Thank you to everyone for the solutions.

Thankfully this is for a numerical analysis project so now that I have made my substitution I can comment on the errors made by that substituion; the course is all about looking at approximate solutions anyway so I don't forsee any issues arrising with that. The course isn't a maple based course so we're not expected to have an in-depth knowledge of Maple and it's workings, so I think ths work around will suit me fine, though I am really greatfull for everyone's help.

My new equation was a series expansion which beyond the second term will have 1/e^(large number*x)^(increasing power) for each term. So whenever x>1 these terms are pretty much negligible, certainly by the time you reach x=17, which i decided to use the new equation from.

Doug that is extremely helpfull, thank you very much. I think i'm just going to plot the function from 0..2 and then use the function z(x) = 2000 -60.x -1.05 thereafter, as the difference between them is very small.

Sorry, that should read "z0 is an initial value of 2000 at x=0"