Rouben Rostamian

MaplePrimes Activity


These are questions asked by Rouben Rostamian

Given a list L of n^2 integers, I can fill an nxn matrix through Matrix(n,n,L).  for instance:
n := 4:
L := [$1..n^2]:
A := Matrix(n,n, L);

I don't know how to do this with a 0-based Array.  I wished that as in the case of the Matrix, the command
B := Array(0..n-1, 0..n-1, L);
would assign B[0,0]=1, B[0,1]=2, ..., B[3,3]=16, but it doesn't.

I know how to fill B's entries through doubly nested for-loops but I suspect that there might be a clever way of doing that. If so, then please show me how.

 

Searching for "typeset but do not execute" in MaplePrimes returns several hits.  The following looks primising:

acer - Replies
... Note that Maple doesn't do so much with this computationally, since it's interpreted
just as a ... But if the 2D Input is only used as typeset math without ...

 

Clicking on that link, however, leads to a page which has nothing to do with the searched item.  How does one navigate to the correct page?

I want to make sense of the expression

Int(t^2/ln(t)*exp(-t), t=0..infinity);

The denominator vanishes at t=1.  The singularity at t=1 is not integrable.  I want to see whether the integral is defined in the sense of Cauchy principal value.  Thus, I let

K := Int(t^2/ln(t)*exp(-t), t=0..1-a) + Int(t^2/ln(t)*exp(-t), t=1+a..infinity);

and wish to see whether the following limit exists:

limit(K, a=0, right);

Maple cannot evaluate this.  Nor can I.  Alternatively, we may try:

series(K, a=0);

or

series(K, a=0) assuming a>0, a<1;

In both cases Maple says that it is unable to compute the series.

So my question is: Does the Cauchy principal value exist, and can Maple help one to determine that?

 

I have the following equation

phi = -arctan(sin(2*theta)*(cos(beta)-1)/(cos(beta)*cos(2*theta)-cos(2*theta)-cos(beta)-1))+theta;

phi = -arctan(sin(2*theta)*(cos(beta)-1)/(cos(beta)*cos(2*theta)-cos(2*theta)-cos(beta)-1))+theta

 

In the denominator I wish to collect the two cos(2*theta) terms  into a single term, as in

(1-cos(beta))*cos(2*theta)

 

Is there a straighforward way of doing it?

 

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