MobiusPizza

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14 years, 158 days

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These are replies submitted by MobiusPizza

@pagan 

Thanks ever so much again.

I'll try the code later.

I've uploaded the following file to show what I am trying to do.

theoretical_BLA.mw

I am trying to obtain expressions for, referring to the above,

Ryu(-1) Ryu(0) Ryu(1) Ryu(2) by Maple automatically through taking into account the properties of E(x) and u(t). E and u are Expectation operator and u the data indexed by time integer t

where:

E(u(t-x)) = 1/N for all x    [1]

(u(t-x))^m = 1 for all even m, = u(t-x) for all odd m   [2]

u(t-a) * u(t-b) = -u(t-k) for a != b and k is unknown   [3]

therefore from [3]    E(u(t-a)*u(t-b)) = -E(u(t-k)) = -1/N for a!=b

Also   E(a*b*c*...*u(t-k))=a*b*c*...*E(u(t-k)) for all scalar constants a, b, ...etc

E(a+b)=E(a) + E(b) for all a and b

If Maple can recognise the above it should be able to derive Ryu(-1) Ryu(0) Ryu(1) Ryu(2)

Theoretical_BLA.docx

shows how I do it manually

@pagan 

Thanks ever so much again.

I'll try the code later.

I've uploaded the following file to show what I am trying to do.

theoretical_BLA.mw

I am trying to obtain expressions for, referring to the above,

Ryu(-1) Ryu(0) Ryu(1) Ryu(2) by Maple automatically through taking into account the properties of E(x) and u(t). E and u are Expectation operator and u the data indexed by time integer t

where:

E(u(t-x)) = 1/N for all x    [1]

(u(t-x))^m = 1 for all even m, = u(t-x) for all odd m   [2]

u(t-a) * u(t-b) = -u(t-k) for a != b and k is unknown   [3]

therefore from [3]    E(u(t-a)*u(t-b)) = -E(u(t-k)) = -1/N for a!=b

Also   E(a*b*c*...*u(t-k))=a*b*c*...*E(u(t-k)) for all scalar constants a, b, ...etc

E(a+b)=E(a) + E(b) for all a and b

If Maple can recognise the above it should be able to derive Ryu(-1) Ryu(0) Ryu(1) Ryu(2)

Theoretical_BLA.docx

shows how I do it manually

Thanks again pagan

Maple is driving me insane with the weird loopholes you have to go through to do seemingly simple stuff :/

I don't know how to program it so that it is 'linear' in the same time in proc manual programming.

Thanks again pagan

Maple is driving me insane with the weird loopholes you have to go through to do seemingly simple stuff :/

I don't know how to program it so that it is 'linear' in the same time in proc manual programming.

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