plot part of the surface f(x,y)=10-x^2-3y^2:
plot3d(10-x^2-3y^2, x=-1 .. 4, y=1 .. 2, view=0 .. 11, axes= normal); (press enter)
Determine the normal vector and the equation of the tangent plane at the point (2,1,3) on the surface.
Display the surface , a black vector and the tangent plane, and give the equation for each of them
label the normal vector and the tangent plane, and give the equation for each of them
anyone can help me, please :(
I feel very confused :(