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how to convert GeneralLinearGroup and GeneralOrthogonalGroup to permutation group for small parameters 


GL23 := GeneralLinearGroup(2, 3);


i use generators , is it correct to find permutation group?

but there is a comma,

[((1, 2)(3, 5))(4, 7), (1, 3, 6)(2, 4, 8)]

does it mean that it has two different solutions?

if not, it is only one solution, 

does it mean that permutation matrix is 

permutationmatrix of  ((1, 2)(3, 5))(4, 7) + (matrix plus) permutation matrix of  (1, 3, 6)(2, 4, 8) ?

Dear All

I have 3D plot


y := 0; 1; z := 0





plot3d(abs((2*(-exp(-t-x-z)+exp(t+x+z)))/(exp(-t-x-z)+tanh((1+I)*t+(1/2-1/2*I)*y+z)+exp(t+x+z))), x = -5 .. 5, t = -5 .. 5)



How I can Improve this plot so that it look more aesthetic ?

Secondly, the resulotion of plot is not so good, and when I export this plot as jpeg file, quality of resolution deteriotate even more, I mean pixel tear out on zooming the image. How I fix this issue which I guess might be due to wrong way of exporting plot ?



i work on Maple 18 and recently maple standard worksheet interface not run properly.

i already have  uninstall and again i have same problems

Dear friends!

Please, suggest me, how to build a plot loocking as the following


where the values on the axis X (1, 5, 10, 50, ...) are categories, not numbers?

if i install maple 2015 in amazon cloud, activate with my license

and i do not use amazon after several trial, 

will the license be used and can not activate in future if i use amazon cloud again in future?

any command or configure needed when using large amount memory such as 100GB memory?

Hi there,
I have a simple task to do with arrays. I have an 8x3000 array, whose columns are sometimes all zeroes (if any element in the column is zero then the entire column is zero). I want to eliminate the zero vectors, so I have this loop (the array is A)

for i from 1 to 3000 do
    while A(1,i)=0 do
    end do;
end do:

Setting "A:=DeleteColumn(A,i);" reduces the size of the array, so if all the zero columns have been deleted at "i=200", Maple will keep trying to check the next column, which doesn't exist anymore. This gives an "index out of bounds" error, but also records "A" as the new smaller array, which is fine.

If I run this loop inside a procedure, the error stops the procedure, but it doesn't record the new array, it stays as the older, larger one. Does anyone know of a way around this?

Any help would be much appreciated.

Below and above the iterators, there is a graphic with numbers rotated in all directions.  I am thinking it is based somewhat on what I have done here

How did they get the rotations in Maple?



In functions such as fsolve, there is an optional parameter that allows one to specify the interval to perform the function on. Additionally, sometimes, if a solution is left out, one can specify an interval to search on to obtain the missing solution.

How does Maple determine the interval to search on if this is not specified?


(Additional Question - you don't have to answer this)

Ultimately, I am asking this question because I have a function for Newton's method; however, it requires an interval to run. I have read that fsolve uses Newton's method, so I am curious how to automatically select such an interval. Does anyone know how to implement such a thing?



Let, fixed an integer i and 1<=j<=2^{i}-1, for each x and y in [0,1] let the following mapping

Then, with the above procedure we can obtained, for a fixed i, all the mappings for j=1,...,2^{i}-1


However, How can I to evalute the "components" of the above procedure? For instance, I can not to compute CreaF(2)[1](0.35,0.465) (i.e., the first function in the "vector" CreaF(2), in x=0.35, y=0.465). 


Thanks very much for your time.


hi everyone..i would like to ask,why do we need to type in (101-100λ) in our maple program..why do we need the continuation..thanks in advance for answering..

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