbik Well, I'm using Windows.

My latex is handled by Scientific Workplace. It produced a dvi-file, which I printed to file (postscript).

The postscript file I converted to pdf using gsview/ghostscript.

The result looked nice.

Of course you can export to pdf directly from Maple, but that is not what you want, I guess.

Same thing happens with plot3d.

Maybe animate is finding a coordinate system in which all frames can be displayed?

It would be quite annoying if the following animation changed the view between frames.

animate(plot,[sin(x),x=-a..a],a=1..10);

which it doesn't.

In range = a..b the length of the real interval [a, b] is b-a. The code could be written from that point of view (not unreasonable).

In your example the matrix has integral values (1,2,3,4), so b-a would result in 3.

In range = a..b the length of the real interval [a, b] is b-a. The code could be written from that point of view (not unreasonable).

In your example the matrix has integral values (1,2,3,4), so b-a would result in 3.

@hirnyk 

Yes, the two sides have simple poles at 2 with the same residues. But so what?

series(lhs(eq),x=2);
                       1        (-1)   1
                       - (x - 2)     + -
                       2               2
series(rhs(eq),x=2,2);
           1        (-1)   3   1           /       2\
           - (x - 2)     + - + -- x - 2 + O\(x - 2) /
           2               8   32                    

@hirnyk 

Yes, the two sides have simple poles at 2 with the same residues. But so what?

series(lhs(eq),x=2);
                       1        (-1)   1
                       - (x - 2)     + -
                       2               2
series(rhs(eq),x=2,2);
           1        (-1)   3   1           /       2\
           - (x - 2)     + - + -- x - 2 + O\(x - 2) /
           2               8   32                    

A plot in the complex plane (R^2) could then be done by

plots[odeplot](Sol, [x(t),y(t)],t=0..4);

A plot in the complex plane (R^2) could then be done by

plots[odeplot](Sol, [x(t),y(t)],t=0..4);

@Doug Meade 

Please take a look at my last suggestion. It is identical to the one you are proposing.

@Doug Meade 

Please take a look at my last suggestion. It is identical to the one you are proposing.