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Tamour_Zubair

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3 years, 163 days
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These are replies submitted by Tamour_Zubair

Scheme is Ok?...

Tamour_Zubair 80
May 08 2022
0 0

@tomleslie

Thanks a lot Professor for your kind response. Can we say that our scheme and coding is completely accurate? 

Accuracy Issue...

Tamour_Zubair 80
April 23 2022
0 0

@tomleslie 

Really thanks to you Professor. Its very helpful.

With you given ideas I devolped the code of rk-2, rk-3. But feel that there is no acccurcy difference between rk-2 and rk-4. I checked builton commands that rk-2 and rk-4 has same reults. Is that any issue in scheme? I am waiting for your kind response.

Thanks 

@rcorless  Sure Professor. Kindly...

Tamour_Zubair 80
April 21 2022
0 0

@rcorless 

Sure Professor.

Kindly share the link of that paper. I will explore it. I shall be very greatfull to you. Thanks

Facing issue in integration evaluations...

Tamour_Zubair 80
February 15 2022
0 0

@acer 

Professor i want to evaluate this

question11.mw

> 

restart
> 

``
> 

JJx11 := int(int(2.73299999999999999999999999999*10^(-22)*p*cos(.50*p+.50*q)/sqrt(p^2+q^2+7.46928900000000000000000000000*10^(-44)), p), q)

int(int(0.2733000000e-21*p*cos(.50*p+.50*q)/(p^2+q^2+0.7469289000e-43)^(1/2), p), q)

 (1)
> 

``

Download question11.mw

Facing issue in integration evaluations...

Tamour_Zubair 80
February 15 2022
0 0

@acer 

Professor we the simplest form of my question is given below. I need to find "AA22" in integration evaluated form at p=1 and q=1.

question.mw

> 

restart; printlevel := 4

{--> enter Terminate, args =

<-- exit Terminate (now at top level) = }
{--> enter ModuleUnload, args =
<-- exit ModuleUnload (now at top level) = }

  
> 

with(LinearAlgebra):
> 

``
> 

> 

ff11 := cos(1.0*k*(p+q)):
> 

NULL
> 

JJx11 := int(int(p*ff11/sqrt(p^2+q^2), p), q);

int(int(p*cos(.50*p+.50*q)/(p^2+q^2)^(1/2), p), q)

 (1)
> 

AA22 := eval(JJx11, [p = 1, q = 1])

eval(int(eval(int(p*cos(.50*p+.50*q)/(p^2+q^2)^(1/2), p), {p = 1}), q), {q = 1})

 (2)
   
 

``

Download question.mw

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