Problem: Write the equation internal bisector and external bisector of a triangle ABC with A(1,2,-7), B(3,-1,-1), C(-5,14,-3). This is my code.
restart;
> with(LinearAlgebra):
> A:=: B:=: C:=: M:=:
>v:=1/Norm(A-B,2)*(A - B) + 1/Norm(A-C,2)*(A - C): M=A + v*t;
>u:= 1/Norm(A-B,2)*(A - B) - 1/Norm(A-C,2)*(A - C): M=A + u*t;
in the commands M = A + v*t and M = A + u*t, please comment for me. Thank you.
